1. Stoichiometry

2. Stoichiometry
Stoy – key – ohm – e - tree

3. 9.1 Introduction to Stoichiometry
1. Define Stoichiometry.
2. Describe the importance of the mole ratio in stoichiometric calculations.
3. Write a mole ratio relating two substances in a chemical equation.
4. Calculate the amount in moles of a reactant or product from the amount in moles of a different reactant or product.

4. Obj 1: What is Stoichiometry?
Stoichiometry means
Stoicheio = element
Metron = measure
Stoichiometry is the quantitative study of chemical reactions using balanced equations.

5. Obj 2: Mole Ratio
Mole Ratios come from the coefficients in a balanced equation.
Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

6. Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3
The Possible Mole Ratios are:

7. Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3
The Possible Mole Ratios are:
1 mol N mol N mol H2
3 mol H mol NH3 2 mol NH3

8. Obj 3: Mole Ratios from Balanced Equations
1 N H2  2 NH3
Other Possible Mole Ratios:
1 mol N mol N mol H2
3 mol H mol NH3 2 mol NH3
3 mol H mol NH3 2 mol NH3
1 mol N mol N mol H2

9. Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3

10. Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3
7.5 mol N2 (3 mol H2 ) = ?
(1 mol N2 )

11. Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N ? mol H ? mol NH3
7.5 mol N2 (3 mol H2 ) = 22.5 mol H2
(1 mol N2 )

12. Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N mol H ? mol NH3
7.5 mol N2 (2 mol NH3) = ?
(1 mol N2 )

13. Obj 4: Using a Mole Ratio 1 N2 + 3 H2  2 NH3
7.5 mol N mol H ? mol NH3
7.5 mol N2 (2 mol NH3) = mol NH3
(1 mol N2 )

14. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: _ N _ H2  _ NH3

15. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: 2 N H2  4 NH3

16. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: 2 N H2  4 NH3
Triple Batch: _ N _ H2  _ NH3

17. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: 2 N H2  4 NH3
Triple Batch: N H2  6 NH3

18. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: 2 N H2  4 NH3
Triple Batch: N H2  6 NH3
Half Batch: _ N _ H2  _ NH3

19. Obj 4: Cookie Stiochiometry
One Batch: N H2  2 NH3
Double Batch: 2 N H2  4 NH3
Triple Batch: N H2  6 NH3
Half Batch: N H2  1 NH3

20. Lets Look at Our Problem Again We want 7.5 batch !
1 N H2  2 NH3
__ mol N ___ mol H2 __ mol NH3

21. Lets Look at Our Problem Again We want 7.5 batch !
1 N H2  2 NH3
7.5 mol N mol H mol NH3

22. The End
The Final Curtain