1. 105  32  1 2 3 4 52.5  16  36.5  105  Warm-up Find the measures of angles 1 – 4.

2. Homework Review 1)D1) C 2)A2) B 3)B3) A 4)A4) C 5)A5) A 6) C 7) D 8) B

3. EOCT Practice Question of the Day

4. GPS Geometry Day 44 (10-12-12) UNIT QUESTION: What special properties are found with the parts of a circle? Standard: MM2G1, MM2G2 Today’s Question: How do we the area of a sector using proportions? Standard: MM2G3.b

5. 1) Find the circumference and area of a circle with a diameter of 10 in. 2) What would be the radius of a circle if it’s area is ? C = 31.42 in., A = 78.54 in. 2 radius = 8

7. A =  r 2 ANSWERS WILL BE IN SQUARE UNITS 6.8

8. Find the area.

9. If  S has a circumference of 10  inches, find the area of the circle to the nearest hundredth. C = 2  r 10  = 2  r 5 = r A =  r 2 A =  5 2 A =  25 A =  in 2

10. Find the area of the shaded region. 188.49 in 2 8 in 2 in A =  2 2 A =  8 2 A =  4 A = 12.57  in 2 A =  64 A = 201.06  in 2 A shaded = A – A= 201.06 - 12.57 =

11. SECTOR: region bounded by two radii of the circle and their intercepted arc R O Q Area of a Sector

12. 60° 120 ° 6 cm 7 cm Q R Q R

13. A SEGMENT is a region bounded by a chord and its intercepted arc A segment is a minor segment if the intercepted arc is less than 180 degrees Area of minor segment = (Area of sector) – (Area of triangle)

14. Area of minor segment = (Area of sector) – (Area of triangle) 12 yd R Q