2. Distance around the circle

3. 2  r = C or d  = C

4. Find the circumference.

5. Portion of the circumference P A B

6. 3.82 m 60º50º 5cm

8. A =  r 2 ANSWERS WILL BE IN SQUARE UNITS 6.8

9. Find the area.

10. If  S has a circumference of 10  inches, find the area of the circle to the nearest hundredth. C = 2  r 10  = 2  r 5 = r A =  r 2 A =  5 2 A =  25 A =  in 2

11. Find the area of the shaded region. 188.49 in 2 6 in 2 in A =  2 2 A =  8 2 A =  4 A = 12.57  in 2 A =  64 A = 201.06  in 2 A shaded = A – A= 201.06 - 12.57 =

12. SECTOR: region bounded by two radii of the circle and their intercepted arc R O Q Area of a Sector

13. 60° 120 ° 6 cm 7 cm Q R Q R

14. A SEGMENT is a region bounded by a chord and its intercepted arc A segment is a minor segment if the intercepted arc is less than 180 degrees Area of minor segment = (Area of sector) – (Area of triangle)

15. Area of minor segment = (Area of sector) – (Area of triangle) 12 yd R Q

16. CW/ HW Book page 226 #8-10, 17-21 Book page 232 #10-15, 22, 23, 29