Download presentation
Presentation is loading. Please wait.
Published byBeverly McDonald Modified over 9 years ago
1
Chemical Reaction Engineering Asynchronous Video Series Chapter 4, Part 1: Applying the Algorithm to a CSTR H. Scott Fogler, Ph.D.
2
Summary At the start of the chapter we saw we needed -r A =f(X). This result is achieved in two steps. 1.Rate Laws –-r A =k f(C i ) –1st order A--> B or 1st order –2nd order A+B --> C –Rate laws are found by experiment 2.Stoichiometry –Liquid: –Gas: -r A =kC A -r A =k A C A C B
3
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate
4
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out:
5
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots)
6
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices)
7
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices) 3.Analytically (Integral tables in Appendix)
8
Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices) 3.Analytically (Integral tables in Appendix) 4.Software packages (Appendix - Polymath)
9
French Menu Analogy
17
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
18
French Menu Analogy Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance:
19
French Menu Analogy Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law:
20
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) French Menu Analogy
21
Remember the French Menu reaction: For a gas phase system: Deriving C A and C B :
22
French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): Deriving C A and C B :
23
French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): We must divide by the stoichiometric coefficient of our basis of calculation yielding: Deriving C A and C B :
24
French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): We must divide by the stoichiometric coefficient of our basis of calculation yielding: And if the feed is equal molar, then: Deriving C A and C B :
25
French Menu Analogy This leaves us with C A as a function of conversion alone: Deriving C A and C B :
26
French Menu Analogy This leaves us with C A as a function of conversion alone: Similarly for C B : Deriving C A and C B :
27
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] French Menu Analogy
28
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] French Menu Analogy
29
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] Combine: French Menu Analogy
30
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] Combine: Evaluate: French Menu Analogy
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.