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Published byAngel Galloway Modified over 11 years ago
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Dihybrid Cross Notes
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1. Determine dominant and recessive traits Carefully read the problem
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2. Assign letters for the trait B = black b = white H = Hairy h = no hair
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3. Determine genotype for parents *Parents must have 4 alleles Heterozygous, black, hairless male = Bbhh White heterozygous hairy female = bbHh
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4. Draw the punnett square with 16 boxes
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5. Put parent gamete combinations on box Bbhh gametes: Bh, Bh, bh, bh bbHh gametes: bH, bh, bH, bh Bh Bh bh bh bH bh bH bh BbHh bbHh Bbhh bbhh BbHh bbHh Bbhh bbhh
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Extra tips When determining the probability of events –If the problem states and then multiply the chances for each Chance of heads and heads = ½ x ½ = ¼ or 25% –If the problem states or then add the chances for each Chance of heads or tails = ½ + ½ = 1 or 100% As you work the problems write in your own extra tips
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