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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 1 Bruce Mayer, PE Engineering-45: Materials of Engineering Bruce Mayer, PE Registered Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 45 Phase Diagrams (1)
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 2 Bruce Mayer, PE Engineering-45: Materials of Engineering Learning Goals – Phase Diagrams When Two Elements Are Combined, Determine the Resulting MicroStructural Equilibrium State For Example Specify –a composition (e.g., wt%Cu - wt%Ni), and –a temperature (T) –a pressure (P) almost ALWAYS assume ROOM Pressure Determine Structure
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 3 Bruce Mayer, PE Engineering-45: Materials of Engineering Learning Goals.2 – Phase Dia. Cont: Determine Structure –HOW MANY phases Result –The COMPOSITION of each phase –Relative QUANTITY of each phase Phase A Phase B
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 4 Bruce Mayer, PE Engineering-45: Materials of Engineering Definitions – Phase Systems Component Pure Constituent of a Compound Typcially an ATOM, but can also be a Molecular Unit Solvent/Solute Solvent Majority Component in a Mixture Solute Minority Component in a Mixture System Possible Alloys Formed by Specific Components (e.g. C-Fe Sys)
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 5 Bruce Mayer, PE Engineering-45: Materials of Engineering The Solid Solubility Limit Solubility Limit Max Concentration of Solute that will actually DISSOLVE in a Solvent to form a SOLUTION Example: Water-Sugar Add Sugar (Solute) to Water (Solvent) –Initially ALL the Sugar Dissolves –But after a Certain Amount, SOLID Sugar Starts to Collect on the bottom of the Vessel Sucrose/Water Phase Diagram Pure Sugar Temperature (°C) 0 20 4060 80100 CoCo =Composition (wt% sugar) L (liquid solution i.e., syrup) Solubility Limit L (liquid) + S (solid sugar) 20 40 60 80 100 PureWater
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 6 Bruce Mayer, PE Engineering-45: Materials of Engineering The Solid Solubility Limit cont. Sol-Sol Quantitative Example At What wt% Sugar does the Sugar NO Longer Dissolve for –20 °C –80 °C For 20 °C Cast Right from 20C –Find Solid Sugar in Vessel at C 0 = 63 wt% For 80C, Again Cast Rt –Find Solid Sugar in Vessel at C 0 = 75 wt% INcreased Temp INcreases Sol-Sol Limit Sugar Pure Temperature (°C) 0 20 4060 80100 CoCo =Composition (wt% sugar) L (liquid solution i.e., syrup) Solubility Limit L (liquid) + S (solid sugar) 20 40 60 80 100 PureWater 63 75
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 7 Bruce Mayer, PE Engineering-45: Materials of Engineering Components & Phases Components The elements or compounds which are mixed initially (e.g., Al and Cu) Phases The PHYSICALLY and CHEMICALLY DISTINCT material regions that result from mixing (e.g., and below) Aluminum Copper Alloy
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 8 Bruce Mayer, PE Engineering-45: Materials of Engineering Effect of T & Composition (C 0 ) Water Sugar System Changing T can change No. of phases: path A to B. Changing C 0 can change No. of phases: path B to D
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 9 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Equilibria Consider the Cu-Ni Alloy System Crystal Structure electroneg r (nm) NiFCC1.90.1246 CuFCC1.80.1278 Both have the same crystal structure (FCC) and have similar electronegativities and atomic radii (c.f. Hume – Rothery rules) suggesting high mutual solubility. Copper and Nickel are, in fact, totally miscible in all Proportions
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 10 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Diagrams –The Cu-Ni Phase Diagram Describes Phase Formation as a Function of T, C 0, P This Course Considers binary systems: 2 components independent variables: T & C 0 (P = 1atm in all Cases) 2 phases: L (liquid) (FCC solid soln) 3 phase fields: L L+ wt% Ni 204060801000 1000 1100 1200 1300 1400 1500 1600 T(°C) L (liquid) (FCC solid solution) L + liquidus solidus
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 11 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Dia.’s: Phase No.s & Types Rule-1: Given T & C 0 (for P = 1 atm) then Find NUMBER & TYPES of Phases Present Examples Pt- A (1100C, 60wt-%) –1 Phase → ; the FCC Solid Solution Pt- B (1250,35) –2 Phases → L+ wt% Ni 204060801000 1000 1100 1200 1300 1400 1500 1600 T(°C) L (liquid) (FCC solid solution) L + liquidus solidus A(1100,60) B (1250,35) –Cu-Ni Phase Diagram
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 12 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Dia.’s: Phase Composition Rule-2: Given T & C 0 (for P = 1 atm) then Find The COMPOSITION (wt% or at%) for EACH Phase Example: C 0 = 35 wt% Ni At T A : –Only Liquid –C L = C O = 35 wt% Ni –Cu-Ni Phase Diagram
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 13 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Dia.’s: Phase Comp. cont. Example: C 0 = 35 wt% Ni At T D : –Only Solid ( -FCC) –C = C 0 = 35 wt% Ni At T B : –BOTH and L –C = C solidus 43 wt% Ni –C L = C liquidus 32 wt% Ni –Cu-Ni Phase Diagram Note the Use of the IsoThermal “Tie Line” at T B to Find C L & C
