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Kyler Marutzky Motor and Battery Analysis. Objective  Motor capable of powering a 20 lb. aircraft.  Provide enough energy to the motor for a minimum.

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Presentation on theme: "Kyler Marutzky Motor and Battery Analysis. Objective  Motor capable of powering a 20 lb. aircraft.  Provide enough energy to the motor for a minimum."— Presentation transcript:

1 Kyler Marutzky Motor and Battery Analysis

2 Objective  Motor capable of powering a 20 lb. aircraft.  Provide enough energy to the motor for a minimum 40 minute flight.  Motor capable of attaining airspeeds of 40 mph.

3 Motors Considered  Electric Brushless  Gas 2-stroke engine

4 Why Electric?  Less vibration to the rest of aircraft Photos are being taken.  Center of gravity doesn’t change throughout flight.  Advancements in RC electric motors have made them very efficient.

5 Configuration  Pusher  Ducted Fan  Puller Chosen for this application  Twin engine

6 Motor  Hacker A60-16M 2276 max Wattage 65 max Amperage 35 max Volts Fully capable of lifting a 20 lb. aircraft.  Over compensated size Future endeavors.

7 Type of Battery  Lithium Polymer Light weight Capable of supplying more energy than NiMH and Cadmium batteries.

8 Battery Needed  Capable of supplying up to: 1500 Watts (~50 Watts/lb., ~20lb aircraft) 35 Volts 65 Amps  Flight constraints: Capable of supplying enough energy to sustain a 40 minute flight. Capable of providing enough power to the motor for 40mph airspeeds.

9 Battery Chosen  9s3p Lithium Polymer 9-3 cell batteries 3 cells in series 3x3x3 cells in parallel  Cell 4.3 Amp/Hour 3.7 Volts

10 Calculations  Peak power to motor Watts = Current * Volts ○ Current = 4.3 Amps * 9 = 38.7 A ○ Volts = 3.7 * 9 = 33.3V ○ Power = 38.7A * 33.3V = 1288 Watts  Duration of flight Flight time = Amperage/(Amperage/Hour) ○ Battery Amperage = 38.7 A/Hour ○ Average motor amps = 32.1A ○ Flight time = 32.2A/(38.7A/H) =.83 Hours

11 In-Flight Analysis

12 Questions?


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