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Agresti/Franklin Statistics, 1 of 106  Section 9.4 How Can We Analyze Dependent Samples?

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Presentation on theme: "Agresti/Franklin Statistics, 1 of 106  Section 9.4 How Can We Analyze Dependent Samples?"— Presentation transcript:

1 Agresti/Franklin Statistics, 1 of 106  Section 9.4 How Can We Analyze Dependent Samples?

2 Agresti/Franklin Statistics, 2 of 106 Dependent Samples Each observation in one sample has a matched observation in the other sample The observations are called matched pairs

3 Agresti/Franklin Statistics, 3 of 106 Example: Matched Pairs Design for Cell Phones and Driving Study The cell phone analysis presented earlier in this text used independent samples: One group used cell phones A separate control group did not use cell phones

4 Agresti/Franklin Statistics, 4 of 106 Example: Matched Pairs Design for Cell Phones and Driving Study An alternative design used the same subjects for both groups Reaction times are measured when subjects performed the driving task without using cell phones and then again while using cell phones

5 Agresti/Franklin Statistics, 5 of 106 Example: Matched Pairs Design for Cell Phones and Driving Study Data:

6 Agresti/Franklin Statistics, 6 of 106 Example: Matched Pairs Design for Cell Phones and Driving Study Benefits of using dependent samples (matched pairs): Many sources of potential bias are controlled so we can make a more accurate comparison Using matched pairs keeps many other factors fixed that could affect the analysis Often this results in the benefit of smaller standard errors

7 Agresti/Franklin Statistics, 7 of 106 Example: Matched Pairs Design for Cell Phones and Driving Study To Compare Means with Matched Pairs, Use Paired Differences: For each matched pair, construct a difference score d = (reaction time using cell phone) – (reaction time without cell phone) Calculate the sample mean of these differences: x d

8 Agresti/Franklin Statistics, 8 of 106 For Dependent Samples (Matched Pairs) Mean of Differences = Difference of Means

9 Agresti/Franklin Statistics, 9 of 106 For Dependent Samples (Matched Pairs) The difference (x 1 – x 2 ) between the means of the two samples equals the mean x d of the difference scores for the matched pairs The difference (µ 1 – µ 2 ) between the population means is identical to the parameter µ d that is the population mean of the difference scores

10 Agresti/Franklin Statistics, 10 of 106 For Dependent Samples (Matched Pairs) Let n denote the number of observations in each sample This equals the number of difference scores The 95 % CI for the population mean difference is:

11 Agresti/Franklin Statistics, 11 of 106 For Dependent Samples (Matched Pairs) To test the hypothesis H 0 : µ 1 = µ 2 of equal means, we can conduct the single-sample test of H 0 : µ d = 0 with the difference scores The test statistic is:

12 Agresti/Franklin Statistics, 12 of 106 For Dependent Samples (Matched Pairs) These paired-difference inferences are special cases of single-sample inferences about a population mean so they make the same assumptions

13 Agresti/Franklin Statistics, 13 of 106 Paired-difference Inferences Assumptions: The sample of difference scores is a random sample from a population of such difference scores The difference scores have a population distribution that is approximately normal This is mainly important for small samples (less than about 30) and for one-sided inferences

14 Agresti/Franklin Statistics, 14 of 106 Paired-difference Inferences Confidence intervals and two-sided tests are robust: They work quite well even if the normality assumption is violated One-sided tests do not work well when the sample size is small and the distribution of differences is highly skewed

15 Agresti/Franklin Statistics, 15 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study Boxplot of the 32 difference scores

16 Agresti/Franklin Statistics, 16 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study The box plot shows skew to the right for the difference scores Two-sided inference is robust to violations of the assumption of normality The box plot does not show any severe outliers

17 Agresti/Franklin Statistics, 17 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study

18 Agresti/Franklin Statistics, 18 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study Significance test: H 0 : µ d = 0 (and hence equal population means for the two conditions) H a : µ d ≠ 0 Test statistic:

19 Agresti/Franklin Statistics, 19 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study The P-value displayed in the output is 0.000 There is extremely strong evidence that the population mean reaction times are different

20 Agresti/Franklin Statistics, 20 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study 95% CI for µ d =(µ 1 - µ 2 ):

21 Agresti/Franklin Statistics, 21 of 106 Example: Matched Pairs Analysis for Cell Phones and Driving Study We infer that the population mean when using cell phones is between about 32 and 70 milliseconds higher than when not using cell phones The confidence interval is more informative than the significance test, since it predicts just how large the difference must be

22 Agresti/Franklin Statistics, 22 of 106  Section 9.5 How Can We Adjust for Effects of Other Variables?

23 Agresti/Franklin Statistics, 23 of 106 A Practically Significant Difference When we find a practically significant difference between two groups, can we identify a reason for the difference? Warning: An association may be due to a lurking variable not measured in the study

24 Agresti/Franklin Statistics, 24 of 106 Example: Is TV Watching Associated with Aggressive Behavior? In a previous example, we saw that teenagers who watch more TV have a tendency later in life to commit more aggressive acts Could there be a lurking variable that influences this association?

25 Agresti/Franklin Statistics, 25 of 106 Control Variable A control variable is a variable that is held constant in a multivariate analysis (more than two variables)

26 Agresti/Franklin Statistics, 26 of 106 Can An Association Be Explained by a Third Variable? Treat the third variable as a control variable Conduct the ordinary bivariate analysis while holding that control variable constant at fixed values Whatever association occurs cannot be due to effect of the control variable


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