1. Scalars A scalar is any physical quantity that can be completely characterized by its magnitude (by a number value) A scalar is any physical quantity that can be completely characterized by its magnitude (by a number value) Mathematical operations involving scalars – follow rules of elementary algebra Mathematical operations involving scalars – follow rules of elementary algebra In text represented with letters in italic type In text represented with letters in italic type Examples: mass, volume, length Examples: mass, volume, length

2. Vectors Possess a magnitude, direction, and sense Possess a magnitude, direction, and sense Represented graphically by an arrow (tail, tip or head) SHOW Represented graphically by an arrow (tail, tip or head) SHOW –Magnitude: proportional to the length of arrow –Direction: defined by angle between reference axis and line of action of the arrow –Sense: indicated by the arrowhead In text, vector symbolized by boldface type, A, and its magnitude (always positive) by |A | or simply A In text, vector symbolized by boldface type, A, and its magnitude (always positive) by |A | or simply A In slides, vector symbolized by boldface type, A, and magnitude by regular type, A In slides, vector symbolized by boldface type, A, and magnitude by regular type, A In handwritten work, vector represented by letter with an arrow over it, its magnitude by letter enclosed in absolute value symbol or by letter itself SHOW In handwritten work, vector represented by letter with an arrow over it, its magnitude by letter enclosed in absolute value symbol or by letter itself SHOW Obey parallelogram law of addition Obey parallelogram law of addition Examples: position, force, moment Examples: position, force, moment

3. Multiplication and division of a vector by a scalar Product of a vector, A, and a scalar, a Product of a vector, A, and a scalar, a –Vector, aA –Magnitude, aA –Sense of aA is the same as A provided a is positive, it is opposite to A if a is negative Division can be converted to multiplication and then laws of multiplication applied, A/a = (1/a) A, a≠0 Division can be converted to multiplication and then laws of multiplication applied, A/a = (1/a) A, a≠0 Product is associative with respect to scalar multiplication Product is associative with respect to scalar multiplication a(bA) = (ab)A Product is distributive with respect to scalar addition Product is distributive with respect to scalar addition (a + b)A = aA + bA Product is distributive with respect to vector addition Product is distributive with respect to vector addition a(A + B) = aA + aB

4. Vector addition Parallelogram law SHOW Parallelogram law SHOW –Join the tails –Draw parallel dashed lines from the head of each vector to the intersection at a common point –Resultant, R, is the diagonal of the parallelogram (extends from the tails of the two vectors to the intersection of the dashed lines) –Special case – two vectors collinear – parallelogram law reduces to an algebraic or scalar addition, R = A + B Triangular construction (head-to-tail fashion) SHOW Triangular construction (head-to-tail fashion) SHOW –Adding B to A –Connect the tail of vector B to the head of vector A –Resultant, R, extends from the tail of vector A to the head of vector B Vector addition is commutative, A + B = B + A Vector addition is commutative, A + B = B + A Vector addition is associative, (A + B) + D = A + (B + D) Vector addition is associative, (A + B) + D = A + (B + D)

5. Vector subtraction Difference between two vectors A and B Difference between two vectors A and B –Subtraction defined as a special case of addition –R’ = A – B = A + (-B) = A + (-1)B SHOW SHOW

6. Resolution of a vector Vector may be resolved into two “components” having known lines of action by using the parallelogram law Vector may be resolved into two “components” having known lines of action by using the parallelogram law –SHOW –Starting at the head of R, extend dashed line parallel to a until it intersects b, likewise dashed line parallel to b until it intersects a –Two components A and B are then drawn such that they extend from the tail of R to the points of intersection –R is resolved into the vector components A and B

7. Problems in Statics involving force (a vector quantity) Find the resultant force, knowing its components Find the resultant force, knowing its components Resolve a known force into its components Resolve a known force into its components

8. Procedure for analysis – addition of forces Apply parallelogram law Apply parallelogram law –Sketch vector addition using parallelogram law –Determine interior angles from geometry of the problem (recall sum total of interior angles of parallelogram = 360°) –Label known angles and known forces –Redraw half portion of constructed parallelogram to show triangular head-to-tail addition components –Unknowns can be determined from known data on triangle and use of trigonometry –If no 90° angle, law of sines and/or law of cosines may be used SHOW –EXAMPLES (pgs 29-32)

