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Published byAshlie Beatrix O’Brien’ Modified over 9 years ago
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INTERNAL COMBUSTION ENGINES LECTURER PROF.Dr. DEMIR BAYKA
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FOR A MIXTURE OF GASES MOLECULAR WEIGHT: SPECIFIC GAS CONSTANT where R 0 =8.314 kJ/kmol-K
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SPECIFIC HEAT OF A GAS MIXTURE
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SPECIFIC HEAT RELATIONS units are kJ/kmol-K also
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ALGORITHMS coefficients A ij can be obtained from pages 131 & 133 of your reference book
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CHAPTER 3 COMBUSTION PROCESS 1. SPARK IGNITION ENGINES AIR + FUEL REACTANTS PRODUCTS
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AIR = OXYGEN + NITROGEN (and some CO2 and Argon) CO2 and Argon may be assumed as part of Nitrogen such that
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FOR UNIT VOLUME OF O 2 4.773 units of AIR = O 2 + 3.773 units of N 2 ’ O 2 is approximately 21% of AIR (on a volume basis)
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FUEL IS MIXTURE OF HYDROCARBONS OTHER FUELS ARE ALCOHOLS, NATURAL GAS, LPG and HYDROGEN GENERAL FORMULA C N H M O L
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MOLECULAR WEIGHT OF THE FUEL C N H M O L M f = 12N + M + 16L EXAMPLE : C 8 H 18 (octane) M f = 12 x 8 + 18 = 114
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ON A MASS BASIS CARBON PERCENT OF FUEL
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ON A MASS BASIS HYDROGEN PERCENT OF FUEL
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ON A MASS BASIS OXYGEN PERCENT OF FUEL
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ASSUMING NO OTHER ELEMENT C + H + O f = 1
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PRODUCTS OF COMBUSTION LEAN MIXTURE CO 2, H 2 O, O 2, N 2 COMPLETE COMBUSTION RICH MIXTURE CO 2, CO, H 2 O, H 2, N 2 INCOMPLETE COMBUSTION
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STOICHIOMETRIC REACTION
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ACTUAL REACTION
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…..COMPLETE COMBUSTION
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…INCOMPLETE COMBUSTION
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TEMPERATURE OF THE PRODUCTS
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n i = The number of moles of species u i = Molar specific internal energy of species (kJ/kmol)
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LET US ASSUME FOR SIMPLICITY:
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INTERNAL ENERGY OF THE REACTANTS
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INTERNAL ENERGY OF THE PRODUCTS
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INTERNAL ENERGY OF THE PRODUCTS
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THE PROCEDURE FOR FINDING THE PRODUCT TEMPERATURE 1. COMPUTE T R ……... (= T 2 ) 2. COMPUTE LHS LHS = (Q R-P + U R ) 3. ASSUME T P and COMPUTE RHS 4. IF RHS<>LHS then ASSUME NEW T P and COMPUTE RHS 5. INTERPOLATE OR EXTRAPOLATE TO FIND T P
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