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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-1 Developed By: Dr. Don Smith, P.E. Department of Industrial Engineering Texas A&M University College Station, Texas Executive Summary Version Chapter 5 Present Worth Analysis
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-2 LEARNING OBJECTIVES 1.Formulating alternatives 2.PW of equal-life alternatives 3.PW of different-life alternatives 4.Future worth analysis 5.Capitalized Cost 6.Payback period 7.Life cycle Cost 8.PW of Bonds 9.Spreadsheets
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-3 Sct. 5. 1 Formulating Mutually Exclusive Alternatives One of the important functions of financial management and engineering is the creation of “alternatives” If there are no alternatives to consider then there really is no problem to solve! Given a set of “feasible” alternatives, engineering economy attempts to identify the “best” economic approach to a given problem
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-4 Types of Economic Projects Mutually exclusive alternatives From a set of feasible alternatives, pick one and only one to execute Mutually exclusive alternatives compete against each other Independent projects From a set of feasible alternatives select as many as can be funded in the current period The “Do Nothing” (DN) alternative should always be considered
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-5 Cash Flow Types for Projects Revenue – each alternative generates costs and revenues over the estimated life of the project. Criteria: Select the alternative that maximizes the economic measure of merit Service – each alternative has only current and future costs over the estimated life of the project. Criteria: Select the alternative that minimizes the economic measure of merit, which is a cost-based measure
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-6 Sct 5.2 Present Worth Analysis of Equal-Life Alternatives Find PW at a stated interest rate, which is usually equal to or greater than the organization’s established MARR A process of obtaining the equivalent worth of future cash flows BACK to some point in time. – called the Present Worth Method
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-7 Present Worth Approach: Mutually Exclusive Projects Alternatives must be of equal service, that is, evaluate all alternatives over the same number of years. For a single project, project is financially viable if PW 0 at the MARR For 2 or more alternatives, select the one with the (numerically) larger PW value Examples: PW 1 PW 2 Select $-1500 $-500 Alt 2 +2500 -500 Alt 1 -1200 +25 Alt 2
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-8 PW method for independent projects Select all projects with PW 0 when the MARR is used in calculating the PW values This assumes no restriction of how much is invested during a given time period. If investment limit exists, which it usually does, use the techniques of chapter 12
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-9 Sct 5.3 Present Worth Analysis of Different-Life Alternatives For alternatives with un-equal lives the rule is: PW of the alternatives must be compared over the same number of years Called “ Equal Service ” requirement Approach – 1 of 2 approaches LCM -- Evaluate the alternatives over the lowest common multiple of lives, e.g., lives of 4 and 6, use n = 12 and assume re-investment at same cash low estimates Study period -- assume a planning horizon and evaluate the alternatives over this number of years
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-10 PW Analysis using LCM Approach Example 5.2 is a good illustration of LCM method at i = 15% per year Location A has n A = 6 years and B has n B = 9 o LCM = 18 years; determine both PW values over 18 years o Assume two re-purchases of A at the end of years 6 and 12 o Assume one re-purchase of B at end of year 9 o All cash flow estimates are assumed to continue for 18 years, including the end-of-lease ‘return deposit’ PW A = $-45,036 and PW B = $-41,384 Select location B with the (numerically) larger PW, which has the smaller equivalent PW cost
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-11 Sct 5.4 Future Worth Analysis In some applications, a future worth analysis is preferred For equal service, determine LCM of lives Find PW of each alternative Then compute FW in LCM year at the same interest rate used to find PW of each alternative For the study period approach, use the appropriate value of “n” to take cash flows forward for each alternative
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-12 Sct 5.5 Capitalized Cost Calculations and Analysis CAPITALIZED COST- Present worth of a project that lasts forever. Analysis method for: Government or public projects; Roads, dams, bridges, project that basically possess infinite life; Infinite analysis period: “n” in the problem is either very long, indefinite, or infinity.
