Presentation is loading. Please wait.

Presentation is loading. Please wait.

MAT 2401 Linear Algebra 1.2 Part II Gauss-Jordan Elimination

Similar presentations


Presentation on theme: "MAT 2401 Linear Algebra 1.2 Part II Gauss-Jordan Elimination"— Presentation transcript:

1 MAT 2401 Linear Algebra 1.2 Part II Gauss-Jordan Elimination http://myhome.spu.edu/lauw

2 HW Written Homework

3 Time Part I may be a bit longer. Part II will be shorter.

4 Preview System with No solutions. System with Infinite Number of solutions.

5 How many solutions? Q: Given a system of 3 equations in 3 unknowns, how many solutions are possible? Inconsistent System Consistent System

6 Example 4 Use Gauss-Jordan Elimination to solve the system. Conclusion: 123

7 Example 5 Use Gauss-Jordan Elimination to solve the system.

8 Example 5 123

9 Geometric Interpretation We are looking for the intersection points of 3 planes (linear equations) It turns out that they are the same intersection points of (another) 2 planes  A straight line

10 Remarks The solution set is the collection of the points on the intersection line of the planes: x-3z=-1 and y-z=0.

11 Expectations Some descriptions are necessary to help your audience to follow your solutions Here, I suggested “The system becomes”. You can use similar wordings if you want.

12 Expectations Since the intersection is a line, it is customary to represent it as a parametric equations (Calculus III)

13 Expectations Instead of “t is any real number”, we use the set notation i.e. t is an element of the real numbers.

14 System of Linear Equations (LE)

15 Homogeneous System of LE

16 Q: Is the system consistent?A:

17 Trivial and Non-Trivial Solutions Trivial Solutions Non-Trivial Solutions At least one of the x i is non-zero. (You need this for today’s HW)

18 Visual Summary


Download ppt "MAT 2401 Linear Algebra 1.2 Part II Gauss-Jordan Elimination"

Similar presentations


Ads by Google