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 14 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Dia.’s: Phase Wt Fractions Example: C 0 = 35 wt% Ni At T A : –Only Liquid –W L = 1.00 & W = 0.00 (wt Frac’s) At T D : –Only Solid –W L = 0.00 & W = 1.00 (Frac’s) –Cu-Ni Phase Diagram Rule-3: Given T & C 0 (for P = 1 atm) then Find The AMOUNT of EACH Phase in Wt-Fraction
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 15 Bruce Mayer, PE Engineering-45: Materials of Engineering Phase Dia.’s: Wt Fractions cont. Example: C 0 = 35 wt% Ni At T B : –BOTH and L Calc W ,B & W L,B Using the INVERSE LEVER RULE –Cu-Ni Phase Diagram WLWL S R S = 27wt% WW R R S S R
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 16 Bruce Mayer, PE Engineering-45: Materials of Engineering Lever Rule Proof Sum of weight fractions: Conservation of mass (Ni): Combine These Two Equations for W L & W α A Geometric Interpretation Balance massXdist at Tip-Pt
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 17 Bruce Mayer, PE Engineering-45: Materials of Engineering Cooling Cu-Ni Binary Phase-Sys Phase Diagram for Cu-Ni System → System Characteristics: BINARY → 2 components: Cu & Ni ISOMORPHOUS → Complete Solubility of one Component in Another –At least One Solid Phase-Field Extends from 0 to 100 wt% Ni
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 18 Bruce Mayer, PE Engineering-45: Materials of Engineering Ex: Cu-Ni Binary Cooling Consider 35 wt% Ni Cooled: 1300 °C → Rm-Temp Pt-A 1.00 Liquid 35 wt% Ni Pt-B on Liquidus Tiny Amount of solid- in Liq. Suspension –Liq → 35 wt% Ni – → 46 wt% Ni
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 19 Bruce Mayer, PE Engineering-45: Materials of Engineering Ex: Cu-Ni Binary Cooling cont. Pt-C in 2-Ph Region (43-35)/(43-32) = 0.727 Liquid –Liq → 32 wt% Ni – → 43 wt% Ni Pt-D on Solidus Small Liq Pockets in Solid Suspension –Liq → 24 wt% Ni – → 36 wt% Ni Pt E 1.00 , @ C 0
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 20 Bruce Mayer, PE Engineering-45: Materials of Engineering NonEquilibrium Cooling Phases Diagrams are Constructed Under the Assumption of ThermoDynamic Equilibrium i.e., All Phases have Formed Sufficiently Slowly to allow for HOMOGENOUS (same) Concentrations WITHIN ALL Phases In the Previous Example The Solid STARTS at 46 wt%-Ni (pt-B) and ENDS at 35 wt%-Ni (Pt-E) Thus Solid particles that WERE 46Ni Had to CHANGE to 35Ni by SOLID STATE DIFFUSION But Solid-State Diffusion Proceeds Slowly Rapid Cooling Can result in NonUniform Comp.
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 21 Bruce Mayer, PE Engineering-45: Materials of Engineering NonEquil Cool → Cored Structure C Changes Composition Upon Cooling First to solidify has C = 46 wt%Ni Last to solidify has C = 35 wt%Ni Fast Cool Rate → Cored structure Slow Cool Rate → Equil. Structure Uniform C 35wt%Ni to solidfy: First to solidfy: 46wt%Ni Last < 35wt%Ni
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 22 Bruce Mayer, PE Engineering-45: Materials of Engineering Mech Props → Cu-Ni System Recall Solid-Solution Strengthening Tensile Strength, TSDuctility (%EL,%AR) Tensile Strength (MPa) Composition, wt%Ni Cu Ni 020406080100 200 300 400 TS for pure Ni TS for pure Cu Elongation (%EL) Composition, wt%Ni Cu Ni 020406080100 20 30 40 50 60 %EL for pure Ni %EL for pure Cu Max As Fcn of C 0 Min as Fcn of C 0
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 23 Bruce Mayer, PE Engineering-45: Materials of Engineering WhiteBoard PPT Work Problems 9.[5,6] The Affect of PRESSURE on Phase Diagrams Water Ice, Has at Least TEN, yes 10, Distinct Structural Phases –Phases form in Response to the PRESSURE Above The Ice
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 24 Bruce Mayer, PE Engineering-45: Materials of Engineering Ice is Nice – Problem 9.5 Starting Point Note Typo in Book Temperature needs to be –15 °C for this to work Given Ice-I at −15C & 10atm → Find MELTING and SUBLIMATION PRESSURES
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 25 Bruce Mayer, PE Engineering-45: Materials of Engineering Ice is Nice P9.5a – Melt Temp At −15C Cast UPward to the Solid-LIQUID Phase Boundary Find that Ice-I, when held at −15C, MELTS at about 1000 atm (~15000 psi, ~100 Mpa) 1000
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 26 Bruce Mayer, PE Engineering-45: Materials of Engineering Ice is Nice P9.5b – Sublime Temp At −15C Cast DOWNward to the Solid-VAPOR Phase Boundary 0.003 Find that Ice-I, when held at −15C, VAPORIZES at about 0.003 atm (~0.0002 psi, ~20 Pa)
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BMayer@ChabotCollege.edu ENGR-45_Lec-21_PhasrDia-1.ppt 27 Bruce Mayer, PE Engineering-45: Materials of Engineering Ice is Nice P9.6 P = 0.1 Atm At 0.1 Atm Cast RIGHTward to intercept the Sol-Liq and Liq-Vap Phase-Boundaries 2.0 Ice-I MELTS at 2 °C Water BOILS at 75 °C –i.e., the VAPOR PRESSURE of Water at 75 °C is 10% of Atm 75
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