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Naming Ions and Naming and Writing Ionic Compounds
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Monoatomic ions cations lose valence electrons and therefore are positively charged –transition metals form more than one cation with different ionic charges –charge is determined from the # of electrons lost Fe 2+ lost two electrons Fe 3+ lost three electrons –naming Stock system –a Roman numeral is used to show the charge of the transition metal »Fe 2+ is iron(II) and Fe +3 is iron(III) Naming Ions
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Classical system –the older name of the element is used to form the name of the cation »ferrum is Latin for iron the suffix -ous is used to name the cation with the lower charge Fe 2+ is the ferrous ion the suffix -ic is used to name the cation with the higher charge Fe +3 is the ferric ion
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TermDefinition Ag 1+ silver Cd 2+ cadmium Zn 2+ zinc Au 1+ gold(I)/aurous Au 3+ gold(III)/auric Co 2+ cobalt(II)/cobaltous Co 3+ cobalt(III)/cobaltic Cr 2+ chromium(II)/chromous Cr 3+ chromium(III)/chromic Cu 1+ copper(I)/cuprous Cu 2+ copper(II)/cupric Fe 2+ iron(II)/ferrous Fe 3+ iron(III)/ferric Hg 2 2+ mercury(I)/mercurous Hg 2+ mercury(II)/mercuric Mn 2+ manganese(II) Mn 3+ manganese(III) Mn 4+ manganese(IV) Ni 2+ nickel(II)/nickelous Ni 3+ nickel(III)/nickelic Pb 2+ lead(II)/plumbous Pb 4+ lead(IV)/plumbic H 1+ hydrogen H 1- hydride
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– anions gain valence electrons and therefore are negatively charged change ending to -ide
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Polyatomic ions composed of more than one atom that form a single unit/ion with a charge –most end with -ite or –ate the –ite ending indicates one less oxygen than the –ate ending –ionic charge is the same for both
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Naming ionic compounds Binary Compounds –cation is written first, followed by the anion with and –ide ending Cs 2 O cesium oxide SrF 2 strontium fluoride CuO copper(II) oxide –oxygen is always 2- and therefore copper will be 2+ Cu 2 O copper(I) oxide –oxygen is 2- and therefore needed two copper atoms with 1- charge
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–SnF 2 ? fluorine is always 1- and therefore tin will be 2+ –Stock system tin(II) fluoride –Traditional system stannous fluoride –SnS 2 ? sulfur is always 2- and therefore tin will be 4+ –Stock system tin(IV) sulfide –Traditional system stannic sulfide
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Writing formulas for ionic compounds write symbol of cation and then anion add subscripts to balance the charges –calcium bromide Ca 2+ and Br 1- is CaBr 2 –potassium sulfide K +1 and S 2- is K 2 S –iron(III) oxide Fe +3 and O 2- is Fe 2 O 3
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crisscross method the ionic charge number of each ion is crossed over and becomes the subscript for the other ion
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Compounds with polyatomic ions –do same as binary compounds use the name of the polyatomic ion with the mono atomic ion –calcium nitrate ? »Ca is 2+ and nitrate is 1- Ca(NO 3 ) 2 –Li 2 CO 3 ? »lithium carbonate
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Names to Formulas aluminum chloride Al Cl 3 2. Determine number of ions 1. Write symbols of elements Final Formula x(+3) + y(-1) = 0 1 For aluminum, a 1 is multiplied times the +3 to give a +3 charge If there is only one atom the “1” is not shown If there is no Roman Numeral, you must know the oxidation number of the positive ion. +3 If there is no Roman Numeral, you must know the oxidation number of the positive ion. What is the Lowest Common Multiple “LCM” of 3 and 1. Do not worry about the sign(+/-) (Al ) x (Cl -1 ) y What is the Lowest Common Multiple “LCM” of 3 and 1. Do not worry about the sign(+/-) For chloride, a 3 is multiplied times the -1 to give a -3 charge 1(+3) + 3(-1) = 0 Remember all compounds are neutral, thus the total positive charge must equal the total negative charge Next This formula says that the +3 charge of one Al atom will cancel the-3 charge from 3 Cl atoms
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Formula to Name Fe(NO 3 ) 3 Choose the correct name for the compound 1. Iron trinitrate 2. iron(I) nitrate 3. iron(III) nitrite 4. iron(III) nitrate 5. none of the above next problem Polyatomic IonsPeriodic Chart
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Name to Formula sodium chlorite Choose the correct formula for the compound 1. NaCl 2. NaClO 3. NaClO 2 4. Na(ClO) 2 5. none of the above next problem Prefixes Periodic Chart
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