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Published byDylan Mason Modified over 9 years ago
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کارایی وقتی خطا وجود نداردکارایی در حالت واقعی ( وجود خطا ) Stop-and-Wait ARQ Selective-Repeat ARQ Go-Back-N ARQ
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Internet Protocol (IP) Addresses
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IPv4 4 Octets, each of them is 8 bits (one byte), Total Length= 32 bits Depicted in decimal Example: 192.168.1.2 O4O3O2O1 IPv6 8 Sections, each section includes 4 4-bit Total Length=128 bits Depicted in Hexadecimal (Base-16) Example: A203:3205:B4F1:9650:784C:21D0:8863:001E S 14 S 13 S 12 S 11 S 24 S 23 S 22 S 21 S 34 S 33 S 32 S 31 S 44 S 43 S 42 S 41 S 54 S 53 S 52 S 51 S 64 S 63 S 62 S 61 S 74 S 73 S 72 S 71 S 84 S 83 S 82 S 81
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IPv4 Address Classes 127.0.0.1 Loopback Test 126 - 1
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Examples in Classes A,B and C CBAClass 193.15.32.0172.17.0.015.0.0.0Network Address 193.15.32.1 193.15.32.254 172.17.0.1 172.17.255.254 15.0.0.1 15.255.255.254 Host Range 193.15.32.255172.17.255.25515.255.255.255Broadcast Address
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فقط جهت اطلاع ( نیاز به نوشتن و حفظ کردن ندارد )
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Invalid IP Addresses IP RangeClass 10.0.0.0 to 10.255.255.255A 172.16.0.0 to 172.31.255.255B 192.168.0.0 to 192.168.255.255C Others are valid IP ranges
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Same SubnetsDifferent Subnets
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Default Subnet Masks
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Subnetting 192.168.3.0 is given We need 4 different subnets Subnet 1: 192.168.3.1/24 to 192.168.3.63/24 Subnet 2: 192.168.3.64/24 to 192.168.3.127/24 Subnet 3: 192.168.3.128/24 to 192.168.3.191/24 Subnet 4: 192.168.3.192/24 to 192.168.3.254/24
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BinaryDecimal 0 0 0 0 0 1 0 0 0 0 0 0 0128 1 1 0 0 0 0 0 0192 1 1 1 0 0 0 0 0224 1 1 1 1 0 0 0 0240 1 1 1 1 1 0 0 0248 1 1 1 1 1 1 0 0252 1 1 1 1 1 1 1 0254 1 1 1 1 255
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Subnet Mask: 255.255.255.224 or /27 6 subnets each of them includes 30 hosts 654321Subnets 192.168.3.192192.168.3.160192.168.3.128192.168.3.96192.168.3.64192.168.3.32Network Address 192.168.3.193 192.168.3.222 192.168.3.161 192.168.3.190 192.168.3.129 192.168.3.158 192.168.3.97 192.168.3.126 192.168.3.65 192.168.3.94 192.168.3.33 192.168.3.62 Host Range 192.168.3.223192.168.3.191192.168.3.159192.168.3.127192.168.3.95192.168.3.63Broadcast Address 192.168.3.0 is given. We need at maximum 4 different subnets Or We need at maximum 30 hosts per subnet 2 X – 2 ≥ Maximum Number of Required Subnets or Hosts/Subnet
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Subnet Mask: 255.255.254.0 or /23 126 subnets each of them includes 510 hosts 126…4321Subnets 172.41.252.0….172.41.8.0172.41.6.0172.41.4.0172.41.2.0 Network Address 172.41.252.1 172.41.253.254 …....... 172.41.8.1 172.41.9.254 172.41.6.1 172.41.7.254 172.41.4.1 172.41.5.254 172.41.2.1 172.41.3.254 *** Host Range 172.41.253.255.....172.41.9.255172.41.7.255172.41.5.255172.41.3.255 Broadcast Address 172.41.0.0 is given We need at maximum 110 different subnets 2 X – 2 ≥ Maximum Number of Required Subnets or Hosts/Subnet *** 172.41.2.1 to 172.41.2.255 (255 Hosts) 172.41.3.0 to 172.41.3.254 (255 hosts) 255+255=510
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10.0.0.0 is given We need at maximum 7865 different hosts/subnet The Related Table?
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