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Chemical Reaction Engineering Asynchronous Video Series Chapter 4, Part 1: Applying the Algorithm to a CSTR H. Scott Fogler, Ph.D.

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Presentation on theme: "Chemical Reaction Engineering Asynchronous Video Series Chapter 4, Part 1: Applying the Algorithm to a CSTR H. Scott Fogler, Ph.D."— Presentation transcript:

1 Chemical Reaction Engineering Asynchronous Video Series Chapter 4, Part 1: Applying the Algorithm to a CSTR H. Scott Fogler, Ph.D.

2 Summary At the start of the chapter we saw we needed -r A =f(X). This result is achieved in two steps. 1.Rate Laws –-r A =k f(C i ) –1st order A--> B or 1st order –2nd order A+B --> C –Rate laws are found by experiment 2.Stoichiometry –Liquid: –Gas: -r A =kC A -r A =k A C A C B

3 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate

4 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out:

5 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots)

6 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices)

7 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices) 3.Analytically (Integral tables in Appendix)

8 Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate The Evaluate step can be carried out: 1.Graphically (Chapter 2 plots) 2.Numerically (Quadrature formulas: Chapter 2 and Appendices) 3.Analytically (Integral tables in Appendix) 4.Software packages (Appendix - Polymath)

9 French Menu Analogy

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17 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.

18 French Menu Analogy Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance:

19 French Menu Analogy Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law:

20 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) French Menu Analogy

21 Remember the French Menu reaction: For a gas phase system: Deriving C A and C B :

22 French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): Deriving C A and C B :

23 French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): We must divide by the stoichiometric coefficient of our basis of calculation yielding: Deriving C A and C B :

24 French Menu Analogy Remember the French Menu reaction: For a gas phase system: If the conditions are isothermal (T = T 0 ) and isobaric (P =P 0 ): We must divide by the stoichiometric coefficient of our basis of calculation yielding: And if the feed is equal molar, then: Deriving C A and C B :

25 French Menu Analogy This leaves us with C A as a function of conversion alone: Deriving C A and C B :

26 French Menu Analogy This leaves us with C A as a function of conversion alone: Similarly for C B : Deriving C A and C B :

27 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] French Menu Analogy

28 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] French Menu Analogy

29 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] Combine: French Menu Analogy

30 Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Mole Balance: Rate Law: Stoichiometry: gas phase, isothermal (T=T 0 ), no pressure drop (P=P 0 ) [Why do you think C B is constant, when B is consumed?] Combine: Evaluate: French Menu Analogy


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