9. Vector components parallel to x and y axes (Cartesian components) F can be resolved into its vector components F x and F y parallel to the x and y axes, F = F x + F y F can be resolved into its vector components F x and F y parallel to the x and y axes, F = F x + F y Unit vectors i and j designate directions along the x and y axes Unit vectors i and j designate directions along the x and y axes –i and j vectors have a dimensionless magnitude of unity –Their direction will be described analytically by a “+” or “-” depending on whether they are pointing along the positive or negative x or y axis SHOW SHOW –F = F x i + F y j (Cartesian vector form) –F’ = F’ x (-i) + F’ y (-j) = - F’ x (i) - F’ y (j) –The magnitude of each component of F is always a positive quantity, represented by the scalars F x and F y –The magnitude of F is given in terms of its components by the Pythagorean theorem, –The direction angle θ, which specifies the orientation of the force, is determined from trigonometry, From this point forward i and j will simply be written in regular type since by definition they are vectors From this point forward i and j will simply be written in regular type since by definition they are vectors

10. Addition of vectors in terms of their (Cartesian) components F 1 = (F 1x i + F 1y j), F 2 = (F 2x i + F 2y j), F 3 = (F 3x i + F 3y j) F 1 = (F 1x i + F 1y j), F 2 = (F 2x i + F 2y j), F 3 = (F 3x i + F 3y j) F R = F 1 + F 2 + F 3 F R = F 1 + F 2 + F 3 F R = (F 1x i + F 1y j) + (F 2x i + F 2y j) + (F 3x i + F 3y j) F R = (F 1x i + F 1y j) + (F 2x i + F 2y j) + (F 3x i + F 3y j) F R = F 1x i + F 2x i + F 3x i + F 1y j + F 2y j + F 3y j F R = F 1x i + F 2x i + F 3x i + F 1y j + F 2y j + F 3y j F R = (F 1x + F 2x + F 3x ) i + (F 1y + F 2y + F 3y ) j F R = (F 1x + F 2x + F 3x ) i + (F 1y + F 2y + F 3y ) j F R = F Rx i + F Ry j F R = F Rx i + F Ry j –F Rx = F 1x + F 2x + F 3x or F Rx = ∑ F x –F Ry = F 1y + F 2y + F 3y or F Ry = ∑ F y EXAMPLES (pgs 40-43) EXAMPLES (pgs 40-43)

11. Rectangular components of a 3-D vector Assume right-handed coordinate system Assume right-handed coordinate system A = A x + A y + A z SHOW A = A x + A y + A z SHOW Cartesian vector notation, A = A x i + A y j + A z k Cartesian vector notation, A = A x i + A y j + A z k Magnitude of Cartesian vector Magnitude of Cartesian vector –A = (A x 2 + A y 2 + A z 2 ) 1/2 –SHOW Direction of Cartesian vector Direction of Cartesian vector –SHOW –cos α = A x /A, cos β = A y /A, cos γ = A z /A

12. Unit vector Unit vector has a magnitude of 1 and specifies a direction Unit vector has a magnitude of 1 and specifies a direction If a unit vector u A and a vector A have the same direction → A can be written as the product of its magnitude A and the unit vector u A, A = A u A If a unit vector u A and a vector A have the same direction → A can be written as the product of its magnitude A and the unit vector u A, A = A u A –u A (dimensionless) defines the direction and sense of A –A (has dimensions) defines the magnitude of A A unit vector having the same direction as A is represented by u A = A/A A unit vector having the same direction as A is represented by u A = A/A

13. Using the unit vector to obtain the direction cosines A unit vector in the direction of A (A = A x i + A y j + A z k) A unit vector in the direction of A (A = A x i + A y j + A z k) u A = A/A = A x /A i + A y /A j + A z /A k u A = A/A = u A x i + u A y j + u A z k ( A x /A = u A x = cos α, A y /A = u A y = cos β, A z /A = u A z = cos γ) u A = A/A = cos α i + cos β j + cos γ k ( u A has a magnitude 1 and recalling that A = (A x 2 + A y 2 + A z 2 ) 1/2 ) 1 = (cos 2 α + cos 2 β + cos 2 γ ) 1/2 Squaring both sides 1 = cos 2 α + cos 2 β + cos 2 γ Equation can be used to determine one of the coordinate direction angles if the other two are known

14. Addition and subtraction of 3-D Cartesian vectors A = (A x i + A y j + A Z k), B = (B x i + B y j + B Z k) A = (A x i + A y j + A Z k), B = (B x i + B y j + B Z k) R = A + B = (A x + B x ) i + (A y + B y ) j + (A z + B z ) k R = A + B = (A x + B x ) i + (A y + B y ) j + (A z + B z ) k R’ = A - B = (A x - B x ) i + (A y - B y ) j + (A z - B z ) k R’ = A - B = (A x - B x ) i + (A y - B y ) j + (A z - B z ) k F R = ∑ F = ∑ F x i + ∑ F y j + ∑ F z k F R = ∑ F = ∑ F x i + ∑ F y j + ∑ F z k EXAMPLES (pgs 52-55) EXAMPLES (pgs 52-55)

