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Published byBethany Riley Modified over 9 years ago
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to: reduces to
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to: reduces to
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to: reduces to
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to: reduces to
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to:
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A vector space containing infinitely many vectors can be efficiently described by listing a set of vectors that SPAN the space. eg: describe the solutions to: These two vectors SPAN the set of solutions. Each of the infinitely many solutions is a linear combination of these two vectors!
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A spanning set can be an efficient way to describe a vector space containing infinitely many vectors. SPANS R 2 - but is it the most efficient way to describe R 2 ? Why do we need this? It is a linear combination of (depends on) the other two.
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A spanning set can be an efficient way to describe a vector space containing infinitely many vectors. SPANS R 2 - but is it the most efficient way to describe R 2 ? Why do we need this? It is a linear combination of (depends on) the other two. This independent set still spans R 2, and is a more efficient way to describe the vector space! definition: An INDEPENDENT set of vectors that SPANS a vector space V is called a BASIS for V.
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= SPANS R 2 : Given any x and y there exist c 1 and c 2 such that
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= is INDEPENDENT: A linear combination of these vectors produces the zero vector ONLY IF c 1 and c 2 are both zero.
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= is INDEPENDENT and SPANS R 2 …. Therefore is a BASIS for R 2. is called the standard basis for R 2 is a nonstandard basis - why do we need nonstandard bases?
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Consider the points on the ellipse below: Described relative to the standard basis they are solutions to: 8x 2 + 4xy + 5y 2 = 1 Described relative to the basis they are solutions to: 9x 2 + 4y 2 = 1 basis =
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There are lots of different ways to write v as a linear combination of the vectors in the set = v = not a BASIS for R 2 example:
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theorem: If = is a BASIS for a vector space V, then for every vector in V there are unique scalars Such that: the c’s exist because spans V they are unique because is independent =
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theorem: If = is a BASIS for a vector space V, then for every vector in V there are unique scalars Such that: 0 = ONLY IF 0000 =
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theorem: If = is a BASIS for a vector space V, then for every vector in V there are unique scalars Such that: the coordinates of = relative to the basis
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This is the vector v
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Relative to the standard basis the coordinates of v are 1 5 =
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Relative to the basis the coordinates of v are 2 3
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v = = coordinates relative standard basis coordinates relative basis
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ?
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ?
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ?
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ? +
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ? +
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ? + IF =0 IF
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example: Suppose V is a vector space that is SPANNED by the two vectors Is it possible that this set of three vectors is INDEPENDENT ? =0 IF The rank is less than the number of variables The solution is not unique NO 3 VECTORS CAN NEVER BE INDEPENDENT in a VECTOR SPACE that is SPANNED BY 2 VECTORS
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The number of independent vectors in a vector space V can never exceed the number of vectors that span V. If is INDEPENDENT in V and SPANS V then k m k m theorem:
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Two different bases for the same vector space will contain the same number of vectors. is a basis for V theorem: If and then k = m k m is a basis for V proof: k m SPANS IS INDEPENDENT k < m k m SPANS IS INDEPENDENT k > m
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Two different bases for the same vector space will contain the same number of vectors. is a basis for V theorem: If and then k = m km is a basis for V definition: The number of vectors in a basis for V is called the DIMENSION of V.
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An independent set of vectors that does not span V can be “padded” to make a basis for V. theorem: Suppose Is independent but does not span V. Then there is at least one vector in V, call it, such that Cannot be written as a linear combination of the vectors in. That is: Is an independent set.
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A spanning set that is not independent can be “weeded” to make a basis. theorem: Suppose spans V but is not independent. Then there is at least one vector in the set, call it u, such that u is a linear combination of the other vectors in the set. Remove u and the remaining vectors in the set will still span V.
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theorem:
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If the dimension of V is n then the set n Containing n vectors is INDEPENDENT IF AND ONLY IF it SPANS V
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theorem: If the dimension of V is n then the set n Containing n vectors is INDEPENDENT IF AND ONLY IF it SPANS V
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theorem: If the dimension of V is n then the set n Containing n vectors is INDEPENDENT IF AND ONLY IF it SPANS V If S = spans V then S is independent. is independent then S spans V. If S =spans V and is not independent then one vector can be removed leaving a spanning set containing n-1 vectors. Since dim V = n, there is in V a set of n independent vectors (basis ). This is impossible. You cannot have more independent vectors than spanning vectors
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theorem: If the dimension of V is n then the set n Containing n vectors is INDEPENDENT IF AND ONLY IF it SPANS V If S =spans V then S is independent. If S = is independent and does not span V, then a vector can be added to S making a set containing n+1 independent vectors - impossible in a space spanned by n vectors- a basis for V contains n vectors If S = is independent then S spans V.
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theorem: If the dimension of V is n then the set n Containing n vectors is INDEPENDENT IF AND ONLY IF it SPANS V
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