1. LecturePLUS Timberlake1 Temperature Particles are always moving. When you heat water, the water molecules move faster. When molecules move faster, the substance gets hotter. When a substance gets hotter, its temperature goes up.

2. LecturePLUS Timberlake2 Learning Check Suppose you place water in a freezer. A. The water particles move 1) faster 2) slower 3) the same B. The water will get 1) hotter 2) colder 3) stay the same C. The temperature of the water will be 1) higher 2) lower 3) the same

3. LecturePLUS Timberlake3 Solution Suppose you place water in a freezer. A. The water particles move 2) slower B. The water will get 2) colder C. The temperature of the water will be 2) lower

4. LecturePLUS Timberlake4 Temperature Measures the hotness or coldness of an object Determined by using a thermometer that contains a liquid that expands with heat and contracts with cooling.

5. LecturePLUS Timberlake5 Temperature Scales Fahrenheit Celsius Kelvin Water boils _____°F _____°C ______K Water freezes _____°F _____°C ______K

6. LecturePLUS Timberlake6 Temperature Scales Fahrenheit Celsius Kelvin Water boils 212°F 100°C 373 K Water freezes 32°F 0°C 273 K

7. LecturePLUS Timberlake7 Units of Temperature between Boiling and Freezing FahrenheitCelsius Kelvin Water boils 212°F 100°C 373 K 180° 100°C 100K Water freezes 32°F 0°C 273 K

8. LecturePLUS Timberlake8 Learning Check A. Temperature of freezing water 1) 0°F 2) 0°C 3) 0 K B. Temperature of boiling water 1) 100°F 2) 32°F 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 1002) 180 3) 273

9. LecturePLUS Timberlake9 Solution A. Temperature of freezing water 2) 0°C B. Temperature of boiling water 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 100

10. LecturePLUS Timberlake10 Fahrenheit Formula 180°F = 9°F =1.8°F 100°C 5°C 1°C Zero point: 0°C = 32°F °F = 9/5 T°C + 32 or °F = 1.8 T°C + 32

11. LecturePLUS Timberlake11 Celsius Formula Rearrange to find T°C °F = 1.8 T°C + 32 °F - 32 = 1.8T°C ( +32 - 32) °F - 32 = 1.8 T°C 1.8 1.8 (°F x 5/9) – 32 = C

12. LecturePLUS Timberlake12 Temperature Conversions A person with hypothermia has a body temperature of 29.1°C. What is the body temperature in °F? °F = 1.8 (29.1°C) + 32 exact tenth's exact = 52.4 + 32 = 84.4°F tenth’s

13. LecturePLUS Timberlake13 Learning Check The normal temperature of a chickadee is 105.8°F. What is that temperature in °C? 1) 73.8 °C 2) 58.8 °C 3) 41.0 °C

14. LecturePLUS Timberlake14 Solution 3) 41.0 °C Solution: °C = (°F - 32) 1.8 =(105.8 - 32) 1.8 =73.8°F 1.8°= 41.0°C

15. LecturePLUS Timberlake15 Kelvin Scale On the Kelvin Scale 1K = 1°C 0 K is the lowest temperature 0 K = - 273°C K °C K = °C + 273

16. LecturePLUS Timberlake16 Learning Check What is normal body temperature of 37°C in kelvins? 1) 236 K 2) 310 K 3)342 K

17. LecturePLUS Timberlake17 Solution What is normal body temperature of 37°C in kelvins? 2) 310 K K = °C + 273 =37 °C + 273 =310. K