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Published byNorma Armstrong Modified over 9 years ago
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-6a – 13a =-19a -8n + 14n = 6n 10r - 19r = -9r
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5xy + 3xy =8xy 2s 2 10ac + 19ac = 9ac 9s 2 + 11s 2 =
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2n x 8 = 16n 24a 2 5e x 9e =45e 2 6a x 4a =
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28b ÷ 7 = 4b 5 2 24 ÷ 4d =6/d 5 3 ÷ 5 =
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x - 3.5 = 8.9 – 3x 4x =12.4 x+-3.5 = 8.93x 4x =8.9 + 3.5 x = 3.1
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2x + 20 = 12 X = 2x = -8 -4
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2/5 = 4y + 16 2/5 = y = 4y-16 -4
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24 + 4c = -2c = -24 4c = -2c - c = 24 6c -4
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1212 3 = ____ 10 22 = ______ 2 50 10110
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4 24 2 4 1 256 6 8 - 10 = 4 24 2 = 4 = 1 = 6262 = 6 10 6 8 = 36
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Rename 2.025 as a mixed number Let x =.025 (x) = (.025) 10x = 0.25 10 (10x) = (0.25)100 1000x =25.25
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Rename 2.025 as a mixed number 10x =.25 1000x = 25.25 = 990x25 x =25/900 or 1/ 36
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Rename 2.025 as a mixed number x =25/900 or 1/ 36 2.025 = 2 +.025.025 = 1/36 2.025 = 2 1/36
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Two-Step Inequalities OBJECTIVE: Solve, graph, and check inequalities that call for two steps to simplify
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2x + 20 < 12 x < -4 2x < 12 -20 2x < -8 Graph the solution. -2 -3 -4 -5 -6 0 Check. Substitute -4 for x. 2(-4) + 20 < 12 -8 + 20 < 12 12 < 12; False Therefore, -4 is not a solution. Solve. Graph and check the solution.
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-2 -3 -4 -5 -6 0 Check another value. 2(-6) + 20 < 12 -12 + 20 < 12 8 < 12; True Therefore, -6 is a solution. Substitute -6 for x. Try -10. 2(- 10) + 20 < 12 -20 + 20 < 12 0 < 12; True Therefore, -10 is also a solution.
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3a < 16 + 11a a -2 3a – 11a < 16 -8a < 16 Graph the solution. -2 -3 -4 -5 -6 0 Check. Substitute -2 for a. 3(-2) < 16 + 11(-2) -6 < 16 -22 -6 < -6;False Solve. Graph and check the solution. -8 >
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Graph the solution. -2 -3 -4 -5 -6 0 Check. Substitute -2 for a. 3(-2) < 16 + 11(-2) -6 < 16 -22 -6 < -6; False Therefore -2 is not a solution. Substituting 0 for a. 3(0) < 16 + 11(0) 0 < 16 +0 0 < 16True Therefore 0 is a solution.
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Homework. PB, p119-120 Class work. PB, p119
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Multistep Inequalities with Grouping symbols OBJECTIVE: solve, graph, and check the solution of an inequality having a grouping symbols
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4(x + 3) -2 Graph the solution. -6 -7 -8 -9 -10 -11 -5 Solve. Graph and check the solution. ≤ 16 Multiply both sides by -2. -2 4(x + 3) - 32 ≥ Apply the DPMoA. 4x + 12 ≥ - 32 Subtract 12 from both sides. - 12 - 11 4x ≥ Divide both sides by 4 4 4 x ≥ - 44 -4
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Graph the solution. -6 -7 -8 -9 -10 -11 -5 -4 Check the solution. 4(x + 3) -2 ≤16 Try -11for x. 4(-11 + 3) -2 ≤16 Combine like terms. 4(-8) -2 ≤ 16 Multiply. -32 -2 16 ≤ Divide 16 ≤ True, so -11 is a solution.
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Graph the solution. -6 -7 -8 -9 -10 -11 -5 -4 Check the solution. 4(x + 3) -2 ≤16 Try x = -5. 4(-5 + 3)3) -2 ≤16 Combine like terms. 4(-2) -2 ≤ 16 Multiply. -8 -2 16 ≤ Divide 164≤ True, so -5 is a solution.
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HW: PB, p121-122 Class work PB, p121
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Multistep Inequalities :fractions and decimals solve, graph, and check the solution of an inequality having fractions and decimals objective Pp 114-115, text
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(0.12x + 0.36) -1-2-340 Example 1.Solve. Graph and check the solution. 0.6 Multiply both sides by 100. 12 - 36 ≥ 1 100 12x + 36 ≥ 60 Subtract 36 from both sides. - 36 12x ≥ 24 Divide both sides by 12. 12 x2 ≥ Graph. 23 0.12x + 0.36 ≥ 0.6 Substitute -2 for x, then evaluate.
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0.12x + 0.36 ≥ 0.6 Substitute -2 for x, then evaluate. 0.12(2) + 0.36 ≥ 0.6 Multiply. 0.24 + 0.36 ≥ 0.6 Add. 0.60 ≥ 0.6 True, so 2 is a solution. 0.12x + 0.36 Try 4 for x, then evaluate. ≥ 0.6 0.12(4) + 0.36 ≥ 0.6 0.48 + 0.36 ≥ 0.6 Multiply. Add. 0.84 ≥ 0.6 True, so 4 is also a solution.
