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Chapter 6 Additional Topics: Triangles and Vectors 6.1 Law of Sines 6.2 Law of Cosines 6.3 Areas of Triangles 6.4 Vectors 6.5 The Dot Product
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6.1 Law of Sines Deriving the Law of Sines Solving ASA and AAS cases Solving the ambiguous SSA case
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The Law of Sines
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Using the Law of Sines (ASA case) Example: Solve this triangle: Solution: º = 180º - (45.1º + 75.8º) = 59.1º
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Using the Law of Sines (AAS case) Example: Solve this triangle: º - (63º + 38º) = 79º
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SSA Variations
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6.2 Law of Cosines Deriving the Law of Cosines Solving the SAS case Solving the SSS case
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Law of Cosines
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Strategy for Solving the SAS Case
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Using the Law of Cosines (SAS case)
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Strategy for the SSS Case
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Navigation Example: Find how far a plane has flown off course at 12º after flying for ¾ of an hour. Also, find how much longer the flight will take.
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6.3 Area of Triangles Base and height given Two sides and included angle given Three sides given (Heron’s Formula) Arbitrary triangles
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Base and Height Given Example: Find the area of this triangle. Solution: A = (ab/2) sin q = ½ (8m)(5m) sin 35º ≈ 11.5 m 2
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Three Sides Given
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Using Heron’s Formula Example: Find the area of the triangle with sides a = 12 cm, b = 8 cm, and c = 6 cm. Solution: s = (12 + 8 + 6)/2 = 13 cm. A = √(13(13-12)(13-8)(13-6) = √(13(1)(5)(7) ≈ 21 cm 2
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6.4 Vectors Velocity and standard vectors Vector addition and Scalar multiplication Algebraic Properties Velocity Vectors Force Vectors Static Equilibrium
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Finding a Standard Vector for a Given Geometric Vector The coordinates (x, y) of P are given by x = x b – x a = 4 – 8 = -4 y = y b – y a = 5 – (-3) = 8
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Vector Addition
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Scalar Multiplication Let u = (-5, 3) and v = (4, -6) u + v = (-5 + 4, 3 + (-6)) = (-1, -3) -3 u = -3(-5, 3) = (-3(-5), -3(3)) = (15, -9)
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Unit Vectors
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Algebraic Properties of Vectors
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The Dot Product The dot product of two vectors Angle between two vectors Scalar component of one vector onto another Work
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The Dot Product
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Computing Dot Products Example: Find the dot product of (4,2) and (1,-3) Solution: (4,2)·(1,-3)=4·1 + 2·(-3) = -2
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Angle Between Two Vectors
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Scalar Component of u on v
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Work Example: How much work is done by a force F = (6,4) that moves an object from the origin to the point p = (8, 2)? Solution: w = (6,4)·(8,2) = 56 ft-lb
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