1. Warm Up
1. What is the third angle measure in a triangle with angles measuring 65° and 43°?
Find each value. Round trigonometric
ratios to the nearest hundredth and angle measures to the nearest degree.
2. sin 73° 3. cos 18° 4. tan 82°
5. sin-1 (0.34) 6. cos-1 (0.63) 7. tan-1 (2.75)
72°
0.96
0.95
7.12
20°
51°
70°

2. Objective
Use the Law of Sines and the Law of Cosines to solve triangles.

3. In this lesson, you will learn to solve any triangle.
To do so, you will need to calculate trigonometric
ratios for angle measures up to 180°. You can use a calculator to find these values.

4. Example 1: Finding Trigonometric Ratios for Obtuse Angles
Use your calculator to find each trigonometric ratio. Round to the nearest hundredth.
A. tan 103°
B. cos 165°
C. sin 93°
tan 103°  –4.33
cos 165°  –0.97
sin 93°  1.00

5. Check It Out! Example 1
Use a calculator to find each trigonometric ratio. Round to the nearest hundredth.
a. tan 175°
b. cos 92°
c. sin 160°
tan 175°  –0.09
cos 92°  –0.03
sin 160°  0.34

6. You can use the altitude of a triangle to find a relationship between the triangle’s side lengths.
In ∆ABC, let h represent the length of the altitude from C to
From the diagram, , and
By solving for h, you find that h = b sin A and h = a sin B. So b sin A = a sin B, and
You can use another altitude to show that these ratios equal

7. You can use the Law of Sines to solve a triangle if you are given
• two angle measures and any side length
(ASA or AAS) or
• two side lengths and a non-included angle measure (SSA).

8. Example 2A: Using the Law of Sines
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. FG
Law of Sines
Substitute the given values.
FG sin 39° = 40 sin 32°
Cross Products Property
Divide both sides by sin 39.

9. Example 2B: Using the Law of Sines
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mQ
Law of Sines
Substitute the given values.
Multiply both sides by 6.
Use the inverse sine function to find mQ.

10. Check It Out! Example 2a
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. NP
Law of Sines
Substitute the given values.
NP sin 39° = 22 sin 88°
Cross Products Property
Divide both sides by sin 39°.

11. Check It Out! Example 2b
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mL
Law of Sines
Substitute the given values.
Cross Products Property
10 sin L = 6 sin 125°
Use the inverse sine function to find mL.

12. Check It Out! Example 2c
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mX
Law of Sines
Substitute the given values.
7.6 sin X = 4.3 sin 50°
Cross Products Property
Use the inverse sine function to find mX.

13. Check It Out! Example 2d
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. AC
mA + mB + mC = 180°
Prop of ∆.
mA + 67° + 44° = 180°
Substitute the given values.
mA = 69°
Simplify.

14. Check It Out! Example 2D Continued
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
Law of Sines
Substitute the given values.
AC sin 69° = 18 sin 67°
Cross Products Property
Divide both sides by sin 69°.

15. The Law of Sines cannot be used to solve every triangle
The Law of Sines cannot be used to solve every triangle. If you know two side lengths and the included angle measure or if you know all three side lengths, you cannot use the Law of Sines. Instead, you can apply the Law of Cosines.

16. You can use the Law of Cosines to solve a triangle if you are given
• two side lengths and the included angle measure (SAS) or
• three side lengths (SSS).

17. The angle referenced in the Law of Cosines is across the equal sign from its corresponding side.
Helpful Hint

18. Example 3A: Using the Law of Cosines
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. XZ
XZ2 = XY2 + YZ2 – 2(XY)(YZ)cos Y
Law of Cosines
Substitute the given values.
= – 2(35)(30)cos 110°
XZ2 
Simplify.
Find the square root of both sides.
XZ  53.3

19. Example 3B: Using the Law of Cosines
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mT
RS2 = RT2 + ST2 – 2(RT)(ST)cos T
Law of Cosines
Substitute the given values.
72 = – 2(13)(11)cos T
49 = 290 – 286 cosT
Simplify.
Subtract 290 both sides.
–241 = –286 cosT

20. Example 3B Continued
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mT
–241 = –286 cosT
Solve for cosT.
Use the inverse cosine function to find mT.

21. Check It Out! Example 3a
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. DE
DE2 = EF2 + DF2 – 2(EF)(DF)cos F
Law of Cosines
Substitute the given values.
= – 2(18)(16)cos 21°
DE2 
Simplify.
Find the square root of both sides.
DE  6.5

22. Check It Out! Example 3b
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mK
JL2 = LK2 + KJ2 – 2(LK)(KJ)cos K
Law of Cosines
Substitute the given values.
82 = – 2(15)(10)cos K
64 = 325 – 300 cosK
Simplify.
Subtract 325 both sides.
–261 = –300 cosK

23. Check It Out! Example 3b Continued
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mK
–261 = –300 cosK
Solve for cosK.
Use the inverse cosine function to find mK.

24. Check It Out! Example 3c
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree. YZ
YZ2 = XY2 + XZ2 – 2(XY)(XZ)cos X
Law of Cosines
Substitute the given values.
= – 2(10)(4)cos 34°
YZ2 
Simplify.
Find the square root of both sides.
YZ  7.0

25. Check It Out! Example 3d
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mR
PQ2 = PR2 + RQ2 – 2(PR)(RQ)cos R
Law of Cosines
Substitute the given values.
9.62 = – 2(5.9)(10.5)cos R
92.16 = – 123.9cosR
Simplify.
Subtract both sides.
–52.9 = –123.9 cosR

26. Check It Out! Example 3d Continued
Find the measure. Round lengths to the nearest tenth and angle measures to the nearest degree.
mR
–52.9 = –123.9 cosR
Solve for cosR.
Use the inverse cosine function to find mR.

27. Do not round your answer until the final step of the computation
Do not round your answer until the final step of the computation. If a problem has multiple steps, store the calculated answers to each part in your calculator.
Helpful Hint

28. Example 4: Sailing Application
A sailing club has planned a triangular racecourse, as shown in the diagram. How long is the leg of the race along BC? How many degrees must competitors turn at point C? Round the length to the nearest tenth and the angle measure to the nearest degree.

29. Example 4 Continued
Step 1 Find BC.
BC2 = AB2 + AC2 – 2(AB)(AC)cos A
Law of Cosines
Substitute the given values.
= – 2(3.9)(3.1)cos 45°
Simplify.
BC2 
Find the square root of both sides.
BC  2.8 mi

30. Example 4 Continued
Step 2 Find the measure of the angle through which competitors must turn. This is mC.
Law of Sines
Substitute the given values.
Multiply both sides by 3.9.
Use the inverse sine function to find mC.

31. Check It Out! Example 4
What if…? Another engineer suggested using a cable attached from the top of the tower to a point 31 m from the base. How long would this cable be, and what angle would it make with the ground? Round the length to the nearest tenth and the angle measure to the nearest degree.
31 m

32. Check It Out! Example 4 Continued
Step 1 Find the length of the cable.
AC2 = AB2 + BC2 – 2(AB)(BC)cos B
Law of Cosines
Substitute the given values.
= – 2(31)(56)cos 100°
Simplify.
AC2 
Find the square root of both sides.
AC 68.6 m

33. Check It Out! Example 4 Continued
Step 2 Find the measure of the angle the cable would make with the ground.
Law of Sines
Substitute the given values.
Multiply both sides by 56.
Use the inverse sine function to find mA.