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HW: PB, p125-126 Class work PB, p125
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Compound inequalities OBJECTIVE: graph and find the solution of compound inequalities pp 116-117, text
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1 2 3 4 5 6 0 Graph: x > 3 and x < 7. x > 3 Graph on the number line. 8 9 10 711 x < 7 Graph on the same number line. Solution. The solution set of the compound inequality in shortened form is: {x | 3 < x < 7}
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-2 -1 0 1 2 3 -3 Graph: z ≤ -2 or z ≥ 4. z ≤ -2 Graph on the number line. 5 6 7 48 z ≥ 4 Graph on the same number line. The solution set of the compound inequality in shortened form is: {z | z ≤ -2 or z ≥ 4}
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Homework. PB, p127-128 Class work. PB, p127
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Polynomials OBJECTIVE: d efine a polynomial c lassify a polynomial by the number of its terms s implify polynomials pp 124-125, text
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Do You Remember? A symbol, usually a letter, used to represent a number variable Expressions that contain variables, numbers, and operation symbols Algebraic Expressions A term that doesn’t have variables constant
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Do You Remember? It tells how many times a number or variable called the base is used as a factor. exponent A __ of an algebraic expression is a number, a variable, or the product of a number and one or more vaeiables. term
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Remember… A monomial is an expression that is a number, a variable, or the product of a number and one or more variables with nonnegative exponents. examples:19, m, 7a 2, 13xy, 1/4 abc 10 MMonomials that are real numbers are called constants.
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Remember… A polynomial is a monomial or the sums and/or differences of two or more monomials. Each monomial in a polynomial is called a t tt term. Polynomials can be classified by their n nn number of terms when they are in s ss simplest form.
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Remember… Types of P PP Polynomial NameNumber of TermsExamples Monomial Binomial Trinomial 1(mono means one) 2(bi means two) 3(tri means three) 2n, 4x 3, r, 7, 6x 2 y 5 2x + 8; 3b + p; 2a 2 – 8b 2 4n + b + c; 2x 2 + 8x - 3
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Remember… Classifying P PP Polynomials; before classifying a a polynomial make sure it is in its simplest form. Example. Simplify: x 2 + 2x + 1 + 3x 2 – 4x. Then classify it.
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Remember… Example. What kind of a polynomial is x 2 + 2x + 1 + 3x 2 – 4x? x 2 + 2x + 1 + 3x 2 – 4xCombine like terms. 4x 2 – 2x + 1Classify. 4x 2 – 2x + 1 is a trinomial because it has 3 terms.
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Homework. PB, p139-140 Class work. text, p125
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Modeling Polynomials OBJECTIVE: u se Algebra tiles to model polynomials pp 128-129, text
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Algebra Tiles = x 2 = -x 2 = x = -x = 1 = -1 Examples of polynomials and their models. x 2 - 4-3x 2 + 2x +1
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Write the polynomials modeled by each set of Algebra tiles. 4x 2 + 7x-2x 2 – 2x + 9 3x 2 + 3x - 5 -3x 2 + 2x - 1
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If a polynomial is not in simple form, model it with Algebra tiles then combine like tiles. Example. Simplify 3x 2 – 2x – 4 + x 2 + 3x. Model the polynomial. Create zero pairs, (an x tile and a –x tile, and other opposites). The simple form is 4x 2 + x – 4. Then rearrange the tiles so the like ones are next to each other.
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Homework. PB, p143-144 Class work. text, p129
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Add Polynomials OBJECTIVES : m odel the addition of polynomials a dd polynomials algebraically pp 130-131, text
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Algebra Tiles = x 2 = -x 2 = x = -x = 1 = -1
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Example. Add 3x 2 – 4x + 5 and 2x 2 – x – 3. 3x 2 - 4x + 5 -2x 2 - x - 3 Step 1. Model each polynomial. +
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2x 2 - x - 3 Step 1. Model each polynomial. 3x 2 - 4x + 3 Step 2. Put the same tiles next to each other.
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Step 2. Put the same tiles next to each other. Step 3. Create zero pairs from opposite tiles.
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Step 3. Create zero pairs from opposite tiles. Step 4. Name the remaining tiles for the answer. x 2 - 5x + 2
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Example. Add 2x 2 + 11x + 9 and 3x 2 – 6x (2x 2 + 11x + 9)(3x 2 - 6x) Polynomials can be added algebraically, in either horizontal or vertical form. + To add polynomials horizontally,use the Commutative and Associative properties to group and combine like terms Remove parentheses. 2x 2 + 11x + 9 + 3x 2 - 6x Use the APA and CPA to group and combine like terms 2x 2 + 3x 2 + 11x – 6x + 9 5x 2 + 5x + 9 Answer.
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6x 2 - 7y 2 Example. Add 4x 2 + 3xy – 9y 2 and 6x 2 – 7y 2 4x 2 + 3xy – 9y 2 + To add polynomials vertically, arrange like terms in columns and add the columns separately. 10x 2 + - 16y 2 Arrange like terms in columns 3xy Answer.
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