1. Quiz Thursday (Algebra range – pages 158-197 excluding 182-183 and starred problems)

2. Quiz Review Practice Solve the equations

3. Quiz Review

4. 3(x + 1) = 2(x + 1) + x 3x + 3 = 2x + 2 + x 3x + 3 = 3x + 2 3 = 2 x NS

5. 3(x + 1) – x = 2(x + 1) + 1 3x + 3 - x = 2x + 2 + 1 2x + 3 = 2x + 3 3 = 3 o IMS

7. Define a variable or use a table or diagram, write an equation and solve it. Make sure to answer the question. Some of the answers may be fractions. 5.The perimeter ( 둘레 ) of a triangle is 51 centimeters. The lengths of its sides are consecutive odd integers. Find the lengths of all three sides. 6. A plane leaves an airport and flies north at a speed of 250 km per hour. A jet leaves the same airport 30 minutes (0.5 hours) later on the same path at 375 km per hour. How long does it take the jet to catch up to the plane. (Same direction travel)

8. 7. A plane travels from Seoul to Taiwan at 600 km per hour. The same plane travels from Taiwan to Seoul at 450 km per hour. The flying time to Taiwan is 1 hour less than the flying time to Seoul. How far apart are the two cities. (Round Trip Travel) 8. Two trains starts at the same time from towns that are 564 km apart and meet in 6 hours. The average speed of one train was 14 km per hour faster than the other. Find the speed of each train. (Opposite Direction Travel)

9. # 5 6 SpeedTimedistance Small plane 250 km/ht + 0.5250t + 125 jet375 km/ht375t 250t + 125 = 375t 125t = 125 t=1 1 hour Let x = an odd integer x + (x+2) + (x+4) = 51 3x + 6 = 51 3x = 45 x = 15 15, 17, 19

10. #7 #8 SpeedTimeDistance To Taiwan600t-1600(t-1) To Seoul450t450t 600t – 600 = 450t 150t = 600 t = 4 Distance 1800 km Total distance = 564 km distance = speed x time x = speed of one train speed x time + speed x time = distance ( x )( 6 ) + ( x + 14 ) ( 6 ) = 564 6x + 6x + 84 = 564 12x = 480 x = 40 Speeds are 40 and 54 km / h 6 x 6(x+14)

11. To Study for the Quiz! Practice problems on pages 167-168 170-173 Review types of problems 174-179 184-196

13. Page 171

14. Page 172

15. Page 173

16. 184 # 1 SpeedTimeDIstance Bus at 50 km per hour506300 Bus at 45 km ph45X45x

17. Page 184 #2 SpeedTimeDistance To Everland40t40t Back from Everland 905-t90(5-t)

18. Page 184 #3 SpeedTimeDistance To town40t40t Back from town 307-t30(7-t) 40t = 210-30t 70t = 210 t = 3 Distance 120 each way 240 km total distance

19. Page 185 #4 SpeedTimeDistance Commercial Jet s+1201620 miles Corporate Jet s1260 The speed of the Commercial Jet is 540 m/h and the speed of the corporate jet is 420 m/h

20. Page 185 # 5 SpeedTimeDistance cars32 plane9s576 The speed of the plane is 288 km/h

21. Page 185 # 6 SpeedTimedistance Juhyeon3 Himchan6t6t

22. Page 186 # 7 SpeedTimedistance Helicopter180 180t + 60 Plane330t330t

23. Page 186 # 8 SpeedTimedistance Small plane250 km/ht + 0.5250t + 125 jet375 km/ht375t 250t + 125 = 375t 125t = 125 t=1 1 hour

24. Page 186 # 9 SpeedTimedistance 유리 60t60t 범영 75t-275(t-2) 60t=75(t-2) 60t = 75t -150 15t = 150 t= 10 8 hours

25. Page 187 # 10 - 11

26. Page 187 #12 SpeedTimedistance To Seoul75t75t TO Home50t+150(t+1) 75t = 50t+50 25t = 50 t=2 3 hours to drive home

27. Page 188-189 #13-17

28. Page 189 # 18 distance = speed x time x = speed of one train speed x time + speed x time = distance ( x )( 6 ) + ( x + 14 ) ( 6 ) = 564 6x + 6x + 84 = 564 12x = 480 x = 40 Speeds are 40 and 54 km / h Total distance = 564 km

29. Page 190 #19 4(s - 8) 4s 4(s-8) + 4s = 608 8s -32 = 608 8s = 640 S = 80 80 and 72 km/h

30. Page 190-191 # 20-23 20)48 km per hour 21) 40 km per hour 22) 18.5 km/h and 37.5 km/h 23) 51 km/h and 45 km/h 24) starred problem – not learned yet!

31. page 192 #25 Let x = an integer Let x+1 = 1 st consecutive integer x+(x+1)=45 2x=44 x=22 x+1=23 22,23 22+23=45 45=45 

32. Page 192 # 26 Let x= even integer Let x+2=1 st consecutive even integer Let x+4=2 nd consecutive even integer x+(x+2)+(x+4)=72 3x+6=72 3x=66 x=22 22,24,26 22+24+26=72 72=72 

33. Page 192-194 27) -45, -43 28) 11, 13, 15, 17 29) 20, 22 30) 24, 25, 26 31) 3 32) -7 33) 10, 40 34) 25, 55 35) 4.5 inches x 7.5 inches 36) 20, 80, 80 37) 15, 17, 19 38) 0

34. Page 195 # 39 SpeedTimedistance To Beach55t55t Return6512-t65(12-t) 55t = 65(12-t) 55t = 780 – 65t 120t = 780 t=6.5 Distance to the resort is 357.5 miles

35. Page195 # 40-41 Not learned yet

36. Page 196 # 42 16t 12t 16t + 12t = 42 28t = 42 t = 1.5 1.5 hours

37. Pages 196 – 197 # 43,45 43)Car 68 mph, Bus 34 mph 44) next slide 45)2 hours at 105 mph, 3 hours at 115 mph

38. Page 196 # 44 SpeedTimedistance To city150t150t Back from city1005-t100(5-t) 150t = 100(5-t) 150t = 500 – 100t 250t = 500 t = 2 Distance = 300 miles