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Lab 3 2 students: missing info from submissions? (emailed) 95 +/- 13.6 Remember, -10 per day late! Overall, really good.

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Presentation on theme: "Lab 3 2 students: missing info from submissions? (emailed) 95 +/- 13.6 Remember, -10 per day late! Overall, really good."— Presentation transcript:

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2 Lab 3 2 students: missing info from submissions? (emailed) 95 +/- 13.6 Remember, -10 per day late! Overall, really good

3 Homework 2 No submissions from 2 students? Overall Average: 58 Stdev: 6.3 Averages on each problem: 1.9.7 2.8.3 3.7.6 4.9.8 5.9.1 6.5.8 7.9.6

4 10%70%10%.10.70.10 Problem 1

5 107010 171 1171 1 171 1 7497 7

6 11451141 2 2 1 171 1171 1 171 1 7497 7 3*1 + 2*2 + 3*14 + 51 = 3+4+42+51 = 100 Problem 2 Sum these 4 prob. distributions to get -> answer (which we can double check to see it sums to 100%)

7 11451141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20

8 11451141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20 11451141 2 2 1

9 1 51141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20 51141 2

10 1 51141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20 51* 20 14* 60 1* 20 2* 20

11 11451141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20 10.28.4.2.4 10.2+8.4+.2+.4 = 19.2 -> mult by 5.208333

12 11451141 2 2 1 P(d|2): 1 is 20%, 2 is 60%, 3 is 20% We read a distance of 2 from YB YB 20 60 206020 60 20 53.143.81.04 2.08 10.2+8.4+.2+.4 = 19.2 -> mult by 5.208333 Problem 3

13 Problem 4 This method isn’t great. First, we’re not observing after every step. Second, info from this one beacon only covers part of the space. It’s also a little suspicious that there’s no probability for being greater than 3 squares away. We should look for the beacon on every timestep. If we don’t see the beacon, that can also help us update our belief state. We could also have more than one beacon. Or add an additional sensor (e.g., range finder). Or take multiple (independent?) readings from the beacon.

14 Problem 5 Enlarge all boundaries by the maximum size of the robot. In this case, it’s the diagonal. Really, instead of square S and G, you should just have points (since that’s the point of using a configuration space).

15 Problem 6 First, start with the configuration space. Then, draw lines between all pairs of corners/robot that are visible to each other. Many people lost points for – Confusing a “visibility graph” with the parts of the environment the robot can see – Using the workspace, rather than the configuration space – Only drawing lines from the center of the robot start location to visible corners – Missing some of the corners in the graph

16 6: A, B, C, D, E, F, G 7: A, B, E, F, D, C, G Each node gets expanded once (and only once) Therefore, will only “visit” a node once, and will not get stuck in a cycle In Depth First, will visit D and F because D will be added back to the queue of nodes under consideration

17 Test Tuesday 75 min 1 page of paper, 1 side Handwritten or typed

18 Learning to Control a Low-Cost Manipulator using Data-Efficient Reinforcement Learning. M. Deisenroth, C. Rasmussen, D. Fox – http://www.cs.washington.edu/ai/Mobile_Robotics/projec ts/robot-rl/ http://www.cs.washington.edu/ai/Mobile_Robotics/projec ts/robot-rl/ EM/Math Timing, losing connection Eliminate drift (w/ wind) What about a more uniform room? Scaling to larger maps? Automatic scaling was cool.


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