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Mole Calculations 1
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Chemical Calculations Atoms and molecules are extremely small. If they are so small and so light, how can we weigh them? We weigh large numbers of them.
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Avogadro took 1.00 g of the smallest atom (H) and determined how many H atoms there are in 1.00 g of H. He found that: 1.00 g H = 6.02 x 10 23 atoms = 1.00 mole This is called Avogadro’s number
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1 dozen donuts = 12 donuts 1 century = 100 years 1 millennium = 1000 years 1.00 mole = 6.02 x 10 23 particles
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The mole is a large number of particles Particle AtomelementCu 6.02 x 10 23 at 1 mole MoleculecovalentCH 4 6.02 x 10 23 molecules 1 mole Formula UnitionicNaCl 6.02 x 10 23 FUs 1 mole
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1. Convert 2.5 x 10 25 at C to moles = 42 moles C 6.02 x 10 23 at x 1 mole2.5 x 10 25 at
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2. Convert 16.3 moles CO 2 to molecules = 9.81 x 10 24 molecules 1mole x 6.02 x 10 23 molecules16.3 moles
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3. Convert 8.9 x 10 24 molecules CO 2 to moles = 15 moles CO 2 6.02 x 10 23 molecules x 1 mole 8.9 x 10 24 molecules
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= 1.7 x 10 25 FUs 1mole x 6.02 x 10 23 FU 28 moles 4. Convert 28 moles NaCl to Formula Units
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Determining Avogadro’s Number
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Ampmeter Power Supply Stop Watch Electrolysis Apparatus
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Determining Avogadro’s Number Produce a volume of hydrogen gas while measuring the time and electrical current. Volume of H 2 10.0 mL Time80.7 s Current0.913 amp
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Background information 1 amp is defined as the number of coulombs per second. There are 6.24 x 10 18 electrons in a coulomb. The density of H 2 is 0.07871 g/L. It takes 1 electron to make 1 H atom
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1. Calculate the number of atoms of H, starting with the time. = 4.5976 x 10 20 at 1 el x 1 at H 1 couls x 6.24 x 10 18 elx 0.913 coul80.7 s
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2. Calculate the number of grams H starting with the volume of H. = 7.871 x 10 -4 g H 1 L x 0.07871 g 1000 mL x 1 L10.0 mL
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3. Divide the atoms of H by the grams of H to get the number of H atoms in a gram which is Avogadro’s number. 7.871 x 10 -4 g H =5.84 x 10 23 at/ 1 gram H =5.84 x 10 23 at/ 1 mole The Mole Song 4.5976 x 10 20 at Avogadro Facts
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