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Published byAshley Ball Modified over 9 years ago
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Solar Hot Water Heater
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Flat Plate Collector Problem A flat plate solar collector is used as a solar hot water heater. The collector area equals 20 square meters. The collector is located in a location with annual average daily solar insolation equal to 5.0 kWh/square meter/day.
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1. Calculate the amount of solar energy incident on this collector each day. Solar Energy = = 5.0 kWh / sq m / day 20 sq m = 100 kWh / day
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2. Assuming that the efficiency of the solar collector and the rest of the system equals 50%, calculate the average daily energy produced (as hot water) by this system. Express your answer in kWh/day. Average Produced Energy/day = = 100 kWh / day 0.50 = 50 kWh / day
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3. Calculate the amount of energy produced by this system each year. Express your answer in kWh. Annual Energy Production = = 50 kWh/day 365 day/year = 18,000 kWh / year
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4. Assuming that the solar energy replaces the heating of hot water by electric energy and that electric energy cost 10¢/kWh, calculate the yearly savings in electricity costs as a result of using the solar hot water system. Express your answer in $/year. Money Saved = = 18,000 kWh $0.10/kWh = $1,800 / year
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5. Suppose this solar hot water system were to cost $5,400 (installed). Calculate the payback period for this system Payback = Cost / Savings = $5,400 / $1,800 /year = 3 years
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