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Published byAmie Bryant Modified over 9 years ago
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Polymerase Chain Reaction
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PCR Repetitive amplification of a piece or region of DNA Numerous uses –Straightforward amplification & cloning of DNA –RT-PCR – reverse transcription coupled with PCR to amplify mRNAs (cDNAs actually are template) –Production of cDNA libraries –Mutagenesis –Sequencing
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PCR Requirements DNA template –DNA that will be amplified (copied) Oligodeoxynucleotide primers –anneal to template to allow DNA replication thermostable DNA polymerase –DNA polymerase extends the primers to synthesize a copy of the template DNA –thermostable polymerases allow automation and repeated rounds of DNA denaturation deoxynucleotides and appriate reaction conditions –dNTPs are incorporated into synthesized DNA, buffered pH, & Mg 2+ to allow enzyme activity of DNA pol
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PCR: The Process 1.Begin with a DNA template Insert in vector 1 st strand cDNA Genomic DNA AAAAAAA TTTTTTT
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PCR: The Process AAAAAAA TTTTTTT 2.Denature template 3.Anneal primers
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AAAAAAA TTTTTTT PCR: The Process 3.Extend primers with thermostable DNA polymerase Taq Pfu This ends a PCR cycle Additional cycles will repeat these three steps
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PCR: The Process Beginning of 2 nd cycle 1.Melt newly synthesized DNA from template New strands of DNA are now also available as templates 2.Anneal primers 3.Extend primers 1 & 23
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PCR: The Process Beginning of 3 rd cycle Melt newly synthesized DNA from template –All new strands of DNA are now also available as templates Anneal primers Extend primers
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PCR: Yields How much amplification can be achieved? –Each cycle of PCR theoretically doubles the number of template molecules –Therefore the rate of amplification is 2 n Where n is the number of amplification cycles –This will reach a practical maximum yield due to reagent (primer & dNTPs) concentration limits and maximum rate due to limiting enzyme concentrations. This upper limit is about 1x10 6 X amplification.
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PCR: Yields Example: Starting with 2ng of 5kb DNA template to amplify a 1Kb insert, what is the theoretical yield after 20 cycles? After 30? 1.How many template molecules are there? = 5000bp X 660g bp/mol bp = 3.3x10 6 g template/mol template = 2x10 -9 g template 3.3x10 6 g temp/mol temp = 6x10 -16 mol temp = 6x10 -16 mol temp X 6.02x10 23 molec/mol = 3.64x10 8 molecules 2. How many molecules of insert can be made in 20 cycles? 30? 3.64x10 8 molecules x 2 20 = 3.8x10 14 molecules – 10 6 X 3.64x10 8 molecules x 2 30 = 3.9x10 17 molecules – 10 9 X
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