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Water Exercise Bangkok UNDP-ADAPT ASIA
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Estimating Irrigation Demand Agricultural study will collect data on net revenue and water use for irrigated farms Regress net revenue (NR) on water (W) and other control variables (X) NR=a0+a1W+a2W^2+BX Coefficients ai estimated by regression
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Calculate Marginal Value Water Differentiate NR equation with respect to W dNR/dW=a1+2a2W Expectation is that a1>0 and a2<0 dNR/dW is the net (of fee) marginal value of water to farmer If there is a fee F for water, the marginal value of water P=dNR/dW+F P is expected to decline as farmers get more water
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Demand for Water P W
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Value of Water Marginal value of water: – P= a1+a2W+F (with a2<0) Aggregate value (CS) of water is sum of marginal values from 0 to W It is the area underneath the demand function – CS=∫P dW – CS=a1W+(a2/2)W^2+FW
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CS for Water P W CS
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Allocating Water Suppose two farmers want to use the water in a watershed Supply of water is 100 and no fees Inverse demand by farmer 1 is: – P=36-0.4W1 Inverse demand by farmer 2 is: – P=50-0.2(W2)
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Calculate Aggregate Value of Water Calculate aggregate value of water to each farmer: – CS1=36W-0.2W^2 – CS2=50W-0.1 W^2
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Evaluate Farmer 1 Values Enter values for Farmer 1 water from 1 to 100 – Enter “1” in location A2 – Enter “=a1+1” in location A3 – Copy and paste formula in locations A4 to A101 Calculate CS of farmer 1 in location B2 – Enter “=36*a1- 0.2*(a2^2)” – Copy and paste formula in B3 to B101
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Evaluate Farmer 2 Values Enter values for Farmer 1 water from 1 to 100 – Enter “=100-A2” in location C2 – Copy and paste formula in locations C3 to C101 Calculate CS of farmer 2 in location D2 – Enter “=50*C2- 0.1*(C2^2)” – Copy and paste formula in D3 to D101
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Calculate Aggregate Value In Column E, sum values Enter in location E2 “=B2+D2 Copy and paste formula in E3 to E101 What allocation maximizes value of water?
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Allocation of Water P 0100 W 33.3 10 32 Farmer 2 Farmer 1 Supply
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Optimum Allocation Optimum maximizes sum of values across all users Equates marginal value of every user Equate P of farmer 1 to P of farmer 2 P=36-0.4W=50-0.2(100-W) W1=10 W2=100-10=90 P=32
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Climate Change Suppose climate change reduces supply of water from 100 to 70 (30% loss) What is new optimal allocation? Enter into location F2 “=70-A2” Copy and paste into F3 to F76 Enter into location G2 “=50*F2-0.2*(F2^2) Sum columns C and G into H2 to H76
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New Allocation Optimum allocation equates P given new supply P=36-0.4W=50-0.2(70-W) W=0 W2=75 P=36 Not same percentage reduction across both farmers
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Allocation of Water P 0100 W 33.3 10 32 Farmer 2 Farmer 1 Supply 70 CC
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Suboptimal Allocation Make both users have 30% reduction Farmer 1 goes from 10 to 7 Farmer 2 goes from 90 to 63 What is total value of this outcome?
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