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Published byWalter O’Connor’ Modified over 9 years ago
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Diode As Circuit Elements Section 3.1-3.3
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Key Concepts Diode models –Exponential model Derivation of n –Ideal model –Constant-voltage model
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Choosing a Diode Model Use the ideal model to develop a quick, rough understanding of a circuit. If the ideal model is not adequate, uses the constant voltage model, which is sufficient for most cases. Occasionally, we will use the exponential model
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I S =Reverse Saturation=leakage current
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Obtain an Exponential Diode Model Empirically
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Ideal Model of a Diode (exponential model) (ideal model) An ideal diode will turn on even for the slightest forward bias voltage. (VD≥0) An ideal diode will turn off even for the slightest reverse bias voltage. (VD<0)
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Behavior of Ideal Diode Ideal diode: V anode >V cathode : Diode is on V anode <V cathode : Diode is off An ideal current experieincing V anode =V cathode, carries no current
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I/V Characteristics An Open—can’t get a current to flow. A short--can’t get a V to develop across a diode. A diode V anode >V cathode : Diode is on V anode <V cathode : Diode is off An ideal current experieincing V anode =V cathode, carries no current In practice, consider a slightly positive or negative voltage to determine the response of a diode.
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Example 1: An OR Gate Realized By Diodes
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Analysis of an OR Gate Observations: 1.If D1 is on, VA=VOUT and VOUT=“1” 2.If D2 is on, VB=VOUT and VOUT=“1”. 3.VOUT is 0 if and only if D1 and D2 are “0” This is an OR gate. Logic 1=3 V Logic 0=0V
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Example of an OR Gate VA=3 V VB=0 V VOUT=2.424 V≈3V
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In Class Exercise VA VB
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In Class Exercise VA VB If VA=“0”, node 1 is “0”. If VB=“0”, node 1 is “0”. If both VA and VB are “1” or 3V, no current can flow through R1, node 1 is 3 V. So we have an AND gate. Assume node 2 is 3V.
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Simulation Example VA=3V VB=0V VOUT=0.575 V
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Simulation Example VA=3V VB=3V VOUT=3 V
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In-Class Exercise What is logic implemented by A, B and LED?
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Solution 0 V
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Basic Gates
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Decimal to Binary Converter Big idea: If you deprive an LED with current,it will turn off. If you provide an LED with current, it will turn on.
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If VD is less than VD, On, the diode behaves like an open circuit. The diode will behave like an open circuit for VD=V D,on Constant Voltage Model
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Analysis of an OR Gate VA=3V, VB=0V Observations: D1 is ON. VD1=0.7V So VOUT=2.3 V D2 is OFF Logic 1=3 V Logic 0=0V
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Example of an OR Gate VA=3 V VB=0 V VOUT=2.424 V≈3V (ideal diode model) ≈2.3 V (constant voltage model)
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Cascade Two Stages of AND gates
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Cascade an AND with an OR
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Limitations of Diode Logic Circuit Vout=1.23 V
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Level Shift Vout of 606 mV Vout can depend on input voltage combination!
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