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Final 2004 Presidential Election Gallup Poll Rhajiv Ratnatunga STATS 1000 Seminar 21
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Polls are used by politicians and their supporters to gauge their likely election day performance.
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Gallup Statistical Model “President Bush held a 49-47 edge over Sen. John Kerry when the undecided voters were not allocated to a particular candidate. When Gallup, using a statistical model that assumes that 9 of 10 of those voters would support Kerry, allocated the voters, the poll ended as a dead heat with each candidate garnering 49%.” What does this mean? This was the estimate
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95% Confidence Interval for Unknown Population Proportion Estimate +/- margin of error = sample proportion +/- 2 standard deviations almost = to sample proportion +/- 2 standard errors = p hat +/- 2 sqrt ((p hat (1-p hat))/n) Explain the multiplier The standard error
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Since the population proportion is unknown….. The test for normal approximation is revised by…. Replacing the population proportion with the sample proportion np becomes np(hat) and n(1-p) becomes n(1-p(hat)) Since n is big, we can say without doing calculations that both tests will be larger than 10
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Kerry/ Edwards Bush/ Cheney Nader/ Camejo Other (vol.) None (vol.) No opini on Likely Voters 2004 Oct 29-31 ^†4749*1*3 Final Allocated Estimate 49 11-- “Results based on likely voters are based on the subsample of 1,573 survey respondents deemed most likely to vote in the November 2004 General Election, according to a series of questions measuring current voting intentions and past voting behavior. For results based on the total sample of likely voters, one can say with 95% confidence that the margin of sampling error is ±3 percentage points.”
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.47 + 2 *sqroot ((.47(1-.47))/1573) =.495 = 50% John Kerry -.47 - 2 *sqroot ((.47(1-.47))/1573) =.444 = 44% (44%,50%) = Confidence interval for Kerry.49 + 2 *sqroot ((.49(1-.49))/1573) =.515 = 52% George Bush.49 - 2 *sqroot ((.49(1-.49))/1573) =.444 =.46% (46%, 52%) = Confidence interval for Kerry
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The margin of error given was accurate.
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