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Published byLaureen Griffith Modified over 9 years ago
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Multi Media
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Bit : Bit : is the basic unit of information in computing and telecommunications; it is the amount of information that can be stored by a device or other physical system that can normally exist in only two distinct states (0 or 1). 1 Bit 2 Bit 2 Bit = 2² = 4 (Alternatives) Multi Media 0101 0 1 Alternatives(A,B) 1(0,0) 2(0,1) 3(1,0) 4(1,1) Truth Table
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Multi Media 3 Bit 3Bit = 2³= 8(Alternatives) 0 1 Alternatives(A,B) 1(0,0,0) 2(0,0,1) 3(0,1,0) 4(0,1,1) 5(1,0,0) 6(1,1,0) 7(1,0,1) 8(1,1,1) Truth Table 0 1
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Multi Media 4 Bit 4 Bit = 2 = 16 (Alternatives) 5 Bit 5 Bit = 2=32 (Alternatives) 0 1
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Multi Media 6 Bit = 64 (Alternatives) 7Bit= 128 (Alternatives) 8Bit = 256(Alternatives) = 1 Byte 0 1 ASCII Code Changed to 1 Byte to be understood by the computer system
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Multi Media ASCII Code : Is The American Standard Code for Information Interchange Look to Lec11MM.doc
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1 Character ------ ASCII Code ------- 1 Byte ----- 8 Bit Every character has its own ASCII Code = 1 Byte Multi Media …….… ………. ASCII Code 1 Byte 8 Bit
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Universal Code: In computer architecture, 16-bit integers, memory addresses, or other data units are those that are at most 16 bits (2 octets) wide. A 16-bit file format is a binary file format for which each data element is defined on 16 bits (or 2 Bytes). An example of such a format is UTF-16 and the Windows Metafile Format Multi Media
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The 16-bit Intel architecture allows for different memory models ways to access a particular memory location. The reason for using a specific memory model is the size of the assembler instructions or required storage for pointers. Multi Media
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Compilers of the 16-bit era generally had the following type width characteristic: “Tiny” Code and data will be in the same segment (especially, the registers CS,DS,ES,SS will point to the same segment);“near” pointers are always used. Code, data and stack together cannot exceed 64K. Multi Media Data modelShortIntLongPointer IP16L32(near)16 3216 I16LP32(far)16 32
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“S mall “S mall ” Code and data will be in different segments, and “near” pointers are always used. There will be 64K of space for code and 64K for data/stack. “Medium “Medium ” Code pointers will use “far” pointers, enabling access to 1MB. Data pointers remain to be of the “near” type. “Compact” Data pointers will use “far” and code will use “near” pointers. “Large”/“Huge” Code and data pointers will be “far”. Multi Media
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Case study: An archive CONSISTS of A4 Paper (40 Lines and each Line have 80 characters) AN average rate for data entry is 60 Lines (free of errors)per one hour Calculate: Page contains = amount of lines * amount of character in each line =40*80 = 3200 characters Multi Media
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3200 characters ----- 3200 Click ----- 3200 save in buffer ------ 3200 ASKII code ---- 3200 Byte Then will enter 60 correct line * 80 character = 80 character/minute 80 character/minute ÷ 60 second It means 80 character/minute ÷ 60 second = 1.3 character/second The person will enter the paper in = 3200 character / page ÷80 character/minute= 40minte Multi Media
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We need to take care for : 1.Time established 2.Cost 3.Amount finished Multi Media
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Sources of composing an image are : 1. Camera 2. Scanner 3.Mobile phone OCR Software: Optical Character Recognition Input Image ------- Output Character Paper ------ Scanned ----- OCR ------Text 1 minute to enter text using scanner and OCR 40 minute to enter text using person and keyboard Multi Media
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Value of work, time Information service, Economic service, QoS Between at least two ( A & B ) : Machine & machine or machine & person or person & person Service ( Economy, Time, Cost, Quality ) Service doesn’t depend on infrastructure Information service providers ( ISD ) Multi Media
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SQL 2000 SQL 2005 SQL 2008 Multi Media
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Interactive multimedia service Multi Media
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Usage of multimedia Digital sensors Digital Camera+ Soft ware ( Security ) Movie maker usage Multi Media
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