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EENG 2610: Circuit Analysis Class 8: Thevenin’s and Norton’s Theorems Oluwayomi Adamo Department of Electrical Engineering College of Engineering, University.

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Presentation on theme: "EENG 2610: Circuit Analysis Class 8: Thevenin’s and Norton’s Theorems Oluwayomi Adamo Department of Electrical Engineering College of Engineering, University."— Presentation transcript:

1 EENG 2610: Circuit Analysis Class 8: Thevenin’s and Norton’s Theorems Oluwayomi Adamo Department of Electrical Engineering College of Engineering, University of North Texas

2 Thevenin’s and Norton’s Theorems Thevenin’s Theorem  We can replace the entire network, exclusive of the load, by an equivalent circuit that contains only an independent voltage source in series with a resistor in such a way that the current- voltage relationship at the load is unchanged. Norton’s Theorem  Norton’s theorem is identical to the Thevenin’s theorem except that the equivalent circuit is an independent current source in parallel with a resistor. These two theorems are important because  From which we know that if we examine any network from a pair of terminals, the entire network is equivalent to a simple circuit consisting of only an independent source and a resistor.

3 Original Circuit Divide A B Circuit B (Load) Circuit A (linear) A B Circuit B (Load) A B Circuit B (Load) Thevenin’s Theorem Norton’s Theorem

4 From the principle of superposition: A B Circuit B (Load) Circuit A (linear) Circuit A (linear) A B Equivalent : the current due to with all independent sources in circuit A made zero (i.e., voltage sources replaced by short circuits and current sources replaced by open circuits) : the short-circuit current due to all sources in circuit A with replaced by a short circuit. : Thevenin equivalent resistance, the equivalent resistance looking back into circuit A from terminals A-B with all independent sources in circuit A made zero. : open-circuit voltage ( with all independent sources in circuit A made zero )

5 A B Circuit B (Load) A B Circuit B (Load)

6 Example 5.6: Use Thevinin’s and Norton’s theorem to find V o Circuits containing only independent sources

7 Example 5.7: Use Thevinin’s theorem to find V o

8 Example 5.8: Use Thevinin’s and Norton’s theorems to find V o

9 Problem-Solving Strategy Applying Thevenin’s Theorem Step 1: Remove the load and find the voltage across the open- circuit terminals, Voc. Step 2: Determine the Thevenin’s equivalent resistance R Th of the network at the open terminals with the load removed.  (a) If the circuit contains only independent sources Independent sources are made zero by replacing the voltage sources with short circuits and the current sources with open circuits. R Th is then found by computing the resistance of the purely resistive network at the open terminals.  (b) If the circuit contains only dependent sources Since there is no energy source, the Voc is zero in this case. Thevenin equivalent circuit is simply R Th. An independent voltage (or current) source is applied at the open terminals and the corresponding current (or voltage) at these terminals is measured. The voltage/current ratio at the terminals is the Thevenin’s equivalent resistance R Th.

10  (c) If circuit contains both independent and dependent sources, the open-circuit terminals are shorted and the short-circuit current Isc between these terminals is determined. Then, R Th = Voc / Isc. Step 3: If the load is now connected to the Thevenin’s equivalent circuit, consisting of Voc in series with R Th, the desired solution can be obtained. The problem-solving strategy for Norton’s Theorem is essentially the same, with the exception that we are dealing with the short circuit current instead of the open-circuit voltage.


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