1. By: Sriya Neelam

2.  Key words…………………………………… Slide 3  Problem to practice…………………… Slide 4  Real life example……………………….. Slide 5  Bibliography………………………………… Slide 7  Thank You……………………………………. Slide 8

3.  A system of linear equations consists of two or more linear equations.  The solution of a system of linear equations in two variables is any ordered pair that solves the linear equations. Later we will talk about 2 ways of solving.  Substitution works by solving one of the equations for one variable and then plugging this back into the other equation.  Graphing works by plotting both equations and by finding the crossing point.

4. Equation1: y= 3x-2 Equation2: y=-x-6 First step: Substitute –x-6 in place of y into the first equation. You will get –x-6=3x-2. Second step: Move the x to one side and the numbers to another side. -6+2=3x+x -4=4x x =-1 y=-5 The solution: (-1,-5) xY=3x-2 11 -2-8 xY= -x-6 -60 0 Crossing point (-1,-5) Equation1 Equation2

5. Two kids have $20 altogether and one has $5 more than the other kid. How much does each kid have? Here is how to set up the system: Let x be how much money one kid has, y be how much money the second kid has. Then, x + y = 20 x − y = 5 Let us use substitution method. You can write the 2 nd equation as: x = 5+y Substitute x=5+y into the 1 st equation 5+y+y=20 2y=15 y=15/2=7.50 x=12.50

6. One kid has $12.50, and other kid has $7.50

7. I used the below references.. - Big Ideas Math.com - www.mathwarehouse.com