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Chapter 14 NMR Spectroscopy Organic Chemistry 6th Edition Dr. Halligan
CHM 236 Spring 2012 Chapter 14 NMR Spectroscopy Organic Chemistry 6th Edition Paula Yurkanis Bruice
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Ch. 14 Overview Nuclear Magnetic Resonance (NMR) Spectroscopy Theory
Chemical shift Splitting Patterns (N + 1 Rule) Integration Interpretation of 1H and 13C Spectra 13C DEPT and APT NMR Two-Dimensional NMR Spectroscopy Connection between NMR and MRI X-Ray Crystallography
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Nuclear Magnetic Resonance (NMR) Spectroscopy
Identify the carbon–hydrogen framework of an organic compound Certain nuclei, such as 1H, 13C, 15N, 19F, and 31P, have non-zero value for their spin quantum number; this property allows them to be studied by NMR
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The spin state of a nucleus is affected by an applied
magnetic field:
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The energy difference between the spin states increases with the strength of the applied magnetic field:
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a-spin states b-spin states absorb DE release DE Signals detected by NMR
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An NMR Spectrometer In pulsed Fourier transform (FT) spectrometers, the magnetic field is held constant, and a radio frequency (rf) pulse of short duration excites all the protons simultaneously
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The electrons surrounding a nucleus decrease the effective magnetic field sensed by the nucleus:
Beffective = Bo – Blocal
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Chemically equivalent protons: protons in the same chemical environment
Each set of chemically equivalent protons in a compound gives rise to a signal in an 1H NMR spectrum of that compound:
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The Chemical Shift The reference point of an NMR spectrum is defined by the position of TMS (zero ppm): The chemical shift is a measure of how far the signal is from the reference signal The common scale for chemical shifts = d d = distance downfield from TMS (Hz) operating frequency of the spectrometer (MHz)
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1-bromo-2,2-dimethylpropane
1H NMR spectrum of 1-bromo-2,2-dimethylpropane The greater the chemical shift, the higher the frequency The chemical shift is independent of the operating frequency of the spectrometer
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Protons in electron-poor environments show signals at
high frequencies Electron withdrawal causes NMR signals to appear at higher frequency (at larger d values):
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Characteristic Values of
Chemical Shifts
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Diamagnetic Anisotropy
The unusual chemical shifts associated with hydrogens bonded to carbons that form p bonds: The p electrons are freer to move than the s electrons in response to a magnetic field
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The protons show signals at higher frequencies because
they sense a larger effective magnetic field: benzene
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The alkene and aldehyde protons also show signals at
higher frequencies: alkene aldehyde
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The alkyne proton shows a signal at a lower frequency
than it would if the p electrons did not induce a magnetic field: alkyne
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1-bromo-2,2-dimethylpropane
1H NMR spectrum of 1-bromo-2,2-dimethylpropane The area under each signal is proportional to the number of protons giving rise to the signal:
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Integration Line The area under each signal is proportional to the number of protons that give rise to that signal The height of each integration step is proportional to the area under a specific signal The integration tells us the relative number of protons that give rise to each signal, not the absolute number
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Splitting of the Signals
An 1H NMR signal is split into N + 1 peaks, where N is the number of equivalent protons bonded to adjacent carbons Coupled protons split each other’s signal The number of peaks in a signal is called the multiplicity of the signal The splitting of signals, caused by spin–spin coupling, occurs when different kinds of protons are close to one another
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It is not the number of protons giving rise to a signal that
determines the multiplicity of the signal It is the number of protons bonded to the immediately adjacent carbons that determines the multiplicity a: a triplet b: a quartet c: a singlet
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Equivalent protons do not split each other’s signal:
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The ways in which the magnetic fields of three protons
can be aligned:
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Long-range coupling occurs over systems, such as benzene
Splitting is observed if the protons are separated by no more than three s bonds: Long-range coupling occurs over systems, such as benzene
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More Examples of 1H NMR Spectra
Triplet: two neighboring protons Quintet: four neighboring protons
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Triplets: two neighboring protons
Doublet: one neighboring proton Sextet: five neighboring protons Triplets: two neighboring protons Septet: six neighboring protons