15. Position vector If r extends from point A (x A, y A, z A ) to point B (x B, y B, z B ) If r extends from point A (x A, y A, z A ) to point B (x B, y B, z B ) –SHOW –r AB = (x B – x A ) i + (y B – y A ) j + (z B – z A ) k The i, j, k components of the position vector r AB may be formed by taking the coordinates at the head of the vector (point B, (x B, y B, z B )) and subtracting the corresponding coordinates of the tail of the vector (point A, (x A, y A, z A )) The i, j, k components of the position vector r AB may be formed by taking the coordinates at the head of the vector (point B, (x B, y B, z B )) and subtracting the corresponding coordinates of the tail of the vector (point A, (x A, y A, z A ))

16. Force vector directed along a line The direction of a force can be specified by two points through which its line of action passes The direction of a force can be specified by two points through which its line of action passes Formulate F in a Cartesian vector form, realizing it has the same direction as the position vector r directed from point A to point B (A and B are points on a cord along F) Formulate F in a Cartesian vector form, realizing it has the same direction as the position vector r directed from point A to point B (A and B are points on a cord along F) F = Fu = F (r/r) F = Fu = F (r/r) Procedure for analysis Procedure for analysis –Determine position vector r directed from A to B, and compute its magnitude r –Determine the unit vector u = r/r which defines the direction of both r and F –Determine F by combining its magnitude F and direction u F = Fu F = Fu EXAMPLES (pgs 65-68) EXAMPLES (pgs 65-68)

17. Dot product Dot product of vectors A and B, A∙B, “A dot B” Dot product of vectors A and B, A∙B, “A dot B” –A∙B = AB cos θ (where 0°≤θ≤180°), SHOW –The result is a scalar, not a vector –The dot product is also referred to as the scalar product of vectors Applicable laws of operation Applicable laws of operation –Commutative law: A∙B = B∙A –Multiplication by a scalar: a (A∙B) = (aA)∙B = A∙(aB) = (A∙B) a –Distributive law: A∙(B + D) = (A∙B) + (A∙D) Cartesian vector formulation Cartesian vector formulation –i∙i = (1)(1) cos 0° = 1 –i∙j = (1)(1) cos 90° = 0 –i∙k = (1)(1) cos 90° = 0 –Similarly, j∙j = 1, k∙k = 1, j∙k = 0

18. Dot product of two general vectors A∙B = (A x i + A y j + A Z k)∙(B x i + B y j + B Z k) A∙B = (A x i + A y j + A Z k)∙(B x i + B y j + B Z k) = A x B x (i∙i) + A x B y (i∙j) + A x B Z (i∙k) + A y B x (j∙i) + A y B y (j∙j) + A y B z (j∙k) + A y B x (j∙i) + A y B y (j∙j) + A y B z (j∙k) + A z B x (k∙i) + A z B y (k∙j) + A z B z (k∙k) + A z B x (k∙i) + A z B y (k∙j) + A z B z (k∙k) = A x B x + A y B y + A z B z

19. Applications of dot product Determining the angle formed between two vectors or intersecting lines Determining the angle formed between two vectors or intersecting lines (recall A∙B = AB cos θ) θ = cos -1 (A∙B/AB), 0°≤θ≤180° A∙B is computed from A∙B = A x B x + A y B y + A z B z if A∙B = 0 → θ = 90° → A is perpendicular to B

20. Applications of dot product (continued) Components of a vector parallel and perpendicular to a line (aa’) Components of a vector parallel and perpendicular to a line (aa’) –SHOW –Parallel For A p (projection of A onto line aa’) → A p = A cos θ For A p (projection of A onto line aa’) → A p = A cos θ Direction of line specified by the unit vector u (u=1) Direction of line specified by the unit vector u (u=1) A p = A cos θ = (A)(1) cos θ = A∙u [and A p = (A∙u)(u)] The scalar projection of A along a line is determined from the dot product of A and the unit vector u which defines the direction of the line The scalar projection of A along a line is determined from the dot product of A and the unit vector u which defines the direction of the line If A p is positive, then A p has a sense which is the same as u If A p is positive, then A p has a sense which is the same as u If A p is negative, then A p has the opposite sense to u If A p is negative, then A p has the opposite sense to u –Perpendicular A = A p + A n → A n = A - A p A = A p + A n → A n = A - A p A n → A n = A sin θ, θ = cos -1 (A∙u/A) A n → A n = A sin θ, θ = cos -1 (A∙u/A) Or by Pythagorean Theorem A n = (A 2 – A p 2 ) 1/2 Or by Pythagorean Theorem A n = (A 2 – A p 2 ) 1/2 EXAMPLES (pg 76-80) EXAMPLES (pg 76-80)