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DYNAMICS Worked Example 4 – Pushing Blocks. 56 N acts on 3 blocks as shown. A 7 kg B 14 kg C 7 kg 56 N Each block experiences 6 N of friction. a) Calculate the acceleration of the blocks.
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1 st Free body Diagram + sign convention Total mass = 28 kg 56 N18 N is +veis -ve F u = 38 N a = ? F u = 38 N m = 28 kg a = ? a = F u m = 38 28 = 1.4 ms -2
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b) What force does block A exert on block B ? Blocks B and C are affected. Mass of B& C = 21 kg F from A F f = -12 N F u = ? a = 1.4 m/s 2 m = 21 kg F u = m B+C x 1.4 = 21 x 1.4 = 29.4 N is +veis -ve F u = F A + F f F A = F u - F f = 29.4 – (-12) = 41.4 N Over to you – Problems up to 75.
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Internal forces tutorial. Revision questions for Higher Physics, page 17, Q. 1 – 7. Components of forces tutorial. Revision questions for Higher Physics, page 18, Q. 1 – 4. Reminder - Components of forces. Read through your Components of a Vector written notes. Force is a vector therefore the components are found using this method. Forces on a slope tutorial. Revision questions for Higher Physics, page 18, Q. 1 – 5. Lifts tutorial Revision questions for Higher Physics, page 20, Q. 1 – 6. Reminder – Forces on a slope. Read through your forces on a slope notes. Remember – use s in for component of weight parallel to the s lope.
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Problems 52 – 75 52.4900 N 53. a) (i) 0.015 ms -2 (ii) 3 x 10 6 N b) -0.0027 ms -2 54. OA … decreasing acceleration as air resistance increases AB…constant velocity as air resistance balances the weight BC … parachute opens so dramatic deceleration to lower speed CD … constant velocity as new air resistance balances weight DE …dramatic deceleration as parachutist lands. 55.0.02 ms -2 56. 150 N 57. a) 120 N b) -20 N 58.a) 1200 N b) 108 m c) 2592 N 59.a) (ii) 7.7 ms -2 b) mass decreases as fuel is burned, air resistance decreases as rocket leaves Earth’s atmosphere, weight decreases as rocket leaves Earth’s gravitational field. c) 15.9 ms -2 d) Once out of Earth’s gravitational pull weight drops to zero so engines can be switched off and rocket will continue at a constant velocity. 60.a) 1778 kg b) 62 424 N 61. 28 600 N 62.a) 1960 N b) 2260 N c) 1960 N d) 1660 N 63.a) (i) 2450 N (ii) 2450 N (iii) 2950 N (iv) 1950 N b) 4.2 ms -2
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Problems 52 – 75 (cont.) 63. c) An empty lift so resultant force would increase giving a higher acceleration. 64.51.2 N 65.a)b) 37.2 N, 39.2 N, 43.2 N. 66.a) 8 m/s 2 b) 16N 67.a) 5100N b) 2500N c) 700N, 500N d) 10,300N 68. 24m 69.a) 2 m/s 2 b) 40N c) 20N d) 12N e) No – A onto B affects 2 blocks so must balance 8N of friction. B onto C only affects 1 block so just has to balance 4N of friction. 70. a) 3.27 m/s 2 b) 6.54 N 71. 0.541 m/s 2 72. a) 225.5N b) 0.376 m/s 2 73. 9.8 N 74. 0.735 N 75. a) 2283 N b) 2.2 m/s 2 c) 14.8 m/s d) 8520N a (m/s 2 ) 0.5 0 t (s)
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