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Lecture Three Chapters Two and three Photo slides from Digital Image Processing, Gonzalez and Woods, Copyright 2002
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Chapter 2: Digital Image Fundamentals
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Functional Represenation of Images Two-D function f(x,y), (x,y) pixel position. Postive and bounded Written as f(x,y)=i(x,y)r(x,y), i(x,y) illumination from light source, r(x,y) reflectance (bounded between 0 and 1) based on material properties. E.g r(x,y)=0.01 for black velvet, r(x,y) = 0.93 for snow. Intensity of monochrome image f(x,y) is synonymous with grey levels. By convention grey level are from 0 to L-1.
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Chapter 2: Digital Image Fundamentals
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Spatial and Gray Level Resolution Spatial resolution is the smallest level of detail discernable in an image. Number of line pairs per millimeter, say 100 line pairs per millimeter. Gray-level resolution is the smallest discernable change in gray level. Very subjective.
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Chapter 2: Digital Image Fundamentals
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Adjacency and Connectivity Adjacency- Two pixels p and q are adjacent if q is in N(p) where N(p) is the neighborhood of p and they have closely related pixel values. Three common definitions of neighborhood are (1) 4-adjacency. If p=(x,y), values are similar, but q is either (x-1,y),(x+1,y),(x,y-1),(x,y+1) (2) 8-adjacency. It is possible for q to be one of the diagonal points (x-1,y-1),(x-1,y+1),(x+1,y-1),(x+1,x+1). (3) m-adjacency. Either q is 4-adjacent to p, or q is a diagonal point and the intersection of the four neighborhood of p and that of q have no similar pixel values.
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 2: Digital Image Fundamentals
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Adjacency,More Formally Choose a set of gray values V. If f(p) and f(q) are in V, and q is in the right kind of neighborhood of p, then p and q are adjacent. I can model this relationship using 0-1 images, why??
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Chapter Three Image Enhancement in Spatial Domain Find gray level transfomration function T(r) to obtain g(x,y) =T(f(x,y)) processed image from input image. Reasons 1.Contrast enhancement 2.Visual improvement 3.Image understanding
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Negatives Here T(r) = L-1-r L-1 maximum gray level Produces photographic negative. Some details are easier to spot if we go from black and white to white and black.
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Mammogram Notice that the white or gray detail in the dark region is more visible in the negative. This shows a small lesion.
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Log Transformation T(r) = c log(1+s) Inverse Log T(r) = exp(r/c)-1 For the next picture, c=1. Used to display Fourier spectra.
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Power Law or Gamma Transformations This the gamma correction
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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CRT Example CRT devices have intensity to value response functions that are power functions. They vary in exponents from 1.8 to 2.5. A logical transformation is
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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MRI of Fractured Spine Transformation is With gamma = 0.6,0.4,0.3
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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Chapter 3 Image Enhancement in the Spatial Domain Chapter 3 Image Enhancement in the Spatial Domain
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