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Chapters 5 and 19
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Energy = capacity to do work Kinetic = energy of motion Potential = energy of position relative to other objects Work = energy used to cause an object with mass to move against a force Force = push or pull exerted on an object Heat = energy used to cause temp. to increase
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F = the electric force between 2 charged objects k = Coulomb’s constant = 8.99 x 10 9 J-m/C 2 Q 1 and Q 2 are the electrical charges r is the distance of separation between the two objects
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System = portion singled out for study Open Closed Isolated Surroundings = everything else
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Work is energy used to cause an object to move against a force w = F x d [Eq. 5.3] Heat is energy transferred from a hotter object to a colder one
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Energy is conserved. Internal energy Sum of all kinetic and potential energies of the system’s components Change in energy is what we can know E = E final – E initial Magnitude of the change is important Direction of change is important (+ or -)
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Shows the direction and magnitude of the energy change for a chemical reaction
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E is positive when energy is added to the system and negative when energy exits E = q + w (q is heat and w is work) Endothermic System absorbs heat Exothermic System releases heat
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Depends only on the present state of the system, and not the path it took to get there Energy of a system Final
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P-V work = pressure-volume work, which is involved in the expansion or compression of gases w = -P V Enthalpy = heat flow in processes @ constant P where no other work is done except P-V work Internal energy + P*V H = E + P V Change in enthalpy = heat gained/lost @ constant P
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Enthalpy change that accompanies a reaction Heat of reaction ( H rxn ) H = H products – H reactants
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1. Enthalpy is an extensive property. 1. Directly proportional to the amount of reactant consumed in the reaction. 2. Enthalpy change for a rxn is equal in magnitude but opposite in sign to H for the reverse rxn. 3. The enthalpy change for a rxn depends on the state of the reactants and products.
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H 2 O (s) H 2 O (l) H = 6.01 kJ The stoichiometric coefficients always refer to the number of moles of a substance Thermochemical Equations: show enthalpy changes as well as the mass relationships If you reverse a reaction, the sign of H changes H 2 O (l) H 2 O (s) H = - 6.01 kJ If you multiply both sides of the equation by a factor n, then H must change by the same factor n. 2H 2 O (s) 2H 2 O (l) H = 2 x 6.01 = 12.0 kJ
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H 2 O (s) H 2 O (l) H = 6.01 kJ The physical states of all reactants and products must be specified in thermochemical equations. Thermochemical Equations H 2 O (l) H 2 O (g) H = 44.0 kJ How much heat is evolved when 266 g of white phosphorus (P 4 ) burn in air? P 4 (s) + 5O 2 (g) P 4 O 10 (s) H = -3013 kJ 266 g P 4 1 mol P 4 123.9 g P 4 x -3013 kJ 1 mol P 4 x = -6470 kJ
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Hydrogen peroxide can decompose to water and oxygen by the following reaction: 2H 2 O 2 (l) → 2H 2 O (l) + O 2 (g) H = -196 kJ Calculate the value of q when 5.00 g of hydrogen peroxide decomposes at constant pressure.
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Measurement of heat flow Calorimeter = device used to measure magnitude of temp. change that the heat flow produces Heat capacity = C = amount of heat required to raise the temp. by 1K (or 1°C). Extensive property; units are J/K or J/°C
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Molar heat capacity (C m )= heat capacity of one mole of a substance Specific heat (C s )= heat capacity of one gram of a substance Intensive property q = m * C s * T
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How much heat is given off when an 869 g iron bar cools from 94 0 C to 5 0 C? C s of Fe = 0.444 J/g 0 C t = t final – t initial = 5 0 C – 94 0 C = -89 0 C q = m*Cs* t = 869 g *0.444 J/g 0 C * –89 0 C= -34,000 J
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Large beds of rocks are used in some solar- heated homes to store heat. Assume that the specific heat of the rocks is 0.82 J/g-K. Calculate the temperature change 50.0 kg of rocks would undergo if they emitted 450. kJ of heat.
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Coffee cup calorimeter Pressure of the system = atmospheric pressure Assume that the calorimeter contains all heat generated in the reaction Use q = m*C s * T H = q rxn No heat enters or leaves!
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When 50.0 mL of 0.100 M silver nitrate and 50.0 mL of 0.100 M hydrochloric acid are mixed in a constant- pressure calorimeter, the temperature of the mixture increases from 22.30°C to 23.11°C. The temperature increase is caused by the following reaction: AgNO 3 (aq) + HCl (aq) → AgCl (s) + HNO 3 (aq) Calculate H for this reaction in kJ/mol AgNO 3, assuming that the combined solution has a mass of 100.0 g and a specific heat of 4.18 J/g-°C.
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Bomb calorimetry Bomb calorimeter = used to study combustion reactions q rxn = -C cal * T
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Constant-Volume Calorimetry No heat enters or leaves! q sys = q water + q bomb + q rxn q sys = 0 q rxn = - (q water + q bomb ) q water = m x C s x t q bomb = C bomb x t Reaction at Constant V H ~ q rxn H = q rxn Measured in a constant-volume bomb calorimeter
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A 0.5865-g sample of lactic acid (HC 3 H 5 O 3 ) is burned in a calorimeter whose heat capacity is 4.812 kJ/°C. The temperature increases from 23.10°C to 24.95°C. Calculate the heat of combustion of lactic acid (a) per gram and (b) per mole.
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