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Published byBeatrix Wheeler Modified over 9 years ago
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RC Circuits
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We can use a resistor to slow the charging of the capacitor. -Current now varies with time. -In the very short term, you can treat the capacitor like a wire. R = 0 -In the long term, you can treat the capacitor like a break. R = Infinite Charge on capacitor varies with time: q = q o [1- e -t/RC ] V R C
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How much charge is on the capacitor after 1ms? V = 20V R = 100Ω C= 10μF
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How long does it take to gain 50% of maximum Charge? V = 20V R = 100Ω C= 10μF
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How long does it take to gain 100% of maximum Charge? V = 20V R = 100Ω C= 10μF
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We can use a resistor to slow the discharging of the capacitor. -Current varies with time. -The capacitor is now driving the current -As the capacitor discharges, the voltage drops - V C = V R Charge on capacitor varies with time: q = q o [ e -t/RC ] R C (charged)
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How much charge is left on the capacitor after 1ms? V = 20V R = 100Ω C= 10μF
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How long does it take to lose 70% of maximum Charge? V = 20V R = 100Ω C= 10μF
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What is the current through the battery in very short term? What is the current through the battery in the long term? V =20V R 2 = 10 Ω C = 2μF R 1 = 5 Ω
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After a long time, what is the voltage drop across the Capacitor? V =20V R 2 = 10 Ω C = 2μF R 1 = 5 Ω
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