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SETTLEMENT Of SHALLOW FOUNDATION.

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Presentation on theme: "SETTLEMENT Of SHALLOW FOUNDATION."— Presentation transcript:

1 SETTLEMENT Of SHALLOW FOUNDATION

2 2 types of settlement Elastic ( Immediate ) settlement
Time independent Causes: Elastic deformation of dry soil particles Consolidation settlement Time dependant Causes: Water expulsion

3 ONE DIMENSIONAL CONSOLIDATION TEST
CONSOLIDATION SETTLEMENT To calculate the consolidation settlement we have to perform ONE DIMENSIONAL CONSOLIDATION TEST Consolidometer Audiometer

4 P4<< P3 << P2 << P1
time P1 P2 P3 P4 deformation P4<< P3 << P2 << P1

5 I II III

6 Total settlement S = S1 + S2 + S3
I – Initial compression II – Primary Consolidation III – Secondary Settlement I – Initial compression S1 Causes: imperfect contact surface, loading, particles relocation II – Primary Consolidation S2 Causes: water expulsion III – Secondary Settlement S3 Causes: Particles relocation, Particles deformation, Particles destruction Total settlement S = S1 + S2 + S3

7 e eo e1 e2 While P2 is greater than P1 e2 is smaller than e1 Log P
P1 P2

8 e Cc Cc Compression Index
We can use any curve because the slope is the same Cc The slope from the curve Cc = ( LL – 10 ) for undisturbed samples Cc = ( LL – 10 ) for remolded samples Log P

9 Pc Soil History PRECONSOLIDATION PRESSURE
We can find Soil History by finding what is called PRECONSOLIDATION PRESSURE Or Max Past Effective Overburden Pressure Pc

10 e Pc Log P

11 OCC – Over Consolidated Clay
Based on values of Pc Clay soils may be NCC – Normally Consolidated Clay OCC – Over Consolidated Clay

12 P Cc Pc Po NCC – Normally Consolidated Clay.
Where Po is greater than Pc Pc = Max Past Effective Overburden Pressure Po = Max Present Effective Overburden Pressure P The slope of the curve in this area is Cc Cc Pc Po

13 P Po Pc OCC – Over Consolidated Clay. Where Po is smaller than Pc
Pc = Max Past Effective Overburden Pressure Po = Max Present Effective Overburden Pressure P The slope of the curve in this area is Cs Cs Po Pc

14 Cs NCC Cc OCC Pc

15 Total settlement S = Si + Sp + Ss
INITIAL COMPRESSION ( Si ) PRIMARY CONSOLIDATION SETTLEMENT ( Sp ) SECONDARY SETTLEMENT ( Ss ) ep

16 Cα= /log( ) Ss = C’α H log( ) C’α = ep t1 t2

17 Iρ Si = q B INITIAL COMPRESSION ( Si ) Where: q- net applied pressure
B- width of footing Poisson’s ratio (tab. 6.6 p 167) E- modulus of elasticity (tab. 6.5 p 167) Iρ- influence factor (tab. 6.4 p 167) Poisson’s ratio (tab. 6.6 p 167) E- modulus of elasticity (tab. 6.5 p 167) Iρ- influence factor (tab. 6.4 p 167)

18 TIME RATE OF SETTLEMENT

19 Iρ Iρ < summary S = ) Immediate settlement Si = q B Si = q B NCC
Initial compression Si = q B NCC Primary consolidation S = P0 + ΔP Pc OCC Consolidation settlement Pc P0 + ΔP < Ss = C’α H log( ) Secondary settlement

20 Settlement due to surcharge
S = f ( P, soil, Z, X, load application type ) Load application types: point line strip circle square rectangle irregular

21 A- Elastic or immediate settlement
The settlement of a foundation can be divided into two major categories: A- Elastic or immediate settlement B- Consolidation settlement

22 Immediate or Elastic Settlement
Consolidation Settlement Secondary Settlement Time

23 For the calculation of foundation settlement, it is required to determine the vertical stress increase in the soil mass due to the load applied on the foundation. This chapter is divided into the following three parts: Procedure for calculation of vertical stress increase Elastic settlement calculation Consolidation settlement calculation

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25 dr. isam jardaneh / foundation engineering 61303 / 2010

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33 2 : 1 Method dr. isam jardaneh / foundation engineering / 2010

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35 Average Vertical Stress Increase Due to a Rectangularly Loaded Area
As suggested by Griffiths 1984, to find average pressure increase between z = H1 and z = H2 below the corner of a uniformly loaded rectangular area

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39 Elastic Settlement Elastic settlement Based on The Theory of Elasticity

40 Elastic Settlement Based on The Theory of Elasticity

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46 dr. isam jardaneh / foundation engineering 61303 / 2010

47 dr. isam jardaneh / foundation engineering 61303 / 2010

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52 Elastic Settlement of Foundation on Saturated Clay

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54 Settlement of Sandy Soil: Use of Strain Influence Factor

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56 Continuous Footing

57 Need Interpolation ???

58 Influence Factor Method
Example q = 160 KN/m² Find Elastic Settlement After 5 years Using Influence Factor Method 1.5m γ = 17.8 KN/mᶟ 3 x 3 m 3x3m E KN/m² 1.0m 8000 10000 3.0m 16000

59 0.1 1m 0.5m 0.5 2.5m 2m

60 ∑ = 1.55x10¯⁴ Depth m ΔZ Es KN/m² Average Iz ----- ΔZ mᶟ/KN 0.0 – 1.0
8000 0.233 0.291x10¯⁴ 1.0 – 1.5 0.5 10000 0.433 0.217x10¯⁴ 1.5 – 4.0 2.5 0.361 0.903x10¯⁴ 4.0 – 6.0 2.0 16000 0.111 0.139x10¯⁴ ∑ = 1.55x10¯⁴ Iz Es

61 q C1 = ( ---- ) = [ ] = 0.9 C2 = log (5/0.1) = 1.34 Se = C1 C2 ( q – q ) ∑ (Iz/E)Δz Se = 24.9 mm 17.8x1.5 _ q - q 160 – (17.8x1.5)

62 Range of Materials Parameters for Computing Settlement

63 Range of Materials Parameters for Computing Settlement

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70 dr. isam jardaneh / foundation engineering 61303 / 2010

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72 Example 1

73 Example 2

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83 Problem # 1

84 Problem # 2

85 Problem # 3

86 Problem # 4 Estimate the consolidation settlement of the clay layer shown in Figure below using 2:1 method and trapezoidal rule. Note 1 ton = 2000 lb.


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