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Published byRussell Morgan Modified over 9 years ago
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1 The Fourier Series for Discrete- Time Signals Suppose that we are given a periodic sequence with period N. The Fourier series representation for x[n] consists of N harmonically related exponential functions e j2 kn/N, k = 0, 1,2,…….,N-1 and is expressed as where the coefficients c k can be computed as:
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2 Example 2: Determine the spectra of the following signals: (a) x[n] = [1, 1, 0, 0], x[n] is periodic with period 4 (b) x[n] = cos n/3 (c) x[n] = cos( 2) n Solution: (a) x[n] = [1, 1, 0, 0] Now
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3 The magnitude spectra are: and the phase spectra are:
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4 (b) x[n] = cos n/3 Solution: In this case, f 0 = 1/6 and hence x[n] is periodic with fundamental period N = 6. Now Similarly, c 2 = c3 c3 = c4 c4 = 0, c1 c1 = c5 c5 = ½.
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5 (c) Cos( 2) n Solution: The frequency f 0 of the signal is 1/ 2 Hz. Since f 0 is not a rational number, the signal is not periodic. Cosequently, this signal cannot be expanded in a Fourier series.
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6 Power density Spectrum of Periodic Signals The average power of a discrete time periodic signal with period N is The above relation may also be written as or This is Parseval’s Theorem for Discrete-Time Power Signals.
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7 Similarly, for discrete time energy signals, the Parseval’s Theorem may be stated as follows: If the signal x[n] is real, [i.e. x*[n] = x[n]], then we can easily show that |c -k | = |c k | (even symmetry) - c -k = c k (odd symmetry) |c k | = |c N-k | (Periodicity) c k = c N-k (periodicity)
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8 More specifically, we have |c 0 | = |c N | c 0 = - c N |c 0 | = |c N | c 0 = - c N |c 1 | = |c N-1 | c 1 = - c N-1 |c N/2 | = |c N/2 | c N/2 = 0 if N is even |c (N-1)/2 | = |c (N+1)/2 | c (N-1)/2 = (N+1)/2 if N is odd
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9 Example: Determine the Fourier Series Coefficients and the Power Density Spectrum of the following periodic signal.Solution: -N L N A X[n] n k = 0, 1, 2, …., N-1
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10But Therefore,
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11 The Fourier Transform of Discrete-Time Aperiodic Signals The Fourier Transform of a finite energy discrete time signal x[n] is defined as X(w) may be regarded as a decomposition of x[n] into its Frequency components. It is not difficult to Verify that X(w) is periodic with frequency 2 . The Inverse Fourier Transform of X(w) may be defined as
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12 Energy Density Spectrum of Aperiodic Signals Energy of a discrete time signal x[n] is defined as Let us now express the energy E x in terms of the spectral characteristic X(w). First we have If we interchange the order of integration and summation in the above equation, we obtain
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13 Therefore, the energy relation between x[n] and X(w) is This is Parseval’s relation for discrete-time aperiodic signals.
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14 Example: Determine and sketch the energy density spectrum of the signal x[n] = a n u[n], -1<a<1Solution: The energy density spectrum (ESD) is given by 0 w X(w) a = 0.5 a= -0.5
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15 Example: Determine the Fourier Transform and the energy density spectrum of the sequence Solution: The magnitude of x[n] is and the phase spectrum is The signal x[n] and its magnitude is plotted on the next slide. The Phase spectrum is left as an exercise.
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16 x[n] |X(w)|
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17 Properties of Discrete Time Fourier Transform (DTFT) Symmetry Properties: Suppose that both the signal x[n] and its transform X(w) are complex valued. Then x[n] = x R [n] + jx I [n] (1) X(w) = X R (w) + jX I [w] (2) Substitution of (1) and (2) gives Separating the real and imaginary parts, we have
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