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Similar Right Triangles 1. When we use a mirror to view the top of something…….

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Presentation on theme: "Similar Right Triangles 1. When we use a mirror to view the top of something……."— Presentation transcript:

1 Similar Right Triangles 1. When we use a mirror to view the top of something…….

2 Similar Right Triangles 1. When we use a mirror to view the top of something……. Eddie places a mirror 500 meters from a large Iron structure (mirror)

3 Similar Right Triangles 1. When we use a mirror to view the top of something……. Eddie places a mirror 500 meters from a large Iron structure (mirror) His eyes are 1.8 meters above the ground

4 Similar Right Triangles 1. When we use a mirror to view the top of something……. Eddie places a mirror 500 meters from a large Iron structure (mirror) His eyes are 1.8 meters above the ground He stands 2.75 meters behind the mirror and sees the top

5 Similar Right Triangles 1. When we use a mirror to view the top of something……. Eddie places a mirror 500 meters from a large Iron structure His eyes are 1.8 meters above the ground He stands 2.75 meters behind the mirror and sees the top x 500 m2.75 m 1.8 m

6 Similar Right Triangles The triangles are similar by Angle-Angle (AA) Since the triangles are similar……. x 1.8 x 500 m 1.8 m 500 2.75 = 2.75 m

7 Similar Right Triangles The triangles are similar by Angle-Angle (AA) Since the triangles are similar……. x 1.8 x = 500 1.8 2.75 x 500 m 1.8 m 500 2.75 =. 2.75 m

8 Similar Right Triangles The triangles are similar by Angle-Angle (AA) Since the triangles are similar……. x 1.8 x = 500 1.8 2.75 x 500 m 1.8 m 500 2.75 =. x = 328 m 2.75 m

9 Similar Right Triangles The triangles are similar by Angle-Angle (AA) But since the triangles are similar we could equally say… x 500 x = 500 1.8 2.75 x 500 m 1.8 m 1.8 2.75 =. x = 328 m 2.75 m

10 Similar Right Triangles 2. Now try another one……….. At a certain time of day, a lighthouse casts a 200 meter shadow

11 Similar Right Triangles 2. Now try another one……….. At a certain time of day, a lighthouse casts a 200 meter shadow At the same time Eddie casts A 3.1 meter shadow.

12 Similar Right Triangles 2. Now try another one……….. At a certain time of day, a lighthouse casts a 200 meter shadow His head is 1.9 meters above the ground At the same time Eddie casts A 3.1 meter shadow. How high is the Lighthouse?

13 Similar Right Triangles 2. Now try another one……….. At a certain time of day, a lighthouse casts a 200 meter shadow His head is 1.9 meters above the ground At the same time Eddie casts A 3.1 meter shadow. How high is the Lighthouse? 200 m 3.1 m 1.9 m x

14 Similar Right Triangles 200 m 3.1 m 1.9 m x 1.9 x = 200 1.9 3.1 x 200 3.1 =. x = 123 m The triangles are similar by Angle-Angle (AA)

15 Section 10-3: Theorem 10 - 3: “The altitude to the hypotenuse of a right triangle divides the triangle into two triangles that are similar to the original and each other”

16 Section 10-3: Theorem 10 - 3: “The altitude to the hypotenuse of a right triangle divides the triangle into two triangles that are similar to the original and each other” A B C D

17

18 A BC D D A B D B C ΔABC ~ ΔADB ~ ΔBDC

19 A BC D D A B D B C Similar Triangles, so……. AD BD BD CD = ΔABC ~ ΔADB ~ ΔADC

20 A BC D D A B D B C BD is the geometric mean of AD and CD COROLLARY 1 AD BD BD CD =

21 The altitude to the hypotenuse of ΔABC is 4 cm If the distance AD is 2 cm, find the distance CD. Corollary 1: The altitude to the hypotenuse is the geometric mean of the two sections it splits the hypotenuse into A B C D

22 The altitude to the hypotenuse of ΔABC is 4 cm If the distance AD is 2 cm, find the distance CD.. x = 4 4 Corollary 1: The altitude to the hypotenuse is the geometric mean of the two sections it splits the hypotenuse into A B C D 4 cm 2 cm x 4 4 2 = x cm 2.

23 The altitude to the hypotenuse of ΔABC is 4 cm If the distance AD is 2 cm, find the distance CD.. x = 4 4. x = 8 cm Corollary 1: The altitude to the hypotenuse is the geometric mean of the two sections it splits the hypotenuse into A B C D 4 cm 2 cm x 4 4 2 = x cm 2.

24 The altitude to the hypotenuse of ΔABC cuts AC into sections that are 4 cm long and 5 cm long Find the area of ΔABC Corollary 1: The altitude to the hypotenuse is the geometric mean of the two sections it splits the hypotenuse into A B C D

25 A BC D D A B D B C ΔABC ~ ΔADB ~ ΔBDC COROLLARY 2 AC BC BC CD AND AC AB AB AD D B =

26 The altitude to the hypotenuse of ΔABC cuts AC into sections that are 3 cm long and 6 cm long Find the length of the legs AB and BC. Corollary 2: Each leg of the large triangle is the geometric mean of the hypotenuse and the adjacent segment of hypotenuse A B C D

27 Find the length of the legs AB and BC. Hypotenuse, AC = 9 cm Corollary 2: Each leg of the large triangle is the geometric mean of the hypotenuse and the adjacent segment of hypotenuse A B C D 3 cm6 cm x y

28 Find the length of the legs AB and BC. Hypotenuse, AC = 9 cm Corollary 2: Each leg of the large triangle is the geometric mean of the hypotenuse and the adjacent segment of hypotenuse A B C D 3 cm6 cm x y

29 Find the length of the legs AB and BC. Hypotenuse, AC = 9 cm Corollary 2: Each leg of the large triangle is the geometric mean of the hypotenuse and the adjacent segment of hypotenuse A B C D 3 cm6 cm x y


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