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1 Thursday February 21, 2013 Chapter 17: Thermochemistry 1.Calorimeter 2.Enthalpy 3.Heat capacity 4.Heat of combustion 5.Heat of reaction 6.Law of conservation.

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Presentation on theme: "1 Thursday February 21, 2013 Chapter 17: Thermochemistry 1.Calorimeter 2.Enthalpy 3.Heat capacity 4.Heat of combustion 5.Heat of reaction 6.Law of conservation."— Presentation transcript:

1 1 Thursday February 21, 2013 Chapter 17: Thermochemistry 1.Calorimeter 2.Enthalpy 3.Heat capacity 4.Heat of combustion 5.Heat of reaction 6.Law of conservation of energy 7.Molar heat of condensation 8.Molar heat of fusion 9.Molar heat of solidification 10.Molar heat of solution 11.Specific heat 12.Standard heat of formation 13.Surroundings 14.System 15.Thermochemistry BRING TEXTBOOK TOMORROW TOO!

2 2 Wednesday February 18, 2015 Intro to Thermodynamics Q Equation EQ: How is specific heat related to conductivity? ANNOUNCEMENTS:

3 3 THERMOCHEMISTRY The study of the changes in heat in chemical reactions and physical processes.

4 4 Heat Energy HEAT is the form of energy that flows between 2 objects because of their difference in temperature. Other forms of energy — lightlight electricalelectrical kinetic and potentialkinetic and potential

5 5 Heat Transfer Heat transfers until thermal equilibrium is established.

6 6 Heat Transfer No Change in State Heat = (mass)(specific heat)(change in temperature) Q = mc  T Q: heat (joules) m: mass (grams) c: specific heat (J/g o C or J/gK)  T: change in temperature ( o C or K)

7 7 Specific Heat The amount of heat required to raise the temperature of 1 gram (or 1 kg) of a substance by 1 K (or o C)

8 8 Specific Heat

9 9 Is specific heat capacity related to heat conductivity? Iron Wood Air Aluminum Water CONDUCT OR ? INSULATO R? https://www.youtube.com/watch?v=-wj2Oh50wsA

10 10

11 11 A 15.75-g piece of iron is heated and as a result its temperature changes from 25°C to 175°C. Calculate the amount of heat absorbed by the iron. Practice Problem #1

12 12 Practice Problem #2 How much energy would be absorbed by 550 g of silver that is heated from 24 o C to 45 o C? (The specific heat of silver is 235 J/kgK)

13 13 Practice #3 25.0 g of mercury is heated from 25°C to 155°C, and absorbs 455 joules of heat in the process. Calculate the specific heat capacity of mercury.

14 14 Thursday February 19, 2015 Energy In a Cheeto Lab EQ: How much energy is stored in a cheeto? How are food calories related to heat energy? ANNOUNCEMENTS:

15 15 Heat Transfer No Change in State Heat = (mass)(specific heat)(change in temperature) Q = mc  T Q: heat (joules) m: mass (grams) c: specific heat (J/g o C or J/gK)  T: change in temperature ( o C or K)

16 16 Which has more Calories? Crunchy or Puffy Cheetos All human activity requires “burning” food for energy. How much energy is released when food burns in the body? How is the caloric content of food determined? Lets investigate the caloric content of a popular snack food, Cheetos.

17 17 Lab Setup Safety Precautions Wear Goggles Tie back loose hair and sleeves No phone cords or headphones in lab No eating

18 18 Ticket Out the Door

19 19 Hint for #7 1 gram of water has a volume of 1 mL.

20 20 Specific Heat Practice WS Part 2 1)0.46 J/gC or 460 J/kgC 2)0.14 J/gC or 140 J/kgC 3)32 o C 4)0.131 J/gC or 131 J/kgC 5)1540 g 6)7600 J 7)14000 J

21 21 HOMEWORK Complete the back Due tomorrow

22 22 Friday March 14, 2014 Define specific heat. The amount of energy required to raise 1 kg of a substance by 1 Kelvin. Put your vocabulary in the tray at this time!