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-13 P/A Factor as “n” approaches infinity The P/A factor is: On the right hand side, divide both numerator and denominator by (1+i) n If “n” approaches the above reduces to: Let CC represent “capitalized cost” Annual amount forever is A = Pi = (CC)i
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-14 Examples of capitalized cost analyses Example 5.4 -- Finds the CC and A values of a county government software system expected to be used for the indefinite future Example 5.5 -- Compares the CC values for 2 indefinite-life bridge designs – suspension and truss Example 5.6 -- Uses CC method to compare short life (5 year) and very long life (indefinite) alternatives
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-15 Sct 5.6 Payback Period Analysis Also call payout analysis Extension of present worth method Two forms: 1. With no interest -- i = 0% (no-return payback) 2. With an assumed interest rate -- i > 0% (discounted payback analysis) Technique: estimates the time n p to recover the initial investment in a project, either with or without interest earned
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-16 Payback Period Analysis-RULE Never use payback analysis as the primary means of making an accept/reject decision on an alternative! Best used as a screening technique or preliminary analysis tool Historically, this method was a primary analysis tool and often resulted in incorrect selections To apply, the cash flows must have at least one (+) cash flow in the sequence
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-17 Basic Formula for Payback Analysis Determine the number of years n p that it takes for all negative net cash flows to exactly equal all positive cash flows If i = 0% and all NCF estimates are the same, the payback calculation simplifies to n p = P/NCF
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-18 Payback - Interpretations and Fallacies Common managerial philosophy is that a shorter payback is preferred to a longer payback period; this is not a good approach from economic vantage Not a preferred method for final decision making – better as a screening tool Ignores all cash flows after the payback time period May not use all of the cash flows in the cash flow sequence. Refer to Example 5.7 Don’t use no-return (i = 0%) payback for final decisions. It Neglects any required return on the investment Neglects all cash flows after time n p including any positive cash flows that contribute to making a positive return on the investment
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-19 Sct 5.7 Life Cycle Costs Another extension of present worth method Applied to systems over their total estimated system life span Critical to estimate the system life span in years Difficulties – estimation of costs far removed from time t = 0 The life cycle may be defined by two main time phases
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-20 Life Cycle Concept Two main phases are: Acquisition Phase Operations Phase Many cash flow estimates are needed, thus making the analysis less reliable as the life gets longer See Example 5.9
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-21 Sct 5.8 Present Worth of Bonds Bond problems – typical present worth application Common analysis problem in the world of finance Bond is basically an “ iou ” Bond – represent “debt” financing Corporations sell bonds to raise capital Bonds pay a stated rate of interest (bond dividend) to the bond holder for a specified period of time
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-22 Bonds Parameters and Examples 1. Face value, V = $1000 2. Life of the bond, n = 30 years 3. Coupon rate, b = 8% per year, paid quarterly 4. Number of dividend payments per year, c = 4 Bond dividend = I = Vb/c I = 1000(.08)/4 = $20 per quarter
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-23 Cash Flow Profile for Bond Purchase Typical cash flow to bond buyer: 0 1 2 n-1 n // Bond Purchase, V at t = 0 Bond interest payments Repayment of the face value
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-24 Discounting a Bond Bonds are seldom purchased for their face value Most of the time a bond is “ discounted ” in the bond market by a few percentage points But the face value and the periodic dividend payments remain unchanged For example, V = $10,000 bond purchased for 98% of V now, but repays full face value, V, in 10 years
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-25 Bond Purchase: Example $5,000 10-year bond that pays 4.5% semi- annually is under consideration As the potential buyer you require a rate of return of 8% per year, compounded quarterly on your purchase What should you be willing to pay for this bond now in order to receive at least the required rate of return?
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-26 Bond Purchase: Example Draw the cash flow diagram using “6 month periods” as the unit of time Bond dividend = $5000(0.045)/2 = $112.50 every 6 months / / / 0 1 2 3 4 18 19 20 A = $112.50 $5,000 PW = ? (willing to pay) “n” is 20 since bond dividend payments are semi-annual
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-27 Bond Purchase: Example Investor requires 8% per year, compounded quarterly i/qtr = 0.8/4 = 2% per quarter Effective semiannual rate is (1.02) 2 – 1 = 4.04% per 6 months / / / 0 1 2 3 4 18 19 20 $5,000 A = $112.50 Find the PW at 4.04% of this cash flow series PW = max amount to pay for the bond
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-28 Bond Purchase: Example P = 112.50(P/A,4.04%,20) + 5000(P/F,4.04%,20) = $3788 If the bond can be purchased for $3788, or less, the investor will make the required rate of return If the bond cost more than $3788, the investment is not worth it financially
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-29 Sct 5.9 Spreadsheet Applications – PW Analysis and Payback Period Review the Excel financial functions NPV and PV functions are useful analysis tools built into Excel Refer to Example 5.12 and 5.13
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-30 Chapter Summary PW method requires comparison over same number of years – equal service comparison Alternative comparison using PW – select the alternative with the numerically larger PW value, that is, higher new positive cash flow value, or lower net cost in PW terms Extension of PW method are: capitalized cost, life- cycle costs, payback period, bonds Never use payback period as the primary selection method; only as supplemental with other methods such as PW, FW, AW or ROR (as covered in later chapters )
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Slide Sets to accompany Blank & Tarquin, Engineering Economy, 6 th Edition, 2005 © 2005 by McGraw-Hill, New York, N.Y All Rights Reserved 5-31 Chapter 5 End of Slide Set
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