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Nondeterministic Finite Automata CS 130: Theory of Computation HMU textbook, Chapter 2 (Sec 2.3 & 2.5)
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NFAs: Nondeterministic Finite Automata Same as a DFA, except: On input a, state q may have more than one transition out, implying the possibility of multiple choices when processing an input symbol On input a, state q may have no transition out, implying the possibility of “being stuck” A string w is acceptable as long as there exists an admissible state sequence for w
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NFAs A nondeterministic finite automaton M is a five-tuple M = (Q, , , q 0, F), where: Q is a finite set of states of M is the finite input alphabet of M : Q power set of Q, is the state transition function mapping a state-symbol pair to a subset of Q q 0 is the start state of M F Q is the set of accepting states or final states of M
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Example NFA NFA that recognizes the language of strings that end in 01 q0q0 q2q2 0,1 0 1 q1q1 note: (q 0,0) = {q 0,q 1 } (q 1,0) = {} Exercise: draw the complete transition table for this NFA
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^ definition for an NFA ^: Q X * power set of Q ^(q, ) = {q} ^(q, w), w = xa (where x is a string and a is a symbol) is defined as follows: Let ^(q, x) = {p 1,p 2,…p k } Then, ^(q, w) = (p i, a)
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Language recognized by an NFA A string w is accepted by an NFA M if ^(q 0, w) F is non-empty Note that ^(q 0, w) represents a subset of states since the automaton is nondeterministic Equivalent definition: there exists an admissible state sequence for w in M The language L(M) recognized by an NFA is the set of strings accepted by M L(M) ={ w | ^(q 0, w) F is non-empty }
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Converting NFAs to DFAs Given a NFA, M = (Q, , , q 0, F), build a DFA, M’ = (Q’, , ’, {q 0 }, F’) as follows. Q’ contains all subsets S of states in Q. The initial state of M’ is the set containing q 0 F’ is the set of all subsets of Q that contain at least one element in F (equivalently, the subset contains at least one final state)
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Converting NFAs to DFAs ’ is determined by putting together, for each state in the subset and each symbol, all states that may result from a transition: ’(S, a) = (q, a) q S May remove “unreachable” states in Q’
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Example conversion NFA DFA q0q0 q2q2 0,1 0 1 q1q1 {q 0 } 1 0 1 {q 0,q 1 } {q 0,q 2 } 0 0 1
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NFA with -transitions NFA that allows the transition of an empty string from a state Jumping to a state is possible even without input Revision on NFA definition simply allows the “symbol” for
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NFA with -transitions A nondeterministic finite automaton with - transitions (or -NFA) is a five-tuple M = (Q, , , q 0, F), where: Q is a finite set of states of M is the finite input alphabet of M : Q ( + ) power set of Q, is the state transition function mapping a state-symbol pair to a subset of Q q 0 is the start state of M F Q is the set of accepting states or final states of M
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Converting -NFAs to NFAs Task: Given an -NFA M = (Q, , , q 0, F), build a NFA M’ = (Q, , ’, q 0, F’) Need to eliminate -transitions Need epsilon closure concept Add transitions to enable transitions previously allowed by the -transitions Note: the conversion process in the textbook instead builds a DFA from an -NFA The conversion described in these slides is simpler
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Epsilon closure In an NFA M, let q Q ECLOSE(q) represents all states r that can be reached from q using only -transitions Recursive definition for ECLOSE If (q, ) is empty, ECLOSE(q) = {q} Else, Let (q, ) = {r 1, r 2,…, r n }. ECLOSE(q) = ECLOSE(r i ) {q} Note: check out constructive definition in the textbook
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Additional transitions Suppose ECLOSE(q) = {r 1, r 2,…, r n }. For each transition from state r i to state s j on (non-epsilon) symbol a, add a transition from q to s j on symbol a That is, ’(q, s) = (q, s) states resulting from the additional transitions Initially set F’ = F. If (q, ) includes a state in F’, add q to F’
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Equivalence of Finite Automata Conversion processes between DFAs, NFAs, and -NFAs show that no additional expressive capacity (except convenience) is introduced by non- determinism or -transitions All models represent regular languages Note: possible exponential explosion of states when converting from NFA to DFA
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Closure of Regular Languages under certain operations UnionL1 L2 ComplementationL1 IntersectionL1 L2 ConcatenationL1L2 Goal: ensure a FA can be produced from the FAs of the “operand” languages
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Finite Automata with Output Moore Machines Output symbol for each state encountered Mealy Machines Output symbol for each transition encountered Exercise: formally define Moore and Mealy machines
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Next: Regular Expressions Defines languages in terms of symbols and operations Example (01)* + (10)* defines all even-length strings of alternating 0s and 1s Regular expressions also model regular languages and we will demonstrate equivalence with finite automata
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