Download presentation
Presentation is loading. Please wait.
Published byHarold Morris Modified over 9 years ago
1
Electric fields in Material Space Sandra Cruz-Pol, Ph. D. INEL 4151 ch 5 Electromagnetics I ECE UPRM Mayagüez, PR
2
Last Chapter: free space NOW: different materials
3
Some applications superconductors High permittivity dielectrics Transistors Electromagnets
4
We will study Electric charges: Conductors or Insulators Depends on Frequency and Temperature… Boundary conditions Conductors (metals) Insulators (dielectrics) Semiconductors
5
Material @ 20 o C Low frequency Conductivity (S/m) Silver6.1 x 10 7 Copper5.8 x 10 7 Gold4.1 x 10 7 Aluminum3.5 x 10 7 Carbon3 x 10 4 Sea water4 Silicon4.4 x 10 -4 Pure water10 -4 Dry Earth10 -5 Glass, Quartz10 -12, 10 -17 Colder metals conduct better. (superconductivity) Insulators at most lower frequencies. Conductors- have many free electrons available. semiconductor Appendix B
6
Current Units: Amperes [A] Definition: is the electric charge passing through an area per unit time. Current Density, [A/m 2 ] Is the current thru a perpendicular surface:
7
Depending on how I is produced: There are different types of currents. Convection- I flows thru isolator: liquid, gas, vacuum. Doesn’t involve conductors, doesn’t satisfies Ohm’s Law Conduction- flows thru a conductor Displacement (ch9)
8
Current in a filament Convection current, [A] Convection density, A/m 2 SS vv u ll
9
Conduction Current Requires free electrons, it’s inside conductor. Suffers collisions, drifts from atom to atom Conduction current density is: Newton’s Law where v = ne
10
A Perfect conductor Has many charges that are free to move. Therefore it can’t have an E field inside which would not let the charges move freely. So, inside a conductor Charges move to the surface to make E=0
11
Resistance If you force a Voltage across a conductor: Then E is not 0 The e encounter resistance to move I E V + - S l c = resistivity of the material
12
Power in Watts =Rate of change of energy or force x velocity Joule’s Law
13
PE 5.1 Find the current thru the cylindrical surface For the current density
14
PE 5.2 In a Van de Graaff generator, w=0.1m, u=10m/s and the leakage paths have resistance 10 14 . If the belt carries charge 0.5 C/m 2, find the potential difference between the dome and the base. w= width of the belt u= speed of the belt
15
PE 5.3 The free charge density in Cu is 1.81 x 10 10 C/m 3.. For a current density of 8 x 10 6 A/m 2, find the electric field intensity and the drift velocity.
16
Polarization in dielectrics The effect of polarization on a dielectric is to have a surface bound charge of: and leave within it an accumulation of volume bound charge: ps and pv are the polarization (bounded) surface and volume charge densities
17
Permittivity and Strength Not really a constant!
18
Dielectric properties Linear = doesn’t change with E Isotropic= doesn’t change with direction Homogeneous= doesn’t change from point to point. Coulomb’s Law for any material:
19
PE 5.6. A parallel plate capacitor with plate separation of 2mm has a 1kV voltage applied to its plane. If the space between its plates is filled with polystyrene, find E and P.
20
PE 5.7. In a dielectric material, E x = 5V/m and Find:
21
Continuity Equation Charge is conserved.
22
For steady currents: Change= output current –input current = 0
23
Substituting in: where T r = is called the Relaxation time
24
What is Relaxation Time? [s]
25
Is the time it takes a charge placed in the interior of a material to drop to e -1 of its initial value. Find T r for silver Find T r for rubber:
26
We have two materials How the fields behave @ interface? Boundary Conditions
27
We have two materials How do the fields behave @ interface? We look at the tangential and the perpendicular component of the fields.
28
Cases for Boundary Conditions: 1.Dielectric- dielectric 2.Conductor- Dielectric 3.Conductor-Free Space
29
Dielectric-dielectric B.C. Consider the figure below: E1E1 E2E2 E 1t E 1n E 2t E 2n ab c d w hh 11 22 11
30
Dielectric-dielectric B.C. Consider the figure below: D1D1 D2D2 D 1t D 1n D 2t D 2n hh S 22 11 SS
31
Dielectric-Dielectric B.C. E1E1 D2D2 E 1t E 1n D 2t D 2n hh 22 11 In summary: 11
32
Conductor-dielectric B.C. Consider the figure below: E EtEt EnEn a b c d w hh 11 2 =∞ E 2 =0 11 dielectric conductor
33
Conductor-dielectric B.C. Consider the figure below: E EtEt EnEn hh 11 2 =∞ E 2 =0 11 dielectric conductor S SS
34
Conductor-Free Space B.C. Consider the figure below: E EtEt EnEn a b c d w hh 11 2 =∞ E 2 =0 oo Free space conductor
35
PE 5.9 A homogeneous dielectric ( r =2.5) fills region 1 ( x 0) is free space. Find
36
5.29 Lightning strikes a dielectric sphere of radius 2-mm for which r =2.5, =5x10 -6 S/m and deposits uniformly a charge of 1C. Determine the initial volume charge density and the volume charge density 2s later. Answer: 29.84KC/m3, 18.98 kC/m3
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.