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1 Logic Gates
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2 Review of Boolean algebra Just like Boolean logic Variables can only be 1 or 0 Instead of true / false Instead of true / false
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3 Review of Boolean algebra Not is a horizontal bar above the number 0 = 1 0 = 1 1 = 0 1 = 0 Or is a plus 0+0 = 0 0+0 = 0 0+1 = 1 0+1 = 1 1+0 = 1 1+0 = 1 1+1 = 1 1+1 = 1 And is multiplication 0*0 = 0 0*0 = 0 0*1 = 0 0*1 = 0 1*0 = 0 1*0 = 0 1*1 = 1 1*1 = 1 _ _ _ _ _
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4 Review of Boolean algebra Example: translate (x+y+z)(xyz) to a Boolean logic expression (x y z) ( x y z) (x y z) ( x y z) We can define a Boolean function: F(x,y) = (x y) ( x y) F(x,y) = (x y) ( x y) And then write a “truth table” for it: _ _ _ _ _ _ xyF(x,y) 110 100 010 000
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5 Quick survey I understand the basics of Boolean algebra I understand the basics of Boolean algebra a) Absolutely! b) More or less c) Not really d) Boolean what?
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6 Today’s demotivators
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7 Basic logic gates NotAndOrNandNorXor
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8 Rosen, §10.3 question 1 Find the output of the following circuit Answer: (x+y)y Or (x y) y Or (x y) y x+yx+y y (x+y)y(x+y)y__
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9 Rosen, §10.3 question 2 Find the output of the following circuit Answer: xy Or ( x y) ≡ x y Or ( x y) ≡ x y x y xyxy _ _ ___ ___
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10 Quick survey I understand how to figure out what a logic gate does I understand how to figure out what a logic gate does a) Absolutely! b) More or less c) Not really d) Not at all
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11 Rosen, §10.3 question 6 Write the circuits for the following Boolean algebraic expressions a) x+y __ __ x x+yx+y
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12 Rosen, §10.3 question 6 Write the circuits for the following Boolean algebraic expressions b)(x+y)x _______ x+yx+y x+yx+y (x+y)x(x+y)x
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13 Writing xor using and/or/not p q (p q) ¬(p q) x y (x + y)(xy) xy xyxyxyxy 110 101 011 000 x+yx+y xyxyxyxy (x+y)(xy) ____
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14 Quick survey I understand how to write a logic circuit for simple Boolean formula I understand how to write a logic circuit for simple Boolean formula a) Absolutely! b) More or less c) Not really d) Not at all
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15 Converting decimal numbers to binary 53 = 32 + 16 + 4 + 1 = 2 5 + 2 4 + 2 2 + 2 0 = 1*2 5 + 1*2 4 + 0*2 3 + 1*2 2 + 0*2 1 + 1*2 0 = 110101 in binary = 00110101 as a full byte in binary 211= 128 + 64 + 16 + 2 + 1 = 2 7 + 2 6 + 2 4 + 2 1 + 2 0 = 1*2 7 + 1*2 6 + 0*2 5 + 1*2 4 + 0*2 3 + 0*2 2 + 1*2 1 + 1*2 0 1*2 1 + 1*2 0 = 11010011 in binary
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16 Converting binary numbers to decimal What is 10011010 in decimal? 10011010 = 1*2 7 + 0*2 6 + 0*2 5 + 1*2 4 + 1*2 3 + 0*2 2 + 1*2 1 + 0*2 0 0*2 2 + 1*2 1 + 0*2 0 = 2 7 + 2 4 + 2 3 + 2 1 = 2 7 + 2 4 + 2 3 + 2 1 = 128 + 16 + 8 + 2 = 128 + 16 + 8 + 2 = 154 = 154 What is 00101001 in decimal? 00101001 = 0*2 7 + 0*2 6 + 1*2 5 + 0*2 4 + 1*2 3 + 00101001 = 0*2 7 + 0*2 6 + 1*2 5 + 0*2 4 + 1*2 3 + 0*2 2 + 0*2 1 + 1*2 0 0*2 2 + 0*2 1 + 1*2 0 = 2 5 + 2 3 + 2 0 = 2 5 + 2 3 + 2 0 = 32 + 8 + 1 = 32 + 8 + 1 = 41 = 41
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17 A bit of binary humor Available for $15 at http://www.thinkgeek.com/ tshirts/frustrations/5aa9/ Available for $15 at http://www.thinkgeek.com/ tshirts/frustrations/5aa9/
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18 Quick survey I understand the basics of converting numbers between decimal and binary I understand the basics of converting numbers between decimal and binary a) Absolutely! b) More or less c) Not really d) Not at all
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19 How to add binary numbers Consider adding two 1-bit binary numbers x and y 0+0 = 0 0+0 = 0 0+1 = 1 0+1 = 1 1+0 = 1 1+0 = 1 1+1 = 10 1+1 = 10 Carry is x AND y Sum is x XOR y The circuit to compute this is called a half-adder xyCarrySum 0000 0101 1001 1110
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20 The half-adder Sum = x XOR y Carry = x AND y
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21 Using half adders We can then use a half-adder to compute the sum of two Boolean numbers 1 1 0 0 1 1 0 0 + 1 1 1 0 010? 001
