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Published byRolf Lester Modified over 9 years ago
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Thoughts The function F(x) has the following graph. Match the following Values. 1)F’(-3) = 2)F’(-2) = 3)F’(0) = (a) 1 (b) -2 (c) 0
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AP Calculus Unit 2 Day 3 Derivatives of Graphs and Differentiability
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Derivatives we know Y = x+1
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Derivatives we know Y = x 2
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Derivatives we know
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Y = |x|
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Differentiable An adjective – Describes a noun, which in this case is a function Definition: – Capable of being differentiated If a function is differentiable then it is possible to find the derivative.
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FIRST and FOREMOST To have differentiability at a given x-value the function MUST be continuous at that x-value Example
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Example #1—Does exist? First is the function continuous at x=0? Justify your answer. Why is the discontinuity at x=0 a problem?
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Discontinuity Nondifferentiability
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SUPER SIZED Conclusion Discontinuity implies non-differentiability In other words, a function must be continuous at x=a in order to be differentiable at x=a
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A helpful shortcut with some useful notation
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So.... Does this mean that continuity implies differentiability? Let’s explore with this example:
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Does Continuity Mean Differentiability? Is the function continuous at x=-2 ? Justify your answer. Now, lets explore the differentiability at x=-2.
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NOTE: Absolute value functions are NEVER differentiable at the vertex (“corner point”). Likewise, functions that have a “cusp” like are never differentiable at the cusp. However, you can not use these reasons as justifications for non-differentiability. You must resort to using the limit definition of a derivative to prove non-differentiability
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Summarize 1.Confirm continuity 2.Find derivative of the “pieces” 3.Compare the value of the left and right derivatives: Left and right derivatives equal then the derivative exist. Left and right derivatives not equal then the derivative does not exist.
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Another Practice Problem 1. Confirm continuity Is f(x) differentiable at x=2 2. Write derivative function 3. State left and right hand derivatives and make a conclusion.
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CHECKING IN! Left Derivative ≠ Right Derivative Conclusion: NOT Differentiable at x=a Discontinuous at x=a OR
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CHECKING IN! Conclusions: Continuous at x=a Left Derivative = Right Derivative Differentiable at x=a
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