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Martin Gardner ( ) Scientific American – Mathematical Games column

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Presentation on theme: "Martin Gardner ( ) Scientific American – Mathematical Games column"— Presentation transcript:

1 Martin Gardner ( ) Scientific American – Mathematical Games column (297 monthly columns) Books: Mathematical Games Word puzzles Annotated Alice Books on pseudoscience and skepticism Presentation by Dennis Mancl,

2 Magic squares 8 1 6 3 5 7 4 9 2 8 + 1 + 6 = 15 An array of numbers
No duplicates The sum of each row is the same The sum of each column is the same 3 5 7 = 15 4 9 2 = 15 8 3 + 4 15 1 5 + 9 15 6 7 + 2 15

3 Magic squares ? ? ? ? Use the numbers 1 through 16 What will be the sum of each row? ? ? ? ? (1+2+…+16) / 4 1+2+…+n = (n+1)  n / 2 (1+2+…+16) / 4 = (17  16 / 2) / 4 = 136 / 4 = 34 ? ? ? ? ? ? ? ?

4 Magic squares 1 2 3 5 6 7 9 10 11 4 8 12 13 14 15 16 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 Start with 2 squares – numbers in reverse order

5 Magic squares 1 2 3 4 16 15 14 13 5 6 7 8 12 11 10 9 9 10 11 12 8 7 6 5 13 14 15 16 4 3 2 1 Choose 8 cells from one square, 8 cells from the other

6 Magic squares 1 2 3 5 6 7 9 10 4 8 13 14 11 12 15 16 7 4 3 8 16 15 14 12 11 10 6 13 9 5 2 1 16 2 3 5 11 10 9 7 6 13 8 12 4 14 15 1

7 Magic squares 16 2 3 5 11 10 9 7 6 13 8 12 4 14 15 1 = 34 = 34 = 34 = 34 16 5 9 + 4 34 2 11 7 + 14 34 3 10 6 + 15 34 13 8 12 + 1 34

8 Albrecht Dürer – Melencolia I (1514)
16 2 3 5 11 10 9 7 6 13 8 12 4 14 15 1

9 Puzzles

10 If there are 4 red balls and 6 white balls
Spend 6 cents === guaranteed to have at least two red balls Spend 8 cents === guaranteed to have at least two white balls

11 2 cents is enough some of the time
3 cents is always enough

12 Puzzles old square tiles new rectangular tiles

13

14

15 21 red squares 19 white squares You can cover 38 of the 40 squares But there will always be 2 red squares left over You need to cut one of the rectangular tiles in half…

16 Hexaflexagons B A C C A B z
A flexible hexagon made from a long strip of paper folded into triangles You can “flex” the hexagon to show different faces Discovered in 1939 by Arthur Stone ( ) when he was a grad student at Princeton contributions by Bryant Tuckerman ( ), John Tukey ( ), Richard Feynman ( ) [the “Flexagon Committee”] B A C C A B z Example: a tri- hexaflexagon 3 faces Each face has 6 triangles

17 7 Steps to fold a tri-hexaflexagon
z B B Step 1. Start with a strip of 10 equilateral triangles. Fold both ways on all of the lines C A C B A C A C

18 C A B z y Step 2. Fold 3 triangles on the left towards the back x
fold back

19 C A B x Step 3. Fold over one triangle towards the front y
fold to the front C A B x Step 3. Fold over one triangle towards the front y

20 A C B Step 4. Fold the 4 right triangles towards the front y x
fold to the front Step 4. Fold the 4 right triangles towards the front y x Caution: Don’t fold towards the back… if you folded it the wrong way, your flexagon will look like this:

21 A B y Step 5. Re-open the one triangle that was folded over in step 3
re-open one triangle x

22 y A B Step 6. Put glue on the top 2 triangles glue x

23 A B x Step 7. Fold down the top triangle – done! y Front view
Back view

24 Flexing a tri-hexaflexagon

25 Hexaflexagons There is also a hexahexaflexagon: start with a strip of 19 equilateral triangles Fold it into a coil Then fold back the right-most 3 triangles; fold forward the left-most 4 triangles

26 Puzzles and mathematical games
It didn’t start with Martin Gardner… W. W. Rouse Ball ( ) Sam Loyd ( ) And the tradition goes on… Ian Stewart (1945- ) A. K. Dewdney (1941- ) Dennis Shasha () Simon Singh (1964- ) Chris Maslanka (1956- ) Will Shortz (1952- ) Keith Devlin (1947- ) Jordan Ellenberg (1971- )

27 Tri-hexaflexagon template
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