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CHAPTER 1 Section 1.4 إعداد د. هيله العودان (وضعت باذن معدة العرض )

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Presentation on theme: "CHAPTER 1 Section 1.4 إعداد د. هيله العودان (وضعت باذن معدة العرض )"— Presentation transcript:

1 CHAPTER 1 Section 1.4 إعداد د. هيله العودان (وضعت باذن معدة العرض )

2 Example 3 Consider the matrices A = B=C= D= Here AB=AC= 010201021 11341134 25342534 370037000 34683468 H.A.O

3 Theorem 1.4.2. Assuming that sizes of the matrices are such that the indicated operations can be performed, the following rules of matrix arithmetic are valid. (a) A+ 0 = 0 +A=A (b) A-A= 0 (c) 0 -A=-A (d) A 0 = 0 ; 0 A= 0 H.A.O

4 IDENTITY MATRICES and so on. 10011001 10 0 01 0 0 0 1 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 H.A.O

5 Theorem 1.4.3. If R is the reduced row- echelon from of an n × n matrix A, then either R has a row of zeros or R is the identity matrix I n. H.A.O

6 Definition. If A is a square matrix, and if a matrix B of the same size can be found such that AB = BA = I, then A is said to be invertible and B is called an inverse of A. H.A.O

7 Theorem 1.4.4. If B and C are both inverses of the matrix A, then B=C. H.A.O

8 AA = I and A A= I H.A.O

9 Theorem 1.4.5. The matrix A= is invertible if ad-bc≠ 0, in witch case the inverse is given by the formula A = = abcdabcd 1 ad - bc d-b -c a d ad - bc b ad - bc c ad - bc a ad - bc H.A.O

10 Theorem 1.4.6. If A and B invertible matrices of the same size, then: (a) AB is invertible. (b)(AB) = B A. H.A.O

11 A product of any number of invertible matrices is invertible, and the inverse of the product is the product of the inverses in the reverse order. H.A.O

12 Example 7 Consider the matrices A=B=AB= Applying the formula in Theorem1.4.5, we obtain A = B = (AB) = Also, B A = = Therefore, (AB) = B A as guaranteed by Theorem 1.4.6. 12 1 3 3 2 2 3 7 6 9 8 3 -2 -1 1 1 -1 3232 4 -3 - 9292 7272 1 -1 3232 3 -2 -1 1 4 -3 - 9292 7272 H.A.O

13 POWERS OF A MATRIX Definition. If A is a square matrix, then we define the nonnegative integer powers of A to be Moreover, if A is invertible, then we define the negative integer powers to be Aº = I A ⁿ = AA∙ ∙ ∙A ( n >0) n factors Aˉ ⁿ = ( Aˉ¹ )ⁿ = Aˉ¹ Aˉ¹ ∙ ∙ ∙ Aˉ¹ n factors H.A.O

14 Theorem 1.4.7. If A is a square matrix and r and s are integers, then r s r+s r s rs A A = A (A ) = A H.A.O

15 Theorem 1.4.8. If A is an invertible matrix, then: (a) Aˉ¹ is invertible and ( Aˉ¹ ) ˉ¹ = A. (b) A ⁿ is invertible and ( A ⁿ) ˉ¹ = ( Aˉ¹ ) ⁿ for n=0,1,2,… (c) For any nonzero scalar k, the matrix kA is invertible and ( kA ) ˉ¹ = Aˉ¹. 1k1k H.A.O

16 Example 8. Let A and Aˉ¹ be as in Example 7,that is A = A ˉ¹ = Then A ³ = = A ˉ ³ =( A ˉ¹ ) ³ == 1 2 1 3 3 -2 -1 1 1 2 1 3 1 2 1 3 1 2 1 3 11 30 15 41 3 -2 -1 1 3 -2 -1 1 3 -2 -1 1 41 -30 -15 11 H.A.O

17 POLYNOMIAL EXPRESSIONS INVOLVING MATRICES If A is a square matrix, say m × m, and if p(x)= a + a x + ∙ ∙ ∙+a x (1) is any polynomial, then we define p(A)= a I + a A + ∙ ∙ ∙+a A Where I is the m × m identity matrix. In words, p(A) is the m × m matrix that results when A is substituted for x in (1) and a is replaced by a I. 0 0 1 1 n n n n 00 H.A.O

18 Example 9. If p(x)=2x²-3x+4 and A= Then p ( A )=2A²-3A+4I=2 -3 +4 = - + = -1 2 0 3 -1 2 0 3 2 -1 2 0 3 1 0 0 1 2 8 0 18 -3 6 0 9 4 0 0 4 9 2 0 13 H.A.O

19 Theorem 1.4.9. If the sizes of the matrices are such that the stated operations can be performed, then (a) (( A ) ) = A (b) ( A+B ) = A +B and ( A-B ) = A - B (c) ( kA ) = kA, where k is any scalar (d) ( AB ) = B A TTT T T T TTTTT TT H.A.O

20 The transpose of a product of any number of matrices is equal to the product of their transposes in the reverse order. H.A.O

21 Theorem 1.4.10. If A is an invertible matrix, then A is also invertible and (A )ˉ¹ = (A ˉ¹) (4) TT H.A.O

22 Example 10 Consider the matrices A = Applying Theorem 1.4.5 yields A ˉ¹ = (A )ˉ¹ = As guaranteed by Theorem 1.4.10, these matrices satisfy(4) T T -5 -3 2 1 -5 2 -3 1 1 3 -2 -5 1 -2 3 -5 H.A.O


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