Presentation is loading. Please wait.

Presentation is loading. Please wait.

Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Similar presentations


Presentation on theme: "Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?"— Presentation transcript:

1 Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

2 Chapter 1-2

3 What do you think? Point Line Plane Segment Ray Colinear Coplanar Space Opposite Rays Intersection

4 Definitions Point- indicates location has no size Line- straight path that goes on and on forever in both directions. Plane- flat surface with no end and no thickness Segment- part of a line with two end points Ray- part of a line with one end point that never ends on the other side

5 Lets see

6 We DO

7 Intersection- set of all points two figures (lines, planes, shapes) share

8

9 Two Truths and a Lie YAY!!


Download ppt "Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?"

Similar presentations


Ads by Google