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22 Quick survey I understand half adders I understand half adders a) Absolutely! b) More or less c) Not really d) Not at all
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23 How to fix this We need to create an adder that can take a carry bit as an additional input Inputs: x, y, carry in Inputs: x, y, carry in Outputs: sum, carry out Outputs: sum, carry out This is called a full adder Will add x and y with a half-adder Will add x and y with a half-adder Will add the sum of that to the carry in Will add the sum of that to the carry in What about the carry out? It’s 1 if either (or both): It’s 1 if either (or both): x+y = 10 x+y = 10 x+y = 01 and carry in = 1 x+y = 01 and carry in = 1 xyccarrysum 11111 11010 10110 10001 01110 01001 00101 00000
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24 The full adder The “HA” boxes are half-adders
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25 The full adder The full circuitry of the full adder
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26 Adding bigger binary numbers Just chain full adders together
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27 Adding bigger binary numbers A half adder has 4 logic gates A full adder has two half adders plus a OR gate Total of 9 logic gates Total of 9 logic gates To add n bit binary numbers, you need 1 HA and n-1 FAs To add 32 bit binary numbers, you need 1 HA and 31 FAs Total of 4+9*31 = 283 logic gates Total of 4+9*31 = 283 logic gates To add 64 bit binary numbers, you need 1 HA and 63 FAs Total of 4+9*63 = 571 logic gates Total of 4+9*63 = 571 logic gates
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28 Quick survey I understand (more or less) about adding binary numbers using logic gates I understand (more or less) about adding binary numbers using logic gates a) Absolutely! b) More or less c) Not really d) Not at all
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29 More about logic gates To implement a logic gate in hardware, you use a transistor Transistors are all enclosed in an “IC”, or integrated circuit The current Intel Pentium IV processors have 55 million transistors!
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30 Pentium math error 1 Intel’s Pentiums (60Mhz – 100 Mhz) had a floating point error Intel’s Pentiums (60Mhz – 100 Mhz) had a floating point error Graph of z = y/x Graph of z = y/x Intel reluctantly agreed to replace them in 1994 Intel reluctantly agreed to replace them in 1994 Graph from http://kuhttp.cc.ukans.edu/cwis/units/IPPBR/pentium_fdiv/pentgrph.html
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31 Pentium math error 2 Top 10 reasons to buy a Pentium: Top 10 reasons to buy a Pentium: 10Your old PC is too accurate 8.9999163362 Provides a good alibi when the IRS calls 7.9999414610 Attracted by Intel's new "You don't need to know what's inside" campaign 6.9999831538 It redefines computing--and mathematics! 5.9999835137 You've always wondered what it would be like to be a plaintiff 4.9999999021 Current paperweight not big enough 3.9998245917 Takes concept of "floating point" to a new level 2.9991523619 You always round off to the nearest hundred anyway 1.9999103517 Got a great deal from the Jet Propulsion Laboratory 0.9999999998 It'll probably work!!
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32 Flip-flops Consider the following circuit: What does it do?
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33 Memory A flip-flop holds a single bit of memory The bit “flip-flops” between the two NAND gates The bit “flip-flops” between the two NAND gates In reality, flip-flops are a bit more complicated Have 5 (or so) logic gates (transistors) per flip- flop Have 5 (or so) logic gates (transistors) per flip- flop Consider a 1 Gb memory chip 1 Gb = 8,589,934,592 bits of memory 1 Gb = 8,589,934,592 bits of memory That’s about 43 million transistors! That’s about 43 million transistors! In reality, those transistors are split into 9 ICs of about 5 million transistors each
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34 Quick survey I felt I understood the material in this slide set… I felt I understood the material in this slide set… a) Very well b) With some review, I’ll be good c) Not really d) Not at all
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35 Quick survey The pace of the lecture for this slide set was… The pace of the lecture for this slide set was… a) Fast b) About right c) A little slow d) Too slow
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36 End of lecture on 27 January 2005
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