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Angle and Motion Problems (Packets 5 and 6). The sum of the degrees of two complementary angles is 90. #1 If the measure of one of two complimentary angles.

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Presentation on theme: "Angle and Motion Problems (Packets 5 and 6). The sum of the degrees of two complementary angles is 90. #1 If the measure of one of two complimentary angles."— Presentation transcript:

1 Angle and Motion Problems (Packets 5 and 6)

2 The sum of the degrees of two complementary angles is 90. #1 If the measure of one of two complimentary angles is ten less than three times the measure of the other, find the measure of each angle.

3 The sum of the degree measures of two supplementary angles is 180. #2 If the measure of one of two supplementary angles is twenty-four less than five times the measure of the other, find the measure of each angle.

4 The sum of the degree measures of a triangle is 180. #3 The second angle measures sixteen less than twice the first angle and the third angle measures 4 more than three times the first angle. Find the measure of each angle.

5 #4 Dillon drove his car from Philadelphia to New York City at an average rate of 48 mph and returned at an average rate of 62 mph. Find his time going and returning if the time returning was 2 hours less than going. Motion Problems (d = rt) Car 1 Car 2 DistanceRateTime d48t d62t – 2

6 #4 Dillon drove his car from Philadelphia to New York City at an average rate of 48 mph and returned at an average rate of 62 mph. Find his time going and returning if the time returning was 2 hours less than going. Motion Problems (d = rt)

7 #5 Two trains started at the same time 330 miles apart and met in 5 hours. The rate of one train was 12 mph slower than that of the other. Find the rate of each train. Motion Problems (d = rt) slow fast DistanceRateTime 5r5rr5 5(r + 12)r + 125

8 #6 Marcus average 10 mph in a boat traveling downstream and 6 mph traveling upstream. He traveled a total of 24 miles spending as much time going downstream as upstream. How long did he spend going in each direction? Motion Problems (d = rt) Down Up DistanceRateTime 10t10t 6t6t6t


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