Download presentation
Presentation is loading. Please wait.
Published byRandolph Robertson Modified over 9 years ago
3
Projectile Motion ► All objects move in air along a similar path. Explain the shape of that path. ► What is this curve called? (math class)
4
Projectile Motion ► PARABOLA PARABOLA ► Can be represented mathematically ► Same old stuff
5
Projectile Motion Combining the Laws of Motion and what we know about vectors, we can predict the path of projectiles. REMEMBER… X & Y COMPONENTS ARE INDEPENDENT OF EACH OTHER!!!!!
6
Projectile Motion ► Projectile – An object with independent vertical (y) and horizontal (x) motions that moves through the air only under the influence of gravity after an initial thrust ► Trajectory – the path of a projectile through the air
7
Projectile Problem You accidentally throw your car keys horizontally at 9.0 m/s from a cliff 74 m high. How far away from the base of the cliff should you look for your keys? XY
8
Projectile Problems ► Organize information in terms of X and Y components XY
9
Projectile Problems ► Organize information in terms of X and Y components XY Δd y = 74mV x = 9.0 m/s d x = ?
10
Projectile Problems ► What information, that is not stated in the problem, do we know. XY Δd y = 74m a y = 9.8 m/s 2 v yi = 0 m/s at peak of parabola for 2 nd half of the trip V x = 9.0 m/s d x = ?
11
Projectile Problems ► What one variable is part of both the x and y components? TIME ► To solve for d x, we need the time v x = d x / t
12
Projectile Problems ► Can’t solve for t using the X components? ► Can we solve for t using the Y? YEP!
13
Projectile Problems Y’s Δd y = 74m a y = 9.8 m/s 2 v yi = 0 m/s at peak of parabola t = ? Use 2 nd half of parabolic motion, where v yi = 0 m/s (peak of parabola) Δd y = v yi t + ½ a y t 2
14
Projectile Problems ► Solve for t d y = v i t + ½ at 2 74m = 0 + ½ (9.8m/s 2 ) t 2 Therefore, t = √(74m / (½ (9.8m/s 2 ) ) t = 3.9s
15
Projectile Problems ► Knowing the time (3.9s) and v x (9.0m/s), we can solve for d x (where we should look for our keys) ► Using V x = d x / t 9.0m/s = d x / 3.9s d x = 35 m d x = 35 m We should look 35 m from the cliff
16
Projectile Motion Practice Problem ► A stone is thrown horizontally at a speed of +5.0 m/s from the top of a cliff 78.4 m high. How long does it take the stone to reach the bottom of the cliff? How far from the base of the cliff does the stone strike the ground? What are the horizontal and vertical components of the velocity of the stone just before it hits the ground?
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.