Presentation is loading. Please wait.

Presentation is loading. Please wait.

Addressing IP v4 W.Lilakiatsakun.

Similar presentations


Presentation on theme: "Addressing IP v4 W.Lilakiatsakun."— Presentation transcript:

1 Addressing IP v4 W.Lilakiatsakun

2 Anatomy of IPv4 (1) Dotted Decimal Address Network Address
Host Address

3 Anatomy of IPv4 (2) Octet 32 Bit Address

4 Binary to Decimal Conversion (1)

5 Binary to Decimal Conversion (2)

6 Decimal to Binary Conversion (1)

7 Decimal to Binary Conversion (2)

8 Decimal to Binary Conversion (3)

9 Type of IPv4 Address-Network Address

10 Type of IPv4 Address – Broadcast Address

11 Type of IPv4 Address – Host Address

12 Netmask (1) To identify the bit for the same position in the IP address whether it is Network bit or Host bit If the value of Netmask is 1 is the Network bit 0 is the Host bit Example : IP address – Netmask Network bit = the most 24 significant bits Host bit = the least 8 significant bits

13 Netmask (2) Netmask can be represented as “prefix” (slash format)
The number of 1 is counted Netmask is = /24 255 = (8 bits) We can find Network Address (Network ID) from IP Address Network Address = IP adresss & Netmask

14 Netmask (3) Logic AND (&) As a result, X & 0 – 0 X & 1 – X
0 & 0 – 0 0 & 1 – 0 1 & 0 – 0 1 & 1 – 1 As a result, X & 0 – 0 X & 1 – X Logic OR (|) 0 & 0 – 0 0 & 1 – 1 1 & 0 – 1 1 & 1 – 1 As a result, X | 1 – 1 X | 0 – X

15 Network Address = IP address & Netmask
Example: IP address /28 Network Address = IP address & Netmask & Question: IP address = /22 Network ID = ?

16 Netmask (5)

17 Network Address & Broadcast Address
Network ID = IP address that all host bits are 0s /24 Network ID = Broadcast ID = IP address that all host bits are 1s Broadcast ID =

18 Different Prefixes (1)

19 Different Prefixes (2)

20 Assigning Addresses

21 Calculating Addresses

22 Quiz

23 Basic Subnetting (1)

24 Basic Subnetting (2)

25 Basic Subnetting (3)

26 Basic Subnetting (4)

27 Basic Subnetting (5)

28 Basic Subnetting (6)

29 VLSM (Subnetting a subnet)

30 Problem This scenario has the following requirements:
IP address : /24 AtlantaHQ 58 host addresses PerthHQ 26 host addresses SydneyHQ 10 host addresses CorpusHQ 10 host addresses WAN links 2 host addresses (3 Links)

31 Answer

32

33

34


Download ppt "Addressing IP v4 W.Lilakiatsakun."

Similar presentations


Ads by Google