23 23 Specific Heat The amount of heat required to raise the temperature of 1 gram (or 1 kg) of a substance by 1 K (or o C)

24 24 All are units of heat energy. 1 calorie = 4.184 Joules –Specific heat of water in calories: 1.00 cal/gC 1 food Calorie = 1000 calories Lab Setup: Use about 20 mL of water

25 25 Please sit according to your lab station from Friday. Stations 1 and 2 Stations 5 and 6 Stations 3 and 4

26 26 Monday March 17, 2014 Warmup Question: How are the “joule”, “calorie”, and “Calorie” related? All are units of heat energy. 1 calorie = 4.184 Joules –Specific heat of water in calories: 1.00 cal/gC 1 food Calorie = 1000 calories

27 27 Lab Calculations

28 28 Today Exchange data with the other group. Use your data to make to make the calculations on the back. Turn in. Work on Heat Calculations WS

29 29 Tuesday March 18, 2014 How much energy would be absorbed by 550 g of silver that is heated from 24 o C to 45 o C? (The specific heat of silver is 235 J/kgK) Cheeto lab due at this time!!!

30 30 Heat of Fusion & Heat of Vaporization

31 31 Wednesday February 25, 2015 Last Call: –Cheeto Lab –Heat Calculations WS EQ: How much energy is stored in a cheeto? How are food calories related to heat energy? ANNOUNCEMENTS:

32 32

33 33

34 34

35 35 Thursday February 26, 2015 Review phase change Heat of Fusion/Heat of Vaporization EQ: What is difference between heat of fusion and heat of vaporization? ANNOUNCEMENTS:

36 36 solid liquid gas PHASE CHANGE

37 37

38 PHASE CHANGES Melting Solid to liquid Energy absorbed Freezing liquid to solid Energy released

39 Evaporation or Vaporization Liquid to gas Energy absorbed Condensation Gas to liquid Energy released

40 Sublimation Solid to gas

41 Deposition gas to solid http://www.youtube.com/watch?v=Hsu3JoXN-qU

42 42 A,C,E: temperature changes; phase is constant B,D: temperature is constant; phase changes

43 43 Heat Transfer with Change of State Heat Transfer with Change of State Solid Liquid Heat Transferred = (heat of fusion)(mass) Q = (  H fus )(m)Example: Ice + 334 J/g (heat of fusion) -----> Liquid water

44 44 Heat Transfer with Change of State Heat Transfer with Change of State Liquid Gas Heat Transferred = (heat of vaporization)(mass) Q = (  H vap )(m)Example: Water + 2260 J/g (heat of vaporization) -----> Steam

45 45 Which Q equation?? No Phase Change Phase change Q = mc  Tsolid/liquid: Q = (  H fus )(m) liquid/gas: Q = (  H vap )(m) For water: c = 4.18 J/gC  Hfus = 334 J/g  Hvap = 2260 J/g

46 46 Friday February 26, 2015 Kahoot: Which Q is it? Go over Parts 1 and 2 Complete Part 3 EQ: What is difference between heat of fusion and heat of vaporization? ANNOUNCEMENTS:

47 47

48 48

49 49 Friday February 26, 2015 Kahoot: Which Q is it? Go over Parts 1 and 2 Complete Part 3 EQ: What is difference between heat of fusion and heat of vaporization? ANNOUNCEMENTS:

50 50

51 51 Work Session Complete Heat Calculations WS. Check your answers with the key. Hint: Be sure all of your units are in sync before you solve!

52 52 Q=mc  T Q=  H fus (m) Q=  H vap (m)

53 53 Thursday March 20, 2014 A student uses the Q=mc  T equation to figure out how much heat is gained by a piece of ice as it melts into liquid. Why is this incorrect? The equation Q=mc  T cannot be used for a substance undergoing a phase change, only while it is in one specific phase because temperature does not change in a phase change.

54 54 Which Q equation?? No Phase Change Phase change Q = mc  Tsolid/liquid: Q = (  H fus )(m) liquid/gas: Q = (  H vap )(m) For water: c = 4.186 J/gC;  H fus = 334 J/g;  H vap = 2260 J/g

55 55 Tuesday March 3, 2015 Calculating Total Q Quiz Total Q partner activity EQ: What is difference between heat of fusion and heat of vaporization? ANNOUNCEMENTS:

56 56 Total Heat Calculations How much heat is required to raise 250.0 g of ice at a temperature of -15 o C to room temperature of 21.0 o C ?

57 57 Q=mc  T Q=  H fus (m) Q=  H vap (m)

58 58 HEAT EQUATIONS Q = mc  T Q = (  H fus )(m) Q = (  H vap )(m) For water: c = 4.186 J/gC;  H fus = 334 J/g;  H vap = 2260 J/g For ice: c = 2.06 J/g; For steam (gas): c = 2.02 J/g

59 59 TOTAL Q ASSIGNMENT With your partner: Draw a sketch of the phase change graph and label the START and STOP points for your problems. List the equations you would use to solve each step the problem. Solve the heat for each step. Find the total Q.


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