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Vectors and Two-Dimensional Motion
Chapter 3 Vectors and Two-Dimensional Motion
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Vectors Vectors – physical quantities having both magnitude and direction Vectors are labeled either a or Vector magnitude is labeled either |a| or a Two (or more) vectors having the same magnitude and direction are identical
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Vector sum (resultant vector)
Not the same as algebraic sum Triangle method of finding the resultant: Draw the vectors “head-to-tail” The resultant is drawn from the tail of A to the head of B R = A + B B A
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Addition of more than two vectors
When you have many vectors, just keep repeating the process until all are included The resultant is still drawn from the tail of the first vector to the head of the last vector
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Commutative law of vector addition
A + B = B + A
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Associative law of vector addition
(A + B) + C = A + (B + C)
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Negative vectors Vector (- b) has the same magnitude as b but opposite direction
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Vector subtraction Special case of vector addition: A - B = A + (- B)
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Multiplying a vector by a scalar
The result of the multiplication is a vector c A = B Vector magnitude of the product is multiplied by the scalar |c| |A| = |B| If the scalar is positive (negative), the direction of the result is the same as (opposite to that) of the original vector
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Vector components Component of a vector is the projection of the vector on an axis To find the projection – drop perpendicular lines to the axis from both ends of the vector – resolving the vector
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Vector components
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Unit vectors Unit vector: Has a magnitude of 1 (unity)
Lacks both dimension and unit Specifies a direction Unit vectors in a right-handed coordinate system
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Adding vectors by components
In 2D case:
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Chapter 3 Problem 14 A quarterback takes the ball from the line of scrimmage, runs backwards for 10.0 yards, then runs sideways parallel to the line of scrimmage for 15.0 yards. At this point, he throws a 50.0-yard forward pass straight downfield, perpendicular to the line of scrimmage. What is the magnitude of the football’s resultant displacement?
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Position The position of an object is described by its position vector,
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Displacement The displacement of the object is defined as the change in its position,
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Velocity Average velocity Instantaneous velocity
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Instantaneous velocity
Vector of instantaneous velocity is always tangential to the object’s path at the object’s position
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Acceleration Average acceleration Instantaneous acceleration
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Acceleration Acceleration – the rate of change of velocity (vector)
The magnitude of the velocity (the speed) can change – tangential acceleration The direction of the velocity can change – radial acceleration Both the magnitude and the direction can change
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Projectile motion A special case of 2D motion
An object moves in the presence of Earth’s gravity We neglect the air friction and the rotation of the Earth As a result, the object moves in a vertical plane and follows a parabolic path The x and y directions of motion are treated independently
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Projectile motion – X direction
A uniform motion: ax = 0 Initial velocity is Displacement in the x direction is described as
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Projectile motion – Y direction
Motion with a constant acceleration: ay = – g Initial velocity is Therefore Displacement in the y direction is described as
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Projectile motion: putting X and Y together
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Projectile motion: trajectory and range
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Projectile motion: trajectory and range
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Chapter 3 Problem 58 A 2.00-m-tall basketball player is standing on the floor 10.0 m from the basket. If he shoots the ball at a 40.0° angle with the horizontal, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard? The height of the basket is 3.05 m.
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Relative motion Reference frame: physical object and a coordinate system attached to it Reference frames can move relative to each other We can measure displacements, velocities, accelerations, etc. separately in different reference frames
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Relative motion If reference frames A and B move relative to each other with a constant velocity Then Acceleration measured in both reference frames will be the same
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Questions?
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Answers to the even-numbered problems
Chapter 3 Problem 2: Approximately 484 km (b) Approximately 18.1° N of W
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Answers to the even-numbered problems
Chapter 3 Problem 6: Approximately 6.1 units at 113° (b) Approximately 15 units at 23°
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Answers to the even-numbered problems
Chapter 3 Problem 10: 1.31 km north, 2.81 km east
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Answers to the even-numbered problems
Chapter 3 Problem 28: x = 7.23 × 103 m, y = 1.68 × 103 m
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