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The three vinylic protons are at relatively high frequency
because of diamagnetic anisotropy
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The signals for the Hc, Hd, and He protons overlap because the electronic effect of an ethyl substituent is similar to that of a hydrogen:
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The signals for the Ha, Hb, and Hc protons do not overlap
because of the strong electron-withdrawing property of the nitro group:
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Coupling Constants The coupling constant (J) is the distance between two adjacent peaks of a split NMR signal in hertz: Coupled protons have the same coupling constant
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Summary 1. The number of chemical shifts specify the number of proton environments in the compound 2. The chemical shift values specify the nature of the chemical environment: alkyl, alkene, etc. 3. The integration values specify the relative number of protons 4. The splitting specifies the number of neighboring protons 5. The coupling constants specify the orientation of the coupled protons
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A Splitting Diagram for
a Doublet of Doublets
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Complex Splitting JAC = JAB Triplet JAC > JAB Doublet of doublets
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The trans coupling constant is greater than the cis
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A Splitting Diagram for
a Quartet of Triplets
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Why is the signal for Ha a quintet rather than a
triplet of triplet?
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The Difference between a Quartet and a Doublet of Doublets
Methylene has three neighbors, appears as a quartet Doublet Doublet
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When two different sets of protons split a signal, the
multiplicity of the signal is determined by using the N + 1 rule separately for each set of the hydrogens, as long as the coupling constants for the two sets are different When the coupling constants are similar, the multiplicity of a signal can be determined by treating both sets of adjacent hydrogens as though they were equivalent
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Replacing one of the enantiotopic hydrogens by a
deuterium or any other atom or group other than CH3 or OH forms a chiral molecule: prochiral carbon Ha is the pro-R-hydrogen, whereas Hb is the pro-S-hydrogen; and they are chemically equivalent
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Diastereotopic hydrogens have different chemical shifts:
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Diastereotopic hydrogens are not chemically equivalent:
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The three methyl protons are chemically equivalent
because of rotation about the C—C bond: We see one signal for the methyl group in the 1H NMR spectrum
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1H NMR spectra of cyclohexane-d11 at various temperatures:
axial equatorial equatorial axial The rate of chair–chair conversion is temperature dependent
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Protons Bonded to Oxygen and Nitrogen
The greater the extent of the hydrogen bond, the greater the chemical shift These protons can undergo proton exchange They always appear as broad signals
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pure ethanol ethanol with acid
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A 60-MHz 1H NMR spectrum A 300-MHz 1H NMR spectrum
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To observe well-defined splitting patterns, the difference
in the chemical shifts (in Hz) must be 10 times the coupling constant values
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13C NMR Spectroscopy The number of signals reflects the number of different kinds of carbons in a compound. The overall intensity of a 13C signal is about 6400 times less than the intensity of an 1H signal. The chemical shift ranges over 220 ppm. The reference compound is TMS.
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Proton-Decoupled 13C NMR of
2-Butanol
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Proton-Coupled 13C NMR of 2-Butanol
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The intensity of a signal is somewhat related to the
number of carbons giving rise to it Carbons that are not attached to hydrogens give very small signals
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DEPT 13C NMR distinguishes CH3, CH2, and CH groups:
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The COSY spectrum identifies protons that are coupled:
Cross peaks indicate pairs of protons that are coupled
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COSY Spectrum of 1-Nitropropane
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The HETCOR spectrum of 2-methyl-3-pentanone
indicates coupling between protons and the carbon to which they are attached:
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Unknown Identification Using Spectroscopy
Example 1: 13C-NMR of C5H9Br
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Example 1: 1H-NMR of C5H9Br
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Example 1: IR of C5H9Br Answer:
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Example 2: 13C-NMR of C6H10O4 24.1 33.4 174.4 Solvent:
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Example 2: 1H-NMR of C6H10O4 11.97 1.50 2.21
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Example 2: IR of C6H10O4 